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Chemical equivalence tests

If the two structures produced by mental replacement of two different hydrogens in a molecule by a test group are the same the hydrogens are chemically equivalent Thus... [Pg.533]

Suspend 10 ANRC reference casein (Humko Sheffield Chemical, Teklad Test Diets, or equivalent) in 200 ml water and adjust pH to 8.0 with NaOH. Maintain at pH 8 for at >1 hr. Freeze dry and determine nitrogen using Kjeldahl method (unitb 1.2). [Pg.133]

We would expect the radical balance reactions (6) through (16) to be equilibrated at all points in these flames. Tests of the equilibration have been made, as for example in Figure 6, by evaluating the equilibrium concentration ratios using experimentally measured concentration values. Since O, H, S, and H2S concentrations were not measured directly we can indirectly evaluate the equilibration of the radical balance process by using reactions that are sums of the above listed processes. Four such reactions are listed below with an indication of a combination of reactions (6) through (16) that is chemically equivalent. [Pg.124]

Atoms that cannot be distinguished chemically. The replacement test for chemically equivalent atoms gives identical compounds, (p. 576)... [Pg.617]

The term toxic unit (TU) plays an important role in mixture concentration-response analysis. It is defined as the actual concentration of a chemical in the mixture divided by its effect concentration (e.g., c/EC50 Sprague 1970). The toxic unit is equivalent to the hazard quotient (HQ), which is used for calculating the hazard index (HI Hertzberg and Teuschler 2002). The term hazard quotient is generally used more in the context of risk assessment (see Chapter 5 on risk assessment), and the term toxic unit is used more in the context of concentration-response analysis, and therefore the latter term is used here. Toxic units are important for 2 reasons. First, toxic units are the core of the concept of concentration addition concentration addition occurs if the toxic units of the chemicals in a mixture that causes 50% effect sum up to 1. Second, toxic units can help to determine which concentrations of the chemicals to test when a mixture experiment needs to be designed. [Pg.122]

In addition to meeting the requirements concerning chemical-shift differences compared with coupling constants (Au/7), first-order spectra must pass a symmetry test. Any pair of chemically equivalent nuclei must have the same coupling constant to any other nucleus. Nuclear pairs that fail this test are said to be magnetically nonequivalent. To apply the test, it is useful to understand the role of symmetry in the NMR spectrum. [Pg.99]

In the RPF method (eqn (1)), the user must identify the constraints of the application of a set of RPFs. For example, the health effect, dose range of component doses, route(s) of exposure, and dura-tion(s) of exposure for which the RPFs can be applied must be specified (e.g., a set of RPFs may be constrained to oral exposures and not be used for exposures to the same mixture through the inhalation route). To apply the method, an RPF is estimated for each mixture component the RPF estimates the toxicity of the component relative to that of the IC. RPFs commonly are estimated from a ratio of equally toxic doses of the individual dose-response functions for the component and the IC. For example, the quotient of the effective dose at which ten percent of a test population exhibits an effect (EDio) of the IC and the component could serve as a value for the component s RPF obviously, the RPF for the IC equals 1. The index chemical equivalent dose of an individual component is the product of the component dose and the RPF of the component. These equivalent doses are summed across all components. The risk posed by the mixture is estimated by comparing the summed index chemical equivalent doses of the mixture to the dose-response function of the IC ... [Pg.1706]

Discussion Faraday s laAv states (1) that the quantity of any one substance decomposed by the electric current is proportional to the quantity of electricity passed through its solution, and (2) that the quantities of two or more substances liberated by equal quantities of electricity are proportional to the chemical equivalents of these substances. The first part of the law can be tested by passing a constant current through a solution of a salt, such as copper sulphate, and determining the weight of copper deposited during different time intervals. When a constant current flows the quantity of electricity that passes is proportional to the time during which the current flows. [Pg.219]

It is aqueous and has a pH less than or equal to 2 or greater than or equal to 12.5, as determined by a pH meter using either an EPA test method or an equivalent test method approved by the Administrator. The EPA test method for pH is specified as Method 5.2 in Test Methods for the Evaluation of Solid Waste, Physical/Chemical Methods. "... [Pg.113]

Other similar products for which the preferred supplier is currently not approved should be investigated. The supplier should be asked if they have any chemical equivalent materials. If the preferred supplier has aiy, then samples should be requested and the necessary testing should begin. These tests should be completed as soon as possible so that the material can be purchased from the preferred supplier. In some situations a functional equivalent may need to be tested to try to increase the business from the preferred supplier as well as eliminate some of the non-preferred suppliers. [Pg.89]

The principle of the titrimetric method is based on the chemical equivalence of two solutions. In general, any titration system can be used. A test solution with a known concentration Co and an unknown volume Vu is dispensed into a titration vessel containing a receiver liquid, followed by a titration process with a titration solution of known concentration Cj-. An auxiliary solution may be required to adjust the pH value before the titration starts. The equivalence point Eq (in milliliters) is determined by potentiomet-ric detection, for example, with a silver electrode. The unknown volume can be calculated using the following formula ... [Pg.1192]

Japan has the other leaching test. It is the method regulated by JIS K 0058-2 (2005), (Test method for acid extractable contents of chemicals). This test is almost the same as the public announcement no. 19 except for sample size and weight. For this test, a sample is dissolved in a hydrochloric acid solution of 1 mol/1. The dissolved concentration given by this test is estimated to be equivalent to the maximum extractable concentration. [Pg.159]

Faraday believed that the passage of an electric current caused a distortion in the forces of affinity which held the compound together. The decomposition was therefore a chemical process, and the quantities of different elements liberated by the passage of the same quantity of electricity should be in proportion to their chemical equivalent weights. In order to test this hypothesis, he passed an electric current through a number of solutions and fused metallic salts, and in each case he also connected a voltameter in series to measure the amount of hydrogen produced by the quantity of electricity that passed. Faraday s predictions were verified, and are now embodied in his second law of electrolysis. [Pg.102]

However, if the H and D in the dihydride are chemically equivalent or become scrambled, then the racemate will have 50% of the D on the a-carbon. In practice, the deuterium content of the product is always somewhat less than predicted. For the Ru(PPh>3(H)2 catalyst described in the previous paragraph, 37% of the expected D was found on the a-carbon. Pkmies and Backvall applied this method to a number of catalysts and found that many Rh and Ir catalysts gave >90% retention of D on the a-carbon, suggesting a monohydride pathway. The same was true for most of the Ru systems tested, except for the case mentioned above and for (Ph3p)2Ru(Cl)2(Ti2-NH2CH2CH2l ). [Pg.214]

These protons cannot be interchanged by either rotational symmetry or reflectional symmetry. Therefore, these two protons are not chemically equivalent. In this case, the replacement test produces diastereomers. [Pg.725]


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See also in sourсe #XX -- [ Pg.390 , Pg.391 , Pg.392 , Pg.393 ]




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