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Conversion factor from formulas

To complete these steps, we need one additional kind of conversion factor that converts between moles of an element and moles of a compound containing that element. We obtain this conversion factor from the compound s chemical formula. For example, the formula for hexane, C6H14, tells us that each hexane molecule contains six... [Pg.342]

The solution map begins with moles of calcium carbonate and ends with moles of oxygen. Determine the conversion factor from the chemical formula, which indicates three O atoms for every CaCOs unit. [Pg.176]

To use this relationship, we need mol NaCl, but we have g NaCl. We can, however, use the molar mass of NaCl to convert from g NaCl to mol NaCl. Then we use the conversion factor from the chemical formula to convert to mol Na. Finally, we use the molar mass of Na to convert to g Na. The solution map is ... [Pg.177]

Decide which conversion factors, mathematical formulas, or chemical principles you will need to solve the problem. Your plan might suggest a single calculation or a series of them involving different conversion factor s. Once you understand how you need to proceed, you may wish to sketch out the route you will take, using arrows to point the way from one stage of the solution to the next. Sometimes you will need data that are not actually part of the problem statement For instance, you ll often use data from the periodic table. [Pg.53]

C03-0042. Diagram the process for converting from the mass of a compound of a known chemical formula to the number of atoms of one of its constituent elements. Include all necessary equations and conversion factors. [Pg.183]

Biovolumes of individual cells were calculated from linear dimensions of measured cells applied to appropriate stereometric formulae (Smayda 1978). Carbon conversion factors established by Menden-Deuer and Lessard (2000) were used to... [Pg.220]

Let s say that you want to find an empirical formula from the percentage composition. First, convert the mass percentage of each element to grams. Second, convert from grams to moles using the molar mass of each element as a conversion factor. (Keep in mind that a formula for a compound can be read as a number of atoms or as a number of moles.) Third, as shown in Sample Problem C, compare these amounts in moles to find the simplest whole-number ratio among the elements in the compound. [Pg.260]

You are given 35.6 g AICI3 and must calculate the number of Al + ions, the number of Cl ions, and the mass in grams of one formula unit of AICI3. Molar mass, Avogadro s number, and ratios from the chemical formula are the necessary conversion factors. The ratio of AP+ ions to CE ions in the chemical formula Is 1 3. Therefore, the calculated numbers of ions should be in that ratio. The mass of one formula unit in grams should be an extremely small number. [Pg.325]

To calculate the number of AP+ and Cl ions, use the ratios from the chemical formula as conversion factors. [Pg.326]

This chapter outlines and lists the symbols, terminology and nomenclature, the units and conversion factors, the order of formulae, the standard conditions, and the fundamental physical constants used in this volume. They are derived from international standards and have been specially adjusted for the TDB publications. [Pg.7]

This section is designed to fill the gap between the familiar formulas presented above and the assumptions and definitions of terms and physical constants needed to apply them. Values for all physical constants and needed conversion factors are provided, and dimensional analyses are included to show how the final results and their units are obtained. This close focus on the details and units of the equations themselves is followed by worked examples from the chemical literature. The goal is to provide nearly everything the interested reader may need to evaluate his or her own data, with reasonable confidence that he or she is doing so correctly. [Pg.19]

The collective unit of mole can also be used to describe ions. Thus the following conversion factors also come from the formula of calcium nitrate, Ca(N03)2. [Pg.343]

To find a conversion factor that converts from moles of phosphorus to moles of P4O10, we look at the formula for tetraphosphorus decoxide, P4O10. It shows that each molecule of tetraphosphorus decoxide contains four atoms of phosphorus. By extension, one dozen P4O10 molecules contains four dozen P atoms, and one mole of P4O10 (6.022 x 10 P4O10 molecules) contains four moles of phosphorus (4 times 6.022 X 10 P atoms). Thus the formula P4O10 provides us with the following conversion factor ... [Pg.344]

The ratio of moles of P4O10 to moles of P (which came from the subscripts in the chemical formula, P4O10) provided the key conversion factor that allowed us to convert from units of phosphorus to units of tetraphosphorus decoxide. [Pg.369]

