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Hybridization sp3 orbitals

Sandorfy was struck by the artificial character of this approximation. His first target was the series of normal chain saturated hydrocarbons. A preliminary note on his results was published in the Comptes Rendus de VAcademie des Sciences.6 After taking up his position in Montreal, he greatly extended this work by introducing three different approximations, which he called the C CH, and H approximations.7 The first was based only on the atomic orbitals of the carbons, the second used the hybrid sp3 orbitals of the carbons and the Is orbitals of the hydrogens, and the third included all the valence atomic orbitals of the carbons and the hydrogens. [Pg.217]

The asymmetry of sp3 orbitals arises because, as noted previously, the two lobes of a p orbital have different algebraic signs, + and -. Thus, when a p orbital hybridizes with an s orbital, the positive p lobe adds to the s orbital but the negative p lobe subtracts from the s orbital. The resultant hybrid orbital is therefore unsymmetrical about the nucleus and is strongly oriented in one direction. [Pg.13]

What accounts for the stability of conjugated dienes According to valence bond theory (Sections 1.5 and 1.8), the stability is due to orbital hybridization. Typical C—C bonds like those in alkanes result from a overlap of 5p3 orbitals on both carbons. In a conjugated diene, however, the central C—C bond results from conjugated diene results in part from the greater amount of s character in the orbitals forming the C-C bond. [Pg.485]

The beautiful Bohr atomic model is, unfortunately, too simple. The electrons do not follow predetermined orbits. Only population probabilities can be given, which are categorized as shells and orbitals. The orbitals can only accommodate two electrons. Shells and orbitals can also merge ("hybridization"). In the case of carbon, the 2s orbital and the three 2p orbitals adopt a configuration in the shape of a tetrahedron. Each of these sp3 orbitals is occupied by one electron. This gives rise to the sterically directed four-bonding ability of carbon. [Pg.112]

A carbon atom combining with four other atoms clearly does not use the one 2s and the three 2p atomic orbitals that would now be available, for this would lead to the formation of three directed bonds, mutually at right angles (with the three 2p orbitals), and one different, non-directed bond (with the spherical 2s orbital). Whereas in fact, the four C—H bonds in, for example, methane are known to be identical and symmetrically (tetrahedrally) disposed at an angle of 109° 28 to each other. This may be accounted for on the basis of redeploying the 2s and the three 2p atomic orbitals so as to yield four new (identical) orbitals, which are capable of forming stronger bonds (cf. p. 5). These new orbitals are known as sp3 hybrid atomic orbitals, and the process by which they are obtained as hybridisation ... [Pg.4]

The four sp3 orbitals should be oriented at angles of 109.5° with respect to each other => an sp -hybridized carbon gives a tetrahedral structure for methane. [Pg.32]

Although we have described the structures of several molecules in terms of hybrid orbitals and VSEPR, not all structures are this simple. The structures of H20 (bond angle 104.4°) and NH3 (bond angles 107.1°) were described in terms of sp3 hybridization of orbitals on the central atom and comparatively small deviations from the ideal bond angle of 109° 28 caused by the effects of unshared pairs of electrons. If we consider the structures of H2S and PH3 in those terms, we have a problem. The reason is that the bond angle for H2S is 92.3°, and the bond angles in PH3 are 93.7°. Clearly, there is more than a minor deviation from the expected tetrahedral bond angle of 109° 28 caused by the effect of unshared pairs of electrons ... [Pg.104]

Carbon atoms (1) and (2) undergo sp2 hybridization, while carbon atoms (3), (4) and (5) undergo sp3 hybridization. The orbital overlaps are similar to those in 2-butene except carbon atoms (1) and (2) are involved in the double bond and carbon atom (2) is bonded to carbon atom (3) by sp2-sp3 overlap. The overlap of the hybrid orbitals with the Is orbitals of H atoms gives the C-H bonds. [Pg.389]

The left-most C atom (in the structure drawn below) is sp3 hybridized, and the C-H bonds to that C atom are between the sp3 orbitals on C and the Is orbital on H. The other two C atoms are sp hybridized. The right-hand C-H bond is between the sp orbital on C and the Is orbital on H. The c a C triple bond is composed of one sigma bond formed by overlap of sp orbitals, one from each C atom, and two pi bonds, each formed by the overlap of two 2p orbitals, one from each C atom (that is a 2py—2py overlap and a 2pz—2pz overlap). [Pg.631]

Both sand and silt surfaces are dominated by oxygen and its lone pairs of electrons in p orbitals. In some instances, broken surfaces may also have silicon-hybridized sp3 orbitals4 available for bonding. Comparison of sand, silt, and clay reveals the surface area of sand and silt to be low and the interaction between surface bonding orbitals and components in the surrounding medium relatively weak. [Pg.75]

In some atoms, the p and s orbitals are mixed together to form several equivalent, hybridized orbitals. The most common example is carbon, where there are four orbitals that are formed by mixing one s orbital with three p orbitals to give four equivalent orbitals designated as sp3 orbitals. [Pg.76]

In this case since carbon has only two unpaired electrons, it seems likely that it will only form only two covalent bonds, but it is known that carbon can form four covalent bonds. To form four bonds, one electron is promoted from the 2s orbital to the 2pz orbital. Then the one 2s orbital and three 2p orbitals mix together to form four new sp3 hybrid orbitals as shown in Figure 5. So in this case of hybridization, three p and one s orbital combine to give four identical sp3 orbitals. [Pg.25]

The carbon atom (6C) has the electron configuration of ls22s22p2. There are 4 valence electrons, of which only two are unpaired in the ground state. During the formation of carbon compounds, one 2s and three 2p orbitals combine to give four identical sp3 orbitals by the promotion of an electron from the 2s orbital to a 2p orbital. These 4 unpaired orbitals then mix to form four identical sp3 hybrid orbitals. [Pg.30]


See other pages where Hybridization sp3 orbitals is mentioned: [Pg.232]    [Pg.41]    [Pg.441]    [Pg.441]    [Pg.500]    [Pg.16]    [Pg.1322]    [Pg.232]    [Pg.41]    [Pg.441]    [Pg.441]    [Pg.500]    [Pg.16]    [Pg.1322]    [Pg.175]    [Pg.19]    [Pg.949]    [Pg.187]    [Pg.53]    [Pg.12]    [Pg.229]    [Pg.229]    [Pg.329]    [Pg.768]    [Pg.806]    [Pg.68]    [Pg.73]    [Pg.195]    [Pg.6]    [Pg.10]    [Pg.273]    [Pg.66]    [Pg.400]    [Pg.526]    [Pg.402]    [Pg.576]    [Pg.22]    [Pg.270]    [Pg.249]    [Pg.264]    [Pg.19]    [Pg.63]    [Pg.71]    [Pg.314]    [Pg.166]   
See also in sourсe #XX -- [ Pg.391 , Pg.392 ]




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