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Equivalent evaporation

Equivalent evaporation The evaporation that takes place in a boiler at or above 100 C. [Pg.1435]

Column, gas chromatograph FlP-5, 5% phenyl-methyl capillary column, 0.25-mm i.d. X 12-m length, 0.33-qm film thickness (Agilent Technologies) or equivalent Evaporator, rotary vacuum, water-bath set at 60 and 40 °C Processors ... [Pg.1283]

Experiments with butane droplets [1] yielded estimates of 7 m/s for the equivalent evaporation wave velocity and an estimated density of 200 kg/m for the density of... [Pg.12]

Add 4 0 g. (4 0 ml.) of pure anihne dropwise to a cold solution of ethyl magnesium bromide (or iodide) prepared from 1 Og. of magnesium, 5 0 g. (3-5 ml.) of ethyl bromide (or the equivalent quantity of ethyl iodide), and 30 ml. of pure, sodium-dried ether. When the vigorous evolution of ethane has ceased, introduce 0 02 mol of the ester in 10 ml. of anhydrous ether, and warm the mixture on a water bath for 10 minutes cool. Add dilute hydrochloric acid to dissolve the magnesium compounds and excess of aniline. Separate the ethereal layer, dry it with anhydrous magnesium sulphate and evaporate the ether. Recrystallise the residual anihde, which is obtained in almost quantitative yield, from dilute alcohol or other suitable solvent. [Pg.394]

In a typical experiment 105 mg (0.50 mmol) of 3.8c, dissolved in a minimal amount of ethanol, and 100 mg (1.50 mmol) of 3.9 were added to a solution of 1.21g (5 mmol) of Cu(N03)2 BH20 and 5 mmol of ligand in 500 ml of water in a 500 ml flask. -Amino-acid containing solutions required addition of one equivalent of sodium hydroxide. When necessary, the pH was adjusted to a value of 5 ( -amino acids) and 7.5 (amines). The flask was sealed carefully and the solution was stirred for 2A hours, followed by extraction with ether. After drying over sodium sulfate the ether was evaporated. Tire endo-exo ratios were determined from the H-NMR spectra of the product mixtures as described in Chapter 2. [Pg.103]

The successful application of an external standardization or the method of standard additions, depends on the analyst s ability to handle samples and standards repro-ducibly. When a procedure cannot be controlled to the extent that all samples and standards are treated equally, the accuracy and precision of the standardization may suffer. For example, if an analyte is present in a volatile solvent, its concentration will increase if some solvent is lost to evaporation. Suppose that you have a sample and a standard with identical concentrations of analyte and identical signals. If both experience the same loss of solvent their concentrations of analyte and signals will continue to be identical. In effect, we can ignore changes in concentration due to evaporation provided that the samples and standards experience an equivalent loss of solvent. If an identical standard and sample experience different losses of solvent. [Pg.115]

Pish silage prepared by autolysis of rainbow trout viscera waste was investigated as a substrate for the plastein reaction using pepsin (pH 5.0), papain (pH 6—7), and chymotrypsin (pH 8.0) at 37°C for 24 h (152). Precipitation with ethanol was the preferred recovery method. Concentration of the protein hydrolysate by open-pan evaporation at 60°C gave equivalent yields and color of the final plastein to those of the freeze-dried hydrolysate. [Pg.471]

The most convenient mathematical method of describing pervaporation is to divide the overall separation processes into two steps, as shown in Figure 40. The first is evaporation of the feed Hquid to form a (hypothetical) saturated vapor phase on the feed side of the membrane. The second is permeation of this vapor through the membrane to the low pressure permeate side of the membrane. Although no evaporation actually takes place on the feed side of the membrane during pervaporation, this approach is mathematically simple and is thermodynamically completely equivalent to the physical process. The evaporation step from the feed hquid to the saturated vapor phase produces a separation, which can be defined (eq. 13) as the ratio of... [Pg.86]

