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Strains simple shear

Martensitic transformations involve a shape deformation that is an invariant-plane strain (simple shear plus a strain normal to the plane of shear). The elastic coherency-strain energy associated with the shape change is often minimized if the martensite forms as thin plates lying in the plane of shear. Such a morphology can be approximated by an oblate spheroid with semiaxes (r, r, c), with r c. The volume V and surface area S for an oblate spheroid are given by the relations... [Pg.487]

From his detailed analysis, Cheng concludes that it cannot always be said that extensional flows are more effective for mixing purposes than simple shear flow. Care is needed, particularly for flows involving non-Newtonian liquids. The position is rather complicated and Cheng states that at small strains, extensional flows are on the whole more effective than simple shear, but only marginally so, at sufficiently large strains extensional flows are very much more effective. However, at some intermediate strains simple shear may be more effective particularly when the fluid is non-Newtonian. [Pg.212]

Non-Newtonian Fluids Die Swell and Melt Fracture. Eor many fluids the Newtonian constitutive relation involving only a single, constant viscosity is inappHcable. Either stress depends in a more complex way on strain, or variables other than the instantaneous rate of strain must be taken into account. Such fluids are known coUectively as non-Newtonian and are usually subdivided further on the basis of behavior in simple shear flow. [Pg.95]

A sliding plate rheometer (simple shear) can be used to study the response of polymeric Hquids to extension-like deformations involving larger strains and strain rates than can be employed in most uniaxial extensional measurements (56,200—204). The technique requires knowledge of both shear stress and the first normal stress difference, N- (7), but has considerable potential for characteri2ing extensional behavior under conditions closely related to those in industrial processes. [Pg.192]

In this case, the shear stress is linear in the shear strain. While more physically reasonable, this is not likely to provide a satisfactory representation for the large deformation shear response of many materials either, since most materials may be expected to stiffen with deformation. Note that the hypoelastic equation of grade zero (5.117) is not invariant to the choice of indifferent stress rate, the predicted response for simple shear depending on the choice which is made. [Pg.151]

A number of other indifferent stress rates have been used to obtain solutions to the simple shear problem, each of which provides a different shear stress-shear strain response which has no latitude, apart from the constant Lame coefficient /r, for representing nonlinearities in the response of various materials. These different solutions have prompted a discussion in the literature regarding which indifferent stress rate is the correct one to use for large deformations. [Pg.151]

Depending on the relative velocity in opposite pairs of the rollers, flow can be either purely rotational (X = — 1), simple shear (X = 0) or hyperbolic straining (X = 1, shown on this figure)... [Pg.113]

The above description refers to a Lagrangian frame of reference in which the movement of the particle is followed along its trajectory. Instead of having a steady flow, it is possible to modulate the flow, for example sinusoidally as a function of time. At sufficiently high frequency, the molecular coil deformation will be dephased from the strain rate and the flow becomes transient even with a stagnant flow geometry. Oscillatory flow birefringence has been measured in simple shear and corresponds to some kind of frequency analysis of the flow... [Pg.114]

We conclude that high internal stresses are generated by simple shear of a long incompressible rectangular rubber block, if the end surfaces are stress-free. These internal stresses are due to restraints at the bonded plates. One consequence is that a high hydrostatic tension may be set up in the interior of the sheared block. For example, at an imposed shear strain of 3, the negative pressure in the interior is predicted to be about three times the shear modulus p. This is sufficiently high to cause internal fracture in a soft rubbery solid [5]. [Pg.5]

Thus, only the normal Reynolds stresses (i = j) are directly dissipated in a high-Reynolds-number turbulent flow. The shear stresses (i / j), on the other hand, are dissipated indirectly, i.e., the pressure-rate-of-strain tensor first transfers their energy to the normal stresses, where it can be dissipated directly. Without this redistribution of energy, the shear stresses would grow unbounded in a simple shear flow due to the unbalanced production term Vu given by (2.108). This fact is just one illustration of the key role played by 7 ., -in the Reynolds stress balance equation. [Pg.69]

Figures 1.2 and 1.3 show how, if we apply a simple shear strain, y, in our... Figures 1.2 and 1.3 show how, if we apply a simple shear strain, y, in our...
We now use this to calculate the stress in the melt after the retraction has occurred. The deformation is described by the tensor E defined so that an arbitrary vector V in the material is deformed affinely into the vector E.v. For example, in simple shear of shear strain 7, and in uniaxial extension of strain e, the tensor E takes the forms... [Pg.240]

In the two classic viscometric deformations of simple shear and extension, the appropriate components of Q have very different behaviour. For small shear strains, the shear stress depends on the component Q which has the linear asymptotic form 47/15. This prefactor is the origin of tne constant v in the tube potential of Sect. 3.For large strains, however, Qxy 7 and therefore predicts strong shear-thinning. Physically this comes from the entanglement loss on re-... [Pg.240]

