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Steady state kinetics equilibrium constants

Examples of such kinetic treatments were provided by work on chiral 1,1,2,2-tetramethylcyclopropane-d630 and rran -l-ethyl-2-methylcyclopropane146 148. At 350.2 °C, the first substrate approached cis, trans equilibrium with rate constant, and suffered loss of optical activity with a rate constant k The /c, /c, ratio was 1.7 130. The second substituted cyclopropane, at 377.2 °C, exhibited kinetic behavior dictated by kf.ka = 2.0 1. Using steady-state kinetic treatments and the most-substituted-bond hypothesis, these rate constant ratios were calculationally transformed into (cyclization) (rotation) ratios of 11 1 and 0.29 1, ratios different by a factor of 38. [Pg.480]

The Henri-Michaelis-Menten Treatment Assumes That the Enzyme-Substrate Complex Is in Equilibrium with Free Enzyme and Substrate Steady-State Kinetic Analysis Assumes That the Concentration of the Enzyme-Substrate Complex Remains Nearly Constant Kinetics of Enzymatic Reactions Involving Two Substrates... [Pg.135]

The steady-state kinetic studies of liver alcohol dehydrogenase (12.5 nM) are performed. The initial rates (v in /rM/rnin) with varying substrate concentrations in both directions (forward for ethanol oxidation and reverse for ethanal reduction) are given below. Evaluate their kinetic parameters and equilibrium constant. [Pg.142]

By using the steady state kinetic equations, it is then possible to express k and k3 as a function of the overall turnover frequency for CO-conversion to hydrocarbons (Nco), the overall turnover frequency for methane formation (NCH ), the probability for chain growth (a), the steady state coverage of the precursor A and the value of the equilibrium constant K. In table I the expressions for the kj and k are given. [Pg.202]

Expressing the steady state kinetics in terms of these parameters, only the Vm parameter, which has units of mass per unit time per unit volume, has units that include time. All other parameters have units of concentration (mass per unit volume). In addition, the eight concentration parameters cannot vary independently. For example we can compute Kbq in terms of the other parameters if the equilibrium constant of the reaction is known ... [Pg.95]

The equilibrium constant for the TIM-catalyzed reaction is 22 in the direction of DHAP for the reactive, nonhydrated forms of DHAP and G3P [8] as a result, steady-state kinetics as well as the fates of substrate- and solvent-derived protons can be studied using either DHAP or G3P as substrate. In a series of landmark papers, Knowles and Albery quantitated the free energy profile for the reaction (Fig. 6.1) [37-42]. These studies utilized protiated, deuteriated, and tritiated forms of both DHAP and G3P in both unlabeled and tritiated water to follow the course of the transferred proton(s) during the course of the reaction. Several important conclusions were reached (i) for protiated substrates, the transition state for binding/release of G3P is the highest point on the energy diagram (ii) for tritiated... [Pg.1119]

According to these expressions, the intensity of the OH emission will decay as a biexponent, the rapid initial phase 72 represents the reaction as it proceeds until the velocity of dissociation and recombination become equal. The slower phase 71 represents the decay when the two populations (< >OH and 0 ) are in equilibrium with each other. The relative amplitudes of the two phases Ar = (a2i — 7i)/(72 7i) and the macroscopic rate constants (71,72) allow one to calculate the rate of all partial reactions. The agreement between rate constants calculated by time-resolved measurements and steady-state kinetics is usually good. In a limiting case, where the rate of recombination is much slower than dissociation pKo > pH >> pK, the amplitude of the slow phase representing recombination will diminish to zero and the emission of the < >OH state will decay in a single exponent curve with a macroscopic rate constant 72 = k + %,nr) k. ... [Pg.10]

In the above kinetic expression, the Arrhenius rate constant, 1, is modified by the two adsorption equilibrium constants of methanol and water during the steady state kinetic studies. During the transient TPRS experiments, however, only the Arrhenius rate constant, kj, is measured since there is no vapor phase methanol or water to be equilibrated. The similar TPRS results for the oxidation of the surface methoxy intermediate to formaldehyde over the different supported vanadia catalysts reveal that all the catalysts possess the same kj. Consequently, the dramatic differences in the steady state TOFs during methanol oxidation over the different supported vanadia catalysts must be associated with the methanol and water equilibrium adsorption constants. Both methanol and water can be viewed as weak acids that will donate a proton to a basic surface site, but methanol is more strongly adsorbed than water on oxide surfeces, K, > [16]. Furthermore, the methanol oxidation TOFs... [Pg.312]

As before, equilibrium equations can thenbe derived for constants Ka and Kb. Thereafter, these equations can be rearranged to give solutions for [ESa] and [ESaSb] that maybe substituted into Equation (8.43) giving us the complete steady state kinetics... [Pg.428]

Analogous expressions for the phenomenological rate constants can be derived that relax the assumptions of steady-state kinetics for the I minima and of local equilibrium in the A and B states (kf ... [Pg.320]

Where MH stands for methyl-hexane and DMP stands for dimethyl-pentane. The isoheptanes do not appear to be at thermodynamic equilibrium, nor are they fixed at some constant composition. Mango argued that it is difficult to explain the relationship between the isoheptanes by a mechanism involving the thermal decomposition of natural products or their respective kerogenous derivatives, and suggested a steady-state kinetics where certain product ratios are necessarily time-invariant. He proposed a catalytic process in which the four isoheptanes are formed pairwise through two cyclopropyl intermediates (Fig. 19). [Pg.417]

By monitoring the first-order decay of [AES] in time, it is possible to determine k + k-. From knowledge of the equilibrium concentrations of enzyme and substrate and the values for and k2 from steady-state kinetic analysis, it is possible to obtain estimates of the individual rate constants. By defining = [Eeq] + [Seq], and a = k -h k-, it is possible to express k- = a — k fi. Substitution of this form of k-i into Km Km = k-i + k2)/k and rearrangement allows for the calculation of ky. [Pg.138]

This observed rate, like the rate of approach to equilibrium or steady state, is faster than any component step. Neglect of this piece of kinetic wisdom has caused frequent erroneous interpretations of reaction mechanisms (see for instance section 5.3) one must remember to distinguish rates from rate constants. [Pg.120]

For most SPR appHcations the dissociation constant is calculated from the Kd = koff/kon proportion. It can also be evaluated from the steady-state phase (equilibrium). This method, however, is apphcable only for kinetically fast interactions. The time required for reaching the equihbrium at a protein concentration equal to JCj can be expressed as l/ko . For an interaction with off =1x10 s it will take approximately 1 h to reach equilibrium. The steady state is reached faster with increased protein concentrations. Using a high protein concentration results, however, in the collection of only a narrow range of Req points, close to saturation (Rmax)- In this situation the Kj is... [Pg.26]

Equations (2.10) and (2.12) are identical except for the substitution of the equilibrium dissociation constant Ks in Equation (2.10) by the kinetic constant Ku in Equation (2.12). This substitution is necessary because in the steady state treatment, rapid equilibrium assumptions no longer holds. A detailed description of the meaning of Ku, in terms of specific rate constants can be found in the texts by Copeland (2000) and Fersht (1999) and elsewhere. For our purposes it suffices to say that while Ku is not a true equilibrium constant, it can nevertheless be viewed as a measure of the relative affinity of the ES encounter complex under steady state conditions. Thus in all of the equations presented in this chapter we must substitute Ku for Ks when dealing with steady state measurements of enzyme reactions. [Pg.37]


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See also in sourсe #XX -- [ Pg.89 ]




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