Kirste and Lehnen2 determined the Z average of the square radius of gyration, Rg, z of the long chain, in the limit of zero concentration, using the classical interpolation formula (15.5.3) see also Fig. 15.1. (The more adequate formula (15.5.4) was unknown to them.) In an earlier experiment, they also measured the Z average of the square radius of gyration, °Rg,z< of the same chains in the quasi-Brownian state this is the state in which polydimethyl-siloxane chains are found when dispersed in dilute solution in bromo-cyclohexane at temperature T (29 °C). The authors quoted above obtained °Rg,z — 125.44 nm2, i.e. an equivalent area 5, 2(°/ g,z) = 250.88 nm2. From this value, we get the conversion factor [see (15.2.1)]... [Pg.792]

Conversions between mass, moles, and the number of particles are summarized in Figure 10.11. Note that molar mass and the inverse of molar mass are conversion factors between mass and number of moles. Avogadros number and its inverse are the conversion factors between moles and the number of representative particles. To convert between moles and the number of moles of atoms or ions contained in the compound, use the ratio of moles of atoms or ions to 1 mole of compound or its inverse, which are shown on the upward and downward arrows in Figure 10.11. These ratios are derived from the subscripts in the chemical formula. [Pg.340]

The necessary basic knowledge is provided in Chapter 2 The Chemical Production Plant and its Components. It deals vhth important subdisciplines of technical chemistry such as catalysis, chemical reaction engineering, separation processes, hydrodynamics, materials and energy logistics, measurement and control technology, plant safety, and materials selection. Thus, it acts as a concise textbook vhthin the book that saves the reader from consulting other works when such information is required. A comprehensive appendix (mathematical formulas, conversion factors, thermodynamic data, material data, regulations, etc.) is also provided. [Pg.484]

Although the results in Table 8 are given to the first decimal place, it is doubtful whether the method warrants such accuracy, for the errors arise, not in the calculation, but in the assumptions that are made. For example, the composition of potash mica does not always correspond exactly to the ideal formula, KAl3Si30io(OH)2, and therefore the conversion factor of Table 7 may differ slightly from the stated value. The same thing applies to other minerals. Furthermore, the clay may contain silicate minerals other than kaolinite, micas and quartz this would render the method of calculation unsound. In cases of doubt, however, the composition should be checked by thermal analysis. X-ray analysis, or both. [Pg.49]

A good laboratory balance can measure mass routinely to within 10 kg, and use of a microbalance with considerable precautions can lead to mass measurements to within 10 kg or so (Section 2.3). This is stiU three orders of magnitude larger than the mass changes equivalent to heats of reaction, so the physicists argument is valid from this point of view. (Note that the above calculation of Am exemplifies an important property of the SI, its coherence, by which we mean that if all quantities in a formula are expressed in SI units without prefixes the result of the calculation is also expressed in the appropriate SI unit, with no need for conversion factors). [Pg.7]

Often such relationships will take the form of conversion factors or equations. These may be given in the problem, in which case you will have written them down under "Given" in Step 1. Usually, however, you will need other information—which may include physical constants, formulas, or conversion factors—to help get you from what you are given to what you must find. You may recall this information from what you have learned or you can look it up in the chapters or tables within the book. [Pg.27]

Draw a solution map showing the conversion from mol H2O to g H2O. The conversion factor is the molar mass of water, which you can determine by summing the atomic masses of all the atoms in the chemical formula. [Pg.173]

V th conversion factors such as titese— which come directly from the chemical formula— we can determine the amoimts of the constituent elements present in a given amount of a compound. [Pg.176]


See other pages where Conversion factor from formulas is mentioned: [Pg.337]    [Pg.12]    [Pg.116]    [Pg.117]    [Pg.112]    [Pg.112]    [Pg.64]    [Pg.182]    [Pg.372]    [Pg.372]    [Pg.327]    [Pg.8]    [Pg.540]    [Pg.330]    [Pg.341]    [Pg.378]    [Pg.90]    [Pg.87]    [Pg.93]    [Pg.87]    [Pg.175]   
See also in sourсe #XX -- [ Pg.112 , Pg.113 ]




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