Vacuum Treatment. Milk can be exposed to a vacuum to remove low boiling substances, eg, onions, garlic, and some silage, which may impart off-flavors to the milk, particularly the fat portion. A three-stage vacuum unit, known as a vacreator, produces pressures of 17, 51—68, and 88—95 kPa (127, 381—508, and 660—711 mm Hg). A continuous vacuum unit in the HTST system may consist of one or two chambers and be heated by Hve steam, with an equivalent release of water by evaporation, or flash steam to carry off the volatiles. If Hve steam is used, it must be cuUnary steam which is produced by heating potable water with an indirect heat exchanger. Dry saturated steam is desired for food processing operations. [Pg.359]

Ref 14. Milk equivalent. American, cottage, other. Evaporated and sweetened condensed. Whole and nonfat. ... [Pg.362]

Excess sulfur is filteted before evaporation and crystallization. In one modification, excess sulfur is ptegtound in the sodium sulfide solution and an equivalent amount of sodium sulfite added (35). [Pg.29]

Some use is being made of lower grade heat sources, such as moist air from driers, and the constmction of auxiHaries, such as condensers, integral with the evaporator body. A further step is elimination of the conventional condenser—cooling tower—vacuum pump circuit by recirculating last-effect Hquor over the equivalent of a cooling tower built as an integral part of the evaporator body. [Pg.479]

Ethyl 3-amlnopropsnoate (5). To a tu solution of 4 in THF (frem the bromo ester with NaN3 In OMSO) was added a molar equivalent of Ph3P, t 5 equiv of water and a boiling chip (N2 evolution) Alter 8 h at 20°C and evaporation, the residue was treated with El20-hexane and PhaPO was filtered This process was repeated and 5 was distilled at 40-45° and 10.5 torr (83%). [Pg.359]

The model assumes that liquid evaporation is always the rate controlling step. At some point the model must fail, since as droplet size approaches zero the predicted MIE approaches zero rather than the MIE of the vapor in air. In practice, droplets having diameters less than 10-40 /rm completely evaporate ahead of the flame and burn as vapor (5-1.3). The model also predicts that the MIE continuously decreases as equivalence ratio is increased, although as discussed above, combustion around droplets is not restrained by the overall stoichiometry and naturally predominates at the stoichiometric concentration. It is recommended that the model be applied only to droplet diameters above about 20/rm and equivalence ratios less than about one. [Pg.211]

In addition to volume changes the effect of temperature is also important. Thus the specific latent heat of vaporization of a chemical is the quantity of heat, expressed as kJ/kg, required to change unit mass of liquid to vapour with no associated change in temperature. This heat is absorbed on vaporization so tliat residual liquid or tlie sunoundings cool. Alternatively an equivalent amount of heat must be removed to bring about condensation. Thus the temperature above a liquefied gas is reduced as tlie liquid evaporates and tlie bulk liquid cools. There may be consequences for heat transfer media and the strength of construction materials at low temperatures. [Pg.47]


See other pages where Equivalent evaporation is mentioned: [Pg.14]    [Pg.49]    [Pg.13]    [Pg.14]    [Pg.49]    [Pg.13]    [Pg.846]    [Pg.360]    [Pg.87]    [Pg.429]    [Pg.513]    [Pg.341]    [Pg.234]    [Pg.203]    [Pg.242]    [Pg.345]    [Pg.204]    [Pg.407]    [Pg.339]    [Pg.124]    [Pg.1128]    [Pg.1180]    [Pg.1191]    [Pg.1654]    [Pg.1668]    [Pg.1768]    [Pg.371]    [Pg.390]    [Pg.21]    [Pg.173]    [Pg.267]    [Pg.343]    [Pg.411]    [Pg.548]    [Pg.554]    [Pg.211]    [Pg.81]    [Pg.702]    [Pg.311]   
See also in sourсe #XX -- [ Pg.1435 ]




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