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Boiling point pressure

A relief valve will not usually handle the vapor generated because its set pressure is usually higher than the boiling point pressure created by the hole or crack in the vessel therefore, it will not relieve at the lower pressure. [Pg.504]

The effect of superheated steam may be illustrated by reference to baizaldehyde, which boils at 178° at 760 mm. It distils with steam at 97 9° (Pj, = 703-5 mm. andpo = 56-5 mm.) and the distillate contains 32 1 per cent, of benzaldehyde by weight. If one employs steam superheated to 133°, the vapour pressure of benzaldehyde (extrapolated from the boiling point - pressure curve) is 220 mm. hence p = 540 (water), Pb = 220 (benzaldehyde), and... [Pg.25]

To show you how to use the Clausius - Clapyron equation, and to show you how well the equation fits over small temperature ranges. The calculated boiling point pressure for isobutyl alcohol (760.04 torr) is not very different from the normal boiling point pressure of 760.00 torr (0.005%). [Pg.293]

The boiling-point pressure of the water is equal to 30 psig that is, we can assume that the water draw-off is at its bubble-point pressure. At 36 psig pump suction pressure, the available NPSH is then... [Pg.334]

Molecular Boiling point pressure (psig) Density weight (°C) at21.1°C (g/ml)... [Pg.371]

Figure 1. du Font 900 differential thermal analyzer for determining boiling point-pressure curves... [Pg.50]

Compound Boiling Point/Pressure Yield (%) Calc. Found Calc. Found... [Pg.744]

Pressure Boiling Point Pressure Boiling Point... [Pg.59]

P029 Initial Boiling Point Pressure BP PRESS N 13 kPa abs... [Pg.37]

All of the information presented so far in this chapter is practically independent of the system pressure, as long as the pressure is above the boiling-point pressure of the mixture. The reason, as shown in Chapter 7, is that change in fugacity with pressure is given by Eqs. 7.6 and 7.14, which show that... [Pg.190]

Example 9.1 A process involves the use of benzene as a liquid under pressure. The temperature can be varied over a range. Compare the fire and explosion hazards of operating with a liquid process inventory of 1000 kmol at 100 and 150°C based on the theoretical combustion energy resulting from catastrophic failure of the equipment. The normal boiling point of benzene is 80°C, the latent heat of vaporization is 31,000 kJ kmol the specific heat capacity is 150 kJkmoh °C , and the heat of combustion is 3.2 x 10 kJkmok. ... [Pg.269]

One of the principal approaches to making a process inherently safe is to limit the inventory of hazardous materials. The inventories to avoid most of all are flashing flammable or toxic liquids, i.e., liquids under pressure above their atmospheric boiling points. [Pg.271]

Raoult s law When a solute is dissolved in a solvent, the vapour pressure of the latter is lowered proportionally to the mole fraction of solute present. Since the lowering of vapour pressure causes an elevation of the boiling point and a depression of the freezing point, Raoult s law also applies and leads to the conclusion that the elevation of boiling point or depression of freezing point is proportional to the weight of the solute and inversely proportional to its molecular weight. Raoult s law is strictly only applicable to ideal solutions since it assumes that there is no chemical interaction between the solute and solvent molecules. [Pg.341]

Recently, chromatographs and their associated columns have been able to elute components with boiling points up to 700°C under atmospheric pressure. [Pg.24]

When the boiling point is measured at a pressure other than normal atmospheric, the normal boiling point can be calculated by a method described in article 4.1.3.4. [Pg.93]

In practice, however, it is recommended to adjust the coefficient m, in order to obtain either the experimental vapor pressure curve or the normal boiling point. The function f T ) proposed by Soave can be improved if accurate experimental values for vapor pressure are available or if it is desired that the Soave equation produce values estimated by another correlation. [Pg.156]

At low temperatures, using the original function/(T ) could lead to greater error. In Tables 4.11 and 4.12, the results obtained by the Soave method are compared with fitted curves published by the DIPPR for hexane and hexadecane. Note that the differences are less than 5% between the normal boiling point and the critical point but that they are greater at low temperature. The original form of the Soave equation should be used with caution when the vapor pressure of the components is less than 0.1 bar. In these conditions, it leads to underestimating the values for equilibrium coefficients for these components. [Pg.157]

Maxwell and Bonnel (1955) proposed a method to calculate the vapor pressure of pure hydrocarbons or petroleum fractions whose normal boiling point and specific gravity are known. It is iterative if the boiling point is greater than 366.5 K ... [Pg.159]

This method is applicable to heavy fractions whose boiling point is greater than 200°C. The average error is around 10% for pressures between 0.001 and 10 bar. ... [Pg.160]

Normal boiling point K Standard specific gravity Molecular weight kg/lunol Liquid viscosity at 100°F mm /s Liquid viscosity at 2iO F mm /s Critical temperature K Critical pressure bar... [Pg.416]

Beyond propane, it is possible to arrange the carbon atoms in branched chains while maintaining the same number of hydrogen atoms. These alternative arrangements are called isomers, and display slightly different physical properties (e.g. boiling point, density, critical temperature and pressure). Some examples are shown below ... [Pg.91]

The quantity zoi will depend very much on whether adsorption sites are close enough for neighboring adsorbate molecules to develop their normal van der Waals attraction if, for example, zu is taken to be about one-fourth of the energy of vaporization [16], would be 2.5 for a liquid obeying Trouton s rule and at its normal boiling point. The critical pressure P, that is, the pressure corresponding to 0 = 0.5 with 0 = 4, will depend on both Q and T. A way of expressing this follows, with the use of the definitions of Eqs. XVII-42 and XVII-43 [17] ... [Pg.614]


See other pages where Boiling point pressure is mentioned: [Pg.131]    [Pg.250]    [Pg.1303]    [Pg.189]    [Pg.272]    [Pg.274]    [Pg.161]    [Pg.131]    [Pg.250]    [Pg.1303]    [Pg.189]    [Pg.272]    [Pg.274]    [Pg.161]    [Pg.43]    [Pg.256]    [Pg.257]    [Pg.260]    [Pg.62]    [Pg.62]    [Pg.106]    [Pg.98]    [Pg.606]   
See also in sourсe #XX -- [ Pg.106 , Pg.200 ]




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