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Stoichiometry calculation

Step 1 Tablets containing iron(II) fumarate (Fe2+C4H2Oj) and inert binder are mixed with 150 mL of 0.100 M HC1 to dissolve the Fe2+. The solution is filtered to remove insoluble binder. [Pg.16]

Step 2 Iron(II) in the clear liquid is oxidized to iron(IIl) with excess hydrogen peroxide  [Pg.16]

Step 3 Ammonium hydroxide is added to precipitate hydrous iron(Ill) oxide, which is a gel. The gel is filtered and heated in a furnace to convert it into pure solid F G). [Pg.16]

Hydroxide Hydrous irondll) oxide lron(III) oxide [Pg.16]

We now work through some practical laboratory calculations for this analysis. [Pg.16]


Once we know the reaction enthalpy, we can calculate the enthalpy change for any amount, mass, or volume of reactant consumed or product formed. As shown in the following example, we carry out a stoichiometry calculation like those described in Section L but with heat treated as a reactant or a product. [Pg.361]

In 1999 CambridgeSoft released a desktop/personal version of an e-notebook, specifically targeted at medicinal chemistry this incorporated reaction drawing and searching, automatic stoichiometry calculations, and simple procedure write-up using plain text. This system was adopted both by individuals, particularly in the academic community, and by small and mediumsized companies as an alternative to building an in-house hybrid system (Fig. 9.2). [Pg.215]

Smaller companies tend to have fewer concerns around, for example, system scalability, global WAN performance, and complex systems integration. They are rather more driven by the pure functionality of the ELN that is addressing the specific scientific disciplines of interest. Key drivers in this sector of the market have been medicinal chemistry departments, where the obvious benefits of searching existing reactions by substructure and reaction transformations, the ability to automate stoichiometry calculations, the ability to load spectral information, etc. have made for easy adoption and clear and realizable benefits. [Pg.221]

The problem asks for a yield, so we identify this as a yield problem. In addition, we recognize this as a limiting reactant situation because we are given the masses of both starting materials. First, identify the limiting reactant by working with moles and stoichiometric coefficients then carry out standard stoichiometry calculations to determine the theoretical amount that could form. A table of amounts helps organize these calculations. Calculate the percent yield from the theoretical amount and the actual amount formed. [Pg.223]

Tables of amounts are useful in stoichiometry calculations for precipitation reactions. For example, a precipitate of Fe (OH) forms when 50.0 mL of 1.50 M NaOH is mixed with 35.0 mL of 1.00 M FeCl3 solution. We need a balanced chemical equation and amounts in moles to calculate how much precipitate forms. The balanced chemical equation is the net reaction for formation of Fe (OH)3 Fe (ag) + 3 OH (a g) Fe (OH)3 (. )... Tables of amounts are useful in stoichiometry calculations for precipitation reactions. For example, a precipitate of Fe (OH) forms when 50.0 mL of 1.50 M NaOH is mixed with 35.0 mL of 1.00 M FeCl3 solution. We need a balanced chemical equation and amounts in moles to calculate how much precipitate forms. The balanced chemical equation is the net reaction for formation of Fe (OH)3 Fe (ag) + 3 OH (a g) Fe (OH)3 (. )...
From experimentally determined values of the various concentrations, or from the value of a single measured concentration and the reaction stoichiometry, calculate the value of ipiCi) at the times corresponding to these measurements. In some cases it may be necessary to resort to graphical integration to determine (Cf). [Pg.48]

Stoichiometry Calculate reactant and product masses using the balanced equation and molar... [Pg.1]

In order to effectively utilize the stoichiometry of the reaction involved in a titration, both the titrant and the substance titrated need to be measured exactly. The reason is that one is the known quantity, and the other is the unknown quantity in the stoichiometry calculation. The buret is an accurate (if carefully calibrated) and relatively high-precision device because it is long and narrow. If a meniscus is read in a narrow graduated tube, it can be read with higher precision (more significant figures) than in a wider tube. Thus a buret provides the required precise measurement of the titrant. [Pg.67]

The ultimate goal of any titrimetric analysis is to determine the amount of the analyte in a sample. This involves the stoichiometry calculation mentioned in the Work the Data section of the analytical strategy flow chart in Figure 4.1. This amount of analyte is often expressed as a percentage, as it was for the gravimetric analysis examples in Chapter 3. This percentage is calculated via the basic equation for percent used previously for the gravimetric analysis examples ... [Pg.77]

As with gravimetric analysis, the weight of the sample (the denominator in Equation (4.33)) is determined by direct measurement in the laboratory or by weighing by difference. The weight of the analyte in the sample is determined from the titration data via a stoichiometry calculation. As discussed previously, we calculate moles of substance titrated (in this case, the analyte) as in Equation (4.21) ... [Pg.77]

This requires stoichiometry calculations from which the desired results can be derived. Statistics are usually involved. [Pg.152]

In a stoichiometry calculation, the weight of one substance involved in a chemical reaction (reactant or product) is converted to the weight of another substance (reactant or product) appearing in the same reaction. The balanced equation is the basis for the calculation, and the formula weights of the reactant and product involved are needed. In the following general example,... [Pg.497]

A stoichiometry calculation is thus essentially a three-step procedure in which 1) the weight of D is divided by its formula weight to get moles of D, 2) the moles of D are converted to the moles of A by multiplying by the mole ratio a/d, as found in the chemical equation, and 3) the moles of A are converted to grams of A by multiplying by the formula weight of A. [Pg.497]

Before any stoichiometry calculation can be done, you must have a balanced chemical equation ... [Pg.91]

