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Barriers, separation

Figure 8 shows a one-dimensional sketch of a small fraction of that energy landscape (bold line) including one conformational substate (minimum) as well as, to the right, one out of the typically huge number of barriers separating this local minimum from other ones. Keeping this picture in mind the conformational dynamics of a protein can be characterized as jumps between these local minima. At the MD time scale below nanoseconds only very low barriers can be overcome, so that the studied protein remains in or close to its initial conformational substate and no predictions of slower conformational transitions can be made. [Pg.90]

The time that the trajectory must spend at / max to ensure that the equilibrium distribution is sampled is at least Tmin, the time required to surmount the largest barrier separating the global energy minimum from other thermodynamically important states. Using Eq. (39) we find... [Pg.205]

The previous treatment relied on the assumption that the transition occurs on a single potential energy surface V(x) characterized by a barrier separating two wells. This potential is actually created from the terms of the initial and final electronic states. The separation of electron and nuclear coordinates in each of these states gives rise to the diabatic basis with nondiagonal Hamiltonian matrix... [Pg.54]

In case 3, the barrier separating A and B is small relative to that for formation of A ... [Pg.215]

The concept of ion pairs in nucleophilic substitution is now generally accepted. Presumably, the barriers separating the intimate, solvent-separated, and dissociated ion pairs are quite small. The potential energy diagram in Fig. 5.4 depicts the three ion-pair species as being roughly equivalent in energy and separated by small barriers. [Pg.272]

For each reaction, plot energy (vertical axis) vs. the number of the structure in the overall sequence (horizontal axis). Do reactions that share the same mechanistic label also share similar reaction energy diagrams How many barriers separate the reactants and products in an Sn2 reaction In an SnI reaction Based on your observations, draw a step-by-step mechanism for each reaction using curved arrows () to show electron movements. The drawing for each step should show the reactants and products for that step and curved arrows needed for that step only. Do not draw transition states, and do not combine arrows for different steps. [Pg.63]

The interconversion must be relatively easy, i.e., the energy barrier separating the tautomers must not be too high. No fixed limit exists, but with dG of less than 25 kcal they would certainly be considered as tautomers, whereas with an energy barrier of about 40 kcal they would not be considered as tautomers. However, frequently such energy barriers can be lowered by using a suitable catalyst. [Pg.4]

There are various theories on how passive films are formed however, there are two commonly accepted theories. One theory is called the oxide film theory and states that the passive film is a diffusion-barrier layer of reaction products (i.e., metal oxides or other compounds). The barriers separate the metal from the hostile environment and thereby slow the rate of reaction. Another theory is the adsorption theory of passivity. This states that the film is simply adsorbed gas that forms a barrier to diffusion of metal ions from the substrata. [Pg.1268]

A question that intrigued several kineticists around 1920 was the following. For bi-molecular reactions of the type A -1- B = Products collision theory gave at least a plausible conceptual picture If the collision between A and B is sufficiently vigorous, the energy barrier separating reactants and products can be crossed. How, though can one explain the case of monomolecular elementary reactions, e.g. an isomerization, such as cyclopropane to propylene, or the decomposition of a mol-... [Pg.106]

Several text books introduce the concept of catalysis with a potential energy diagram in which an energy barrier separates the products and the reactants, and then state that a catalyst lowers this barrier. Do you approve of this representation Explain your answer. [Pg.401]

Under the conditions determined by the symmetric permutation of identical particles, any number of particles can be placed in each quantum state, lb distribute , of a given energy in gi quantum states, consider the fo I[Pg.139]

The height of the potential barrier separating the initial and final states of the nuclear subsystem decreases and, hence, the Franck-Condon factor increases (Fig. 6). In the classical limit, this results in a decrease of the activation free energy. [Pg.124]

Fig. 4.2. Free energy computation using constraint forces. It may be difficult to sample the surface (x) = using a constrained simulation because of the presence of energy barriers separating different reaction pathways. Left a barrier is shown in the middle of the pathway from reactant A to product B. Right two barriers are shown at B... Fig. 4.2. Free energy computation using constraint forces. It may be difficult to sample the surface (x) = using a constrained simulation because of the presence of energy barriers separating different reaction pathways. Left a barrier is shown in the middle of the pathway from reactant A to product B. Right two barriers are shown at B...
This is concerned with the fact that in the case of the relaxation time, roughly speaking only half of all Brownian particles should leave the initial potential minimum to reach the equilibrium state, while for the profile of the decay time case all particles should leave the initial minimum. Expression (5.120), of course, is true only in the case of the sufficiently large potential barrier, separating the stable states of the bistable system, when the inverse probability current from the second minimum to the initial one may be neglected (see Ref. 33). [Pg.411]

The examples cited above are only two of the many possible cases of H-bond isomerization. Because of the low kinetic barriers separating these species, equilibration of H-bonded isomer populations to limiting thermodynamic values is generally expected to be much faster than for covalent isomers. Methods of quantum statistical thermodynamics can be used to calculate partition functions and equilibrium population distributions for H-bonded isomers,41 just as in the parallel case for covalent isomers and conformers. [Pg.607]


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See also in sourсe #XX -- [ Pg.141 , Pg.142 ]




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