Glucose molar mass

Glucose, C6H1206, is commonly mixed with water to make intravenous feeding solutions. What would be the vapor pressure of a solution where 60.0 g of glucose (molar mass 180.16 g) is dissolved in 700.0 g HzO at 22°C The vapor pressure of pure water at 22°C is 19.83 mm Hg. 

Calculate the vapor pressure of a solution made by dissolving 218 g of glucose (molar mass = 180.2 g/mol) in 460 mL of water at 30°C. What is the vapor-pressure lowering The vapor pressure of pure water at 30°C is given in Table 5.3 (p. 200). Assume the density of the solution is 1.00 g/mL. 

A solution contains 75.0 g of glucose (molar mass 180.2 g/mol) in 425 g of water. Determine the vapor pressure of water over the solution at 35°C. 

Figure I 6.34 Degree of polymerization distribution molar distribution ( ) with number average degree of polymerization (dp = 140 glucose unimers) mass distribution ( ) with weight average degree of polymerization dp = 1242 glucose unimers.

Insulin is a hormone responsible for the regulation of glucose levels in the blood. An aqueous solution of insulin has an osmotic pressure of 2.5 mm Hg at 25°C. It is prepared by dissolving 0.100 g of insulin in enough water to make 125 mL of solution. What is the molar mass of insulin ... 

Amylopectin is the polymeric component of starch and consists mainly of glucose units joined at the 1,4-positions. Relative molar mass tends to be very high, e.g. between 7 and 70 million. A variety of modified starches are used commercially which are produced by derivatisation to give materials such as ethanoates (acetates), phosphates, and hydroxyalkyl ethers. Modified and unmodified starches are used in approximately equal tonnages, mainly in papermaking, paper coatings, paper adhesives, textile sizes, and food thickeners. 

The proportions, by number of atoms, of C and O are the same in glucose. Since, however, C and O have different molar masses, their proportions by mass must be different. 

Historically, the target analytes in clinical mass spectrometric applications were small, volatile compounds that could be analyzed by GC-MS (see Chapter 4). With time, new chemical preparation techniques and derivatization schemes broadened the scope of these metabolites to include fatty acids, amino acids, intermediates of glucose oxidation, phospholipids, steroids, neurogenic amines, nucleic acids, etc. The molecular weights (molar masses) after derivatization were less than 1000 Da, a mass range easily within the limits of most conventional mass spectrometers. 

Thirdly, we determine the amount of glucose consumed n. We obtain the value of n as amount = mass-E molar mass . The molar mass of glucose is 180 gmol 1, so the number of moles is 5.88 x 10-2 mol. 

To get the final answer, we must divide the energy released by the moles of glucose. We find the moles of glucose from the mass given in the problem and the molar mass determined from the atomic weights of the elements. 

At 25°C, the density of glucose is 1.55 g cnuA, its diffusion coefficient is 6.81 x 10- cm s- and the coefficient of viscosity of water is 8.937 x lO- Poise. Assuming that the glucose molecule is spherical, estimate its molar mass ... 

Figure 6.10 Effect of CITREM on the molecular and thermodynamic parameters of maltodextrin SA-2 (DE = 2) in aqueous medium (phosphate buffer, pH = 7.2, ionic strength = 0.05 M 20 °C) (a) weight average molar mass, Mw (b) radius of gyration, Ra (c) structure sensitive parameter, p, characterizing die architecture of maltodextrin associates (d) second virial coefficient, A2 or A2, on the basis of the weight ( ) and molal (A) scales, respectively. The parameter R is defined as the molar ratio of surfactant to glucose monomer units in the polysaccharide. The indicated cmc value refers to the cmc of the pure CITREM solution. Reproduced from Anokhina et al. (2007) with permission.

An oligopeptide of relative molar mass 1600 that binds Fem and functions to enhance the cellular uptake of Fe has been isolated from mouse cells.51 The peptide also binds Co11 but does not enhance the uptake of this metal. The peptide has been referred to as the siderophore-like growth factor (SGF). There is also a proposed Cr-chelating peptide this glucose tolerant factor is essential for the utilization of Cr in the proper functioning of insulin in cells.72 Whilst Zn11 is normally associated... 

The porous nature of the fibers allows for exchange of nutrients and metabolites. Low-molar-mass molecules, such as glucose and ammonia, can move freely through the pores of the fibers, at a rate that is controlled just by the pressure gradients generated by the medium recirculation pump. High-molar-mass proteins, which can be produced by the cells or added as nutritional supplements to the extracapillary space, are not able to permeate the membrane fibers and are retained in the cell bed in the ECS. 

Sample A solution is made by placing 220.0 g of glucose (C6H1206, molar mass = 180.16 g) in a volumetric flask and adding distilled water to equal 1.00 L of solution. Calculate the osmotic pressure at 25°C. Glucose is a nonelectrolyte. 

Which compound releases more energy per gram a fat (assume oleic acid, C17H33COOHM), a carbohydrate such as sugar (assume glucose, C6Hi206(S)>, or a protein (assume collagen, molar mass 300 000 g/mol) ... 

How many grams of glucose (C6Ht206), C= 12, H= 1, 0=16, Molar mass = 180) will it take to make the following solutions ... 

A solution was prepared by dissolving 18.00 g of glucose in 150.0 g of water. The resulting solution was found to have a boiling point of 100.34°C at 1 atm. Calculate the molar mass of glucose. Glucose is a molecular solid that is present as individual molecules in solution. 

Determine the molar mass of the following glucose, C6H12O6. 

A 100.5-mL intravenous (IV) solution contains 5.10 g of glucose (C5H12O6). What is the molarity of this solution The molar mass of glucose is 180.16 g/mol. 

The second order rate constant of the initial reaction between the HO radicals and HA is about one order of magnitude (k 7 x 10 1 mof s ) smaller in comparison to that of the reaction with glucose [179]. This is most probably caused by the considerable viscosity of solutions of high molar mass HA. 

The molar mass of glueose is 180.15 g mol". From this, we ean ealculate the number of moles of glucose formed and, using the reaction stoichiometry, determine the number of moles of CO2 needed. With that information and the other information provided in the problem, we ean use the ideal gas law to ealculate the volume of air that is needed ... 

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