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Function solution

How are the additional determinants beyond the HF constructed With N electrons and M basis functions, solution of the Roothaan-Hall equations for the RHF case will yield N/2 occupied MOs and M — N/2 unoccupied (virtual) MOs. Except for a minimum basis, there will always be more virtual than occupied MOs. A Slater detemfinant is determined by N/2 spatial MOs multiplied by two spin functions to yield N spinorbitals. By replacing MOs which are occupied in the HF determinant by MOs which are unoccupied, a whole series of determinants may be generated. These can be denoted according to how many occupied HF MOs have been replaced by unoccupied MOs, i.e. Slater determinants which are singly, doubly, triply, quadruply etc. excited relative to the HF determinant, up to a maximum of N excited electrons. These... [Pg.99]

Wave equation => wave function (solution of wave equation, denoted by Greek... [Pg.25]

Fig. 5. The complementary-error-function solution of the simple diffusion equation. Fig. 5. The complementary-error-function solution of the simple diffusion equation.
Murzin, A. G. (1993). OB(oligonucleotide/oligosaccharide binding)-fold common structural and functional solution for non-homologous sequences. EMBO J. 12, 861-867. [Pg.273]

Enghsh = time domain (differential equations, yielding exponential time function solutions)... [Pg.13]

Here, the summation goes over all the individual electron wave functions that are occupied by electrons, so the term inside the summation is the probability that an electron in individual wave function ijx((r) is located at position r. The factor of 2 appears because electrons have spin and the Pauli exclusion principle states that each individual electron wave function can be occupied by two separate electrons provided they have different spins. This is a purely quantum mechanical effect that has no counterpart in classical physics. The point of this discussion is that the electron density, n r), which is a function of only three coordinates, contains a great amount of the information that is actually physically observable from the full wave function solution to the Schrodinger equation, which is a function of 3N coordinates. [Pg.10]

Hydrogen Bond Adsorption- of Mono-functional, Solutes... [Pg.451]

Comparison with eqn. (A.10) of Appendix A, shows that p is the fundamental or Green s function solution of the diffusion equation, eqn. (10). [Pg.122]

Superposition of two displaced step-function initial conditions permits solutions that describe diffusion from an initially localized source into an infinite domain. The two step-function initial conditions in Fig. 4.4 have error-function solutions (Eq. 4.31), and their superposition is a localized source of width Ax. The two step functions are... [Pg.84]

Each step function evolves according to an error-function solution of the type given by Eq. 4.31, and their superposition is... [Pg.85]

For identical initial conditions, the difference between a measured profile and the error-function solution is related to the last (nonlinear) term in Eq. 4.43. When diffusivity is a function of local concentration, the concentration profile tends to be relatively flat at a concentration where D(c) is large and relatively steep where D(c) is small (this is demonstrated in Exercise 4.2). Asymmetry of the diffusion profile in a diffusion couple is an indicator of a concentration-dependent diffusivity. [Pg.86]

The interdiffusivity, D, which measures the interdiffusion between Cu and Zn in the laboratory frame, is a strong function of the concentration of Zn. The curve describing D(czn) is concave upward and roughly parabolic in shape, and D(czn) increases by a factor of about 20 when the Zn content increases from 0 to 30 at. % [8]. Describe how the shape of the diffusion-penetration curve for a diffusion couple made of Cu/Cu-30 at. % Zn is expected to deviate from the symmetric form of the constant diffusivity error-function solution. [Pg.92]

Section 4.2.2 shows how to use the scaling method to obtain the error function solution for the one-dimensional diffusion of a step function in an infinite medium given by Eq. 4.31. The same solution can be obtained by superposing the onedimensional diffusion from a distribution of instantaneous local sources arrayed to simulate the initial step function. The boundary and initial conditions are... [Pg.105]

The solution for a diffusion couple in which two semi-infinite ternary alloys are bonded initially at a planar interface is worked out in Exercise 6.1 by the same basic method. Because each component has step-function initial conditions, the solution is a sum of error-function solutions (see Section 4.2.2). Such diffusion couples are used widely in experimental studies of ternary diffusion. In Fig. 6.2 the diffusion profiles of Ni and Co are shown for a ternary diffusion couple fabricated by bonding together two Fe-Ni-Co alloys of differing compositions. The Ni, which was initially uniform throughout the couple, develops transient concentration gradients. This example of uphill diffusion results from interactions with the other components in the alloy. Coupling of the concentration profiles during diffusion in this ternary case illustrates the complexities that are present in multicomponent diffusion but absent from the binary case. [Pg.139]

Pleshanov (P4) extends the integral heat balance method to bodies symmetric in one, two, or three dimensions, using a quadratic polynomial for the approximate temperature function. Solutions are obtained in terms of modified Bessel functions which agree well with numerical finite-difference calculations. [Pg.131]

If Q atoms per square centimeter are deposited on the semiconductor surface with the boundary conditions C(x, t = 0) = Qh(x) and C(°°, t) = 0 (4), then the distribution of impurities after diflusion for a time t is given by a Gaussian function solution to equation 1 (equation 9). [Pg.278]

Equation (1.33) has been written in a form that motivates the use of a Green s function solution. The term on the righthand side represents the action of the dielectric properties of the material and formally renders this equation inhomogeneous. The Green s function, G (x, x ), is the solution to the following inhomogeneous equation,... [Pg.10]

The Green s function solutions in (1.43), (1.48), and (1.49) will form the starting point for the solution of scattering problems in Chapter 4. [Pg.12]

Equation (4.19) is Laplace s equation and has fundamental solutions in the form of harmonic functions. These functions are of two types growing harmonics, which are appropriate for bounded, interior regions, and decaying harmonics, which apply to unbounded space. These functions are expansions of the Green s function solution to Laplace s equation, G (x) = 1/(4jc x ), and are... [Pg.58]

In this course, we do not need to know how to solve the Schrodinger equation. In fact, after this chapter, we shall not even use the equations in Table 2.1. Just remember that orbitals are mathematical functions - solutions of Equation (2.1) - which are continuous and normalized (i.e. the square of cp is 1 when integrated over all space). [Pg.22]

A specific wave function solution is called an orbital. The different orbitals define different energies and distributions for the different electrons. The name orbital goes back to earlier theories where the electron was thought to orbit the nucleus in the way that planets orbit the sun. It seems to apply more to an electron seen as a particle, and orbitals of electrons thought of as particles and wave functions of electrons thought of as waves are really two different ways of looking at the same thing. Each different orbital has its own individual quantum numbers, , , and mg. [Pg.86]

Figure 4.4 illustrates a radial basis function solution to the hypothetical depression classification problem. The algorithm that implemented the radial basis function application determined that seven cluster sites were needed for this problem. A constant variability term, a2 =. 1, was used for each hidden unit. Shown in the diagram are the two central parameters (because there are two input units) for each of the seven Gaussian functions. [Pg.45]

Figure 4.4 Radial basis function solution to the depression classification problem. Figure 4.4 Radial basis function solution to the depression classification problem.
These equations have the following error function solution [39] ... [Pg.198]


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See also in sourсe #XX -- [ Pg.13 ]




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