Hence the maximum air feed actual stoichiometry is a function of water vapor partial pressure corresponding to the air exhaust release temperature (pw) and the total pressure on the air cathode exhaust (ptotai)- Figure 2.8 shows the maximum air feed actual stoichiometry calculated from Equation 2.5, using water vapor partial pressure from the CRC Handbook of Chemistry and Physics [D.R. Lide (ed.), 72nd edn, 1991-92], as a function of air cathode exhaust release temperature. [Pg.57]

Here are some examples to illustrate stoichiometry calculations in volumetric analysis. The key step is to relate moles of titrant to moles of analyte. We also introduce the Kjeldahl titration as a representative volumetric procedure. [Pg.123]

As we ve seen, stoichiometry calculations for chemical reactions always require working in moles. Thus, the most generally useful means of expressing a solution s concentration is molarity (M), the number of moles of a substance (the solute) dissolved in each liter of solution. For example, a solution made by dissolving 1.00 mol (58.5 g) of NaCl in enough water to give 1.00 L of solution has a concentration of 1.00 mol/L, or 1.00 M. The molarity of any solution is found by dividing the number of moles of solute by the number of liters of solution. [Pg.91]

FIGURE 3.5 A flow diagram summarizing the use of molarity as a conversion factor between moles and volume in stoichiometry calculations. [Pg.94]

As indicated by the flow diagram in Figure 3.5, using molarity is critical for carrying out stoichiometry calculations on substances in solution. Molarity makes it possible to calculate the volume of one solution needed to react with a given volume of another solution. This sort of calculation is particularly important in acid-base chemistry, as shown in Worked Example 3.14. [Pg.94]

The concentration of a substance in solution is usually expressed as molarity (M), defined as the number of moles of a substance (the solute) dissolved per liter of solution. A solution s molarity acts as a conversion factor between solution volume and number of moles of solute, making it possible to carry out stoichiometry calculations on solutions. Often, chemicals are stored as concentrated aqueous solutions that are diluted before use. When carrying out a dilution, only the volume is changed by adding solvent the amount of solute is unchanged. A solution s exact concentration can often be determined by titration. [Pg.106]

Worked Example 9.6 illustrates another gas stoichiometry calculation. [Pg.353]

The advantages of using molarity are twofold (1) Stoichiometry calculations are simplified because numbers of moles are used rather than mass, and (2) amounts of solution (and therefore of solute) are measured by volume rather than by mass. As a result, titrations are particularly easy (Section 3.10). [Pg.435]

With a known mineral, as determined by electron diffraction or other technique (such as X-ray diffraction), determination of the stoichiometry and structural formula can be a suitable test for analytical precision of thin-film elemental analyses. This simple test follows the practice commonly employed for electron microprobe data in which the accuracy (and completeness) of an analysis is judged by the departure from stoichiometry calculated for a given mineral. Thus, thin-film analyses of olivines, pyroxenes, garnets, feldspars and many other common rock-forming minerals can be examined for internal consistency via a calculation of structural formulae. [Pg.48]

Earlier in this course, you learned how to do stoichiometry calculations. To solve gas stoichiometry problems, you will incorporate the ideal gas law into what you learned previously. The following steps will help you do this. [Pg.504]

In doing stoichiometry calculations, we assume that reactions proceed to completion—that is, until one of the reactants is consumed. Many reactions do proceed essentially to completion. For such reactions it can be assumed that the reactants are quantitatively converted to products and that the amount of limiting reactant that remains is negligible. On the other hand, there are many chemical reactions that stop far short of completion. An example is the dimerization of nitrogen dioxide ... [Pg.190]

Do stoichiometry calculations to determine new concentrations. Assume reaction with H+/OH goes to completion. [Pg.282]

Ammonium fluxes out of sediments have often been calculated based on measured rates of net ecosystem metabolism (NEM based on dissolved O2 uptake or Die release) (Burdige and Zheng, 1998 Hopkinson et al, 2001). In oxic sediments where NTR is likely to play an important role in transformation of NH4+, total DIN rather than the NH4 flux should be more closely related to the stoichiometry of NEM, whereas in anoxic sediments where DNF is important the estimated DIN flux will not equal that predicted by NEM stoichiometry. Calculation of DNF has often been based upon this missing DIN. [Pg.894]

What conversion factor is present in almost all stoichiometry calculations ... [Pg.329]

Molarity M mol solute L solution in solution stoichiometry calculations... [Pg.478]

When chemists are faced with problems that require them to determine the quantity of a substance by mass, they often use a technique called gravimetric analysis. In this technique, a small sample of the material undergoes a reaction with an excess of another reactant. The chosen reaction is one that almost always provides a yield near 100%. If the mass of the product is carefully measured, you can use stoichiometry calculations to determine how much of the reactant of unknown amount was involved in the reaction. Then by comparing the size of the analysis sample with the size of the original material, you can determine exactly how much of the substance is present. [Pg.804]

Based on reaction stoichiometry, calculate the percentage ionic halide in your samples, and the average value for your cobalt(III) coordination compound. [Pg.45]


See other pages where Stoichiometry calculation is mentioned: [Pg.211]    [Pg.497]    [Pg.34]    [Pg.39]    [Pg.16]    [Pg.19]    [Pg.703]    [Pg.418]    [Pg.419]    [Pg.110]    [Pg.329]    [Pg.369]    [Pg.298]    [Pg.450]    [Pg.400]   
See also in sourсe #XX -- [ Pg.20 , Pg.21 , Pg.22 , Pg.23 , Pg.24 ]

See also in sourсe #XX -- [ Pg.211 , Pg.221 ]

See also in sourсe #XX -- [ Pg.119 , Pg.121 ]




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