N-Hexyl formate

Methyl formate Ethyl formate. n-Propyl formate iso-Propyl formate. n-Butyl formate iso-Butyl formate sec.-Butyl formate. tert.-Butyl formate. n-Amyl-formate iso-Amyl formate n-Hexyl formate cycfoPentyl formate. cycioHexyl formate Allyl formate. ... 

Fig. 5.14 Plot of the interfacial area per unit volume against the agitator speed for the reactor shown in Fig. 5.12 for the reactive pair, n-hexyl formate and 1 M aqueous NaOH.

Synonyms Formic acid, hexyl ester n-Hexyl formate... 

Dicobaltoctacarbonyl at concentrations about 10-3 M was an excellent catalyst (lib) for hydrosilation of 1-hexene by common silanes, including (MeO)3SiH, Et3SiH, and PhCl2SiH, to give exclusively n-hexyl silanes. The only observable side reaction was formation of hexene-2 and hexene-... 

In a thorough study of the effect of reactant ratio, initiator concentration, temperature and time of reaction, it was found that the optimal reaction conditions for 1 1 adduct formation in the reaction of perfluoro-n-hexyl iodide to vinyl acetate are [210] ... 

From adamantan-l-ol and acetylene in 90% H2S04 Kell and McQuillin (1969) obtained exclusively the aldehyde 26 and ketone 27. Addition to substituted adamantyl acetylenes, AdC=CR (R==Ph, n-Pr, n-Hexyl) resulted in the formation of ketones AdCH2COR. 

Maccoll et have pointed out that along the series of primary bromides (n-propyl, n-butyl, n-pentyl, n-hexyl) the chain component of the overall thermal decomposition undergoes a steady decrease relative to the unimolecular component of the decomposition. This has been attributed to the increased probability of formation of -radicals with increase in the length of the carbon chain in the molecule. The decomposition of secondary monobromides is mainly unimolecular with only a slight radical-chain component. Tertiary monobromides decompose uni-molecularly. 

There is good regioselectivity with unsymmetrical alkynes, e.g. 1-heptyne 105 R = n-pentyl forms the 2-substituted cyclopentenone 106 in excellent yield26 but unsymmetrical alkenes give much poorer selectivity, e.g. 1-octene gives 21% each of the cyclopentenones 108 and 109 R1 = n-pentyl R2 = n-hexyl.27 It must be admitted that this combined yield of 40-50% yield is more typical than the 80-85% of 106, but this can be forgiven in a three-component reaction that accomplishes so much. In the formation of the first o-bond a substituent on the alkyne evidently prefers the blobby position in 102 while substituents on the alkene are indifferent about remaining on the atom joined to cobalt. 

The formation of radical R" explains the lack of stereoselectivity in formation of RMgX (X = Cl, Br) from anti- and syn-7-halogenobenzonorbornadiene, but delds vary ( 95 % from anti-RX 32-36 % from syn) . This method also may be applied when R = n-hexyl (85 %) and R = norborn-2-en-7-yl (yield of syn -l- anti RMgX is > 19 %) . A solution of NaCioHg in THF is added dropwise to RX and MgX2 (X = Cl, Br) in THF, and at the end point of the reaction the deep-green color of NaCigHg persists . ... 

The occurrence of energy transfer has been confirmed by preliminary determinations of the yield of hydrocarbon products formed (15). The dependence of the yields of various products on the amount of n-hexane shows a rapid increase at low hydrocarbon electron fractions. The curves then flatten out demonstrating that the active sites on the silica gel surface have been used up. There is a difference in saturation behavior for various hydrocarbon products the combination of two n-hexyl radicals to form n-dodecane indicates a saturation at an electron fraction of 0.05, whereas the formation of 5-methylundecane from n-hexyl and 2-hexyl radicals reaches saturation first at the electron fraction of 0.2. The same general behavior is observed also for Ci0, C9, and C8 products. 

Figure 3. Correlation between the initial velocities of the papain-catalyzed aminolysis of ethyl hippurate by amino add esters (abscissa) and the initial velocities (extent after 2 hr) of their incorporation during the plastein formation from an ovalbumin hydrolysate by papain (ordinate). Open circles ethyl esters. Filled drcles n-hexyl esters. Unusual abbreviations Abu = a-aminobutyric acid, Nva = norvaline.

A sodium fusion test would first be performed on the unknown, breaking it down into its components, and then the unknown would be acidified, mixed with carbon tetrachloride, and shaken with Cl2. A purple color would be indicative of I2/ which would indicate n-hexyl iodide as the unknown. If no purple color is observed, we would add AgNOa. The formation of a white precipitate (AgCl) would point to benzyl chloride as the unknown. 

---