Note 5 The Finger strain tensor for simple shear flow is... [Pg.156]

PP bead foams were subjected to oblique impacts (167), in which the material was compressed and sheared. This strain combination could occur when a cycle helmet hit a road surface. The results were compared with simple shear tests at low strain rates and to uniaxial compressive tests at impact strain rates. The observed shear hardening was greatest when there was no imposed density increase and practically zero when the angle of impact was less than 15 degrees. The shear hardening appeared to be a unique function of the main tensile extension ratio and was a polymer contribution, whereas the volumetric hardening was due to the isothermal compression of the cell gas. Eoam material models for FEA needed to be reformulated to consider the physics of the hardening mechanisms, so their... [Pg.18]

Tanner,R.I., Williams,G. On the orthogonal superposition of simple shearing and small-strain oscillatory motions. Rheol. Acta 10, 528-538 (1971). [Pg.178]

An invariant-plane strain consists of a simple shear on a plane, plus a normal strain perpendicular to the plane of shear (see Section 24.1 and Fig. 24.1). This is a combination of Cases 2 and 3. The expression for Ags then follows directly from Eqs. 19.26 and 19.27, with the result that Age is proportional to c/a. Age is therefore minimized for a disc-shaped inclusion lying in the plane of shear. [Pg.472]

Data can be obtained from tests in uniaxial tension, uniaxial compression, equibiaxial tension, pure shear and simple shear. Relevant test methods are described in subsequent sections. In principle, the coefficients for a model can be obtained from a single test, for example uniaxial tension. However, the coefficients are not fully independent and more than one set of values can be found to describe the tension stress strain curve. A difficulty will arise if these coefficients are applied to another mode of deformation, for example shear or compression, because the different sets of values may not be equivalent in these cases. To obtain more robust coefficients it is necessary to carry out tests using more than one geometry and to combine the data to optimize the coefficients. [Pg.117]

The stress/strain curve in simple shear is approximately linear up to relatively large strains and can be represented by ... [Pg.155]

The results of dynamic tests are dependent on the test conditions test piece shape, mode of deformation, strain amplitude, strain history, frequency and temperature. ISO 4664 gives a good summary of basic factors affecting the choice of test method. Forced vibration, non-resonant tests in simple shear using a sinusoidal waveform are generally preferred for design data as... [Pg.178]

A publication by B. Colleman, H. Markwitz and W. Noll27 describes in detail the theory of viscosimetric flows which was further used by a number of investigators (see, for example, 23,24,28-29) to analyze axial flow in a clearance between motionless and rotating cylinders. The authors of 27,30) have demonstrated theoretically that the spiral flow can be considered as a mutual overlapping (superimposing) of two strains occurring in a simple shear (see Sect. 1.2). [Pg.46]

The theory of viscosimetric flows, as mentioned above, permits the consideration of a spiral flow (Fig. 1) as a superimposition of two simple-shear strains. This approach... [Pg.46]

The use of a rotating vane has become very popular as a simple to use technique that allows slip to be overcome (33,34). Alderman et al (35) used the vane method to determine the yield stress, yield strain and shear modulus of bentonite gels. In the latter work it is interesting to note that a typical toique/time plot exhibits a maximum torque (related to yield stress of the sample) after which the torque is observed to decrease with time. The fall in torque beyond the maximum point was described loosely as being a transition from a gel-like to a fluid-like behavior. However, it may also be caused by the development of a slip surface within the bulk material. Indeed, by the use of the marker line technique, Plucinski et al (15) found that in parallel plate fixtures and in slow steady shear motion, the onset of slip in mayonnaises coincided with the onset of decrease in torque (Fig. 8). These authors found slip to be present for... [Pg.289]

The Relationship between Shear Rate and Strain Show that (dvx/dy) in a simple shear flow is identical to —(dy/dt), where y is the angle shown in the accompanying figure. [Pg.75]


See other pages where Strains simple shear is mentioned: [Pg.79]    [Pg.152]    [Pg.57]    [Pg.73]    [Pg.78]    [Pg.150]    [Pg.5]    [Pg.122]    [Pg.64]    [Pg.76]    [Pg.163]    [Pg.164]    [Pg.164]    [Pg.181]    [Pg.182]    [Pg.233]    [Pg.112]    [Pg.117]    [Pg.154]    [Pg.194]    [Pg.34]    [Pg.78]    [Pg.147]    [Pg.198]   
See also in sourсe #XX -- [ Pg.168 ]




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Shear strains

Shearing strain

Simple shear

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