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Balanced equation and

Substituting equation 6.46 into the charge balance equation and solving for [A ] gives... [Pg.169]

In Chapter 2 we developed models based on analyses of systems that had simple inputs. The right-hand side was either a constant or it was simple function of time. In those systems we did not consider the cause of the mass flow—that was literally external to both the control volume and the problem. The case of the flow was left implicit. The pump or driving device was upstream from the control volume, and all we needed to know were the magnitude of the flow the device caused and its time dependence. Given that information we could replace the right-hand side of the balance equation and integrate to the functional description of the system. [Pg.113]

Write a balanced equation and give the names of the products for the reaction of... [Pg.552]

Chromic oxide, Cr,03, is used as a green pigment and is often made by the reaction between NajCrjOjfs) and NH(ClfsJ to give Cr >rfs), NaCl(s), Nifg), and HjO(g). Write a balanced equation and calculate how much pigment can be made from 1.0 X 101 kg of sodium dichromate. [Pg.410]

The kinetic energy attributable to this velocity will be dissipated when the liquid enters the reservoir. The pressure drop may now be calculated from the energy balance equation and equation 3.19. For turbulent flow of an incompressible fluid ... [Pg.70]

To find out the mass of a product that can be formed from a known mass of a reactant, we first convert the grams of reactant into moles, use the mole ratio from the balanced equation, and then convert the moles of product formed into grams. Essentially, we go through three steps ... [Pg.110]

If an ion is doubly charged, wc multiply its concentration by 2 in the charge balance equation, and likewise for triply charged ions. [Pg.553]

In very dilute solutions of strong acids and bases, the pH is significantly affected by the autoprotolysis of water. The pH is determined by solving three simultaneous equations the charge-balance equation, the material-balance equation, and the expression for Kw. [Pg.555]

Division by the stoichiometric coefficients takes care of the stoichiometric relations between the reactants and products. There is no need to specify the species when reporting the unique average reaction rate, because the value of the rate is the same for each species. However, the unique average rate does depend on the coefficients used in the balanced equation, and so the chemical equation should be specified when reporting the unique rate. [Pg.651]

Using data available in Appendix 2A, write balanced equations and calculate the hear released when (a) 1.00 mol and (b) 1.00 g of each of the following compounds is burned in excess oxygen propane, butane, and pentane. Is there a trend in the amount of heat released per mole of molecules or per gram of compound If so, what is it ... [Pg.868]

Sanger, M. J. (2005). Evaluating students conceptual understanding of balanced equations and stoichiometric ratios using a particulate drawing. Jownua/ of Chemical Education, 52(1), 131-134. [Pg.190]

C04-0147. Write the balanced equation and determine the number of moles of water produced when 2.95 mL of pyridine (C5 H5 N, p = 0.982 g/mL) reacts with excess O2 to give water, carbon dioxide, and molecular nitrogen. [Pg.276]

C04-0150. A former antiknock ingredient in gasoline is a colorless liquid whose formula is C5 H]2 O. Write the balanced equation, and determine the number of moles of carbon dioxide produced when 3.15 mL of the... [Pg.276]

The problem asks for the amount of energy released in a chemical reaction that forms a specified mass of product. The balanced equation is as much visualization as is needed for this problem. The data provided are A S for the balanced equation and the mass of product formed, 1.00 kg. [Pg.376]

To show the logic of this kind of calculation, we apply the seven-step approach to problem solving. We are asked to calculate at 298 K for the Haber reaction. We visualize the process by remembering that there is a connection between free energy, A G reaction > and equilibrium,. eq. The problem provides only the balanced equation and the temperature. Any other necessary data will be found in tables and appendices. [Pg.1151]

At the end of 24 hours of continuous process the system was shut down. The knowledge of flowed buffer volumes and of the optical densities inside and downstream each ultrafiltration stage allowed to estimate product distribution (see appendix for mass-balance equations and the calculation procedure). The content of each cell was recovered and ffeeze-dried in order to be stored and used for subsequent kinetic experiments. A schematic flow-sheet of the whole procedure is illustrated in figure 1. [Pg.442]

While the principle of the mass balance is very simple, its application can often be quite difficult. It is important therefore to have a clear understanding of the nature of the system (physical model) which is to be modelled by the mass balance equations and also of the methodology of modelling. [Pg.17]

The component mass balance, when coupled with the heat balance equation and temperature dependence of the kinetic rate coefficient, via the Arrhenius relation, provide the dynamic model for the system. Batch reactor simulation examples are provided by BATCHD, COMPREAC, BATCOM, CASTOR, HYDROL and RELUY. [Pg.144]

The coefficients of the above equations are the partial differentials of the two dynamic balance equations and are given by... [Pg.154]

As discussed previously in Sec. 3.3.1.7, each additional component of the feed mixture must be expressed by a separate component mass balance equation and by its own equilibrium relationship. [Pg.210]

The component mass balance equation, combined with the reactor energy balance equation and the kinetic rate equation, provide the basic model for the ideal plug-flow tubular reactor. [Pg.234]

Solution of the required column height is achieved by integrating the two component balance equations and the heat balance equation, down the column from the known conditions Xi , yout and TLin, until the condition that either Y is greater than or X is greater than Xqui is achieved. In this solution approach, variations in the overall mass transfer capacity coefficient both with respect to temperature and to concentration, if known, can also be included in the model as required. The solution procedure is illustrated by the simulation example AMMON AB. [Pg.253]

Input functions [i.e., I(t)], describing the rate at which the administered dose enters a compartment, may have various forms depending on the administration schedule. The input function /(f) is added to the appropriate mass balance equation and can describe any drug administration pattern. First-order absorption... [Pg.87]

We assume all reactions to be first order and irreversible within the range of the experimental conditions. The governing differential mass balance equations and their solutions have been reported [9J. The values of the constants through at 450°C are shown in Table I. A comparison of the experimental data with the theoretical predictions is shown in Figures 2 through 4 the above assumption of a first order reaction appears reasonable. [Pg.367]

In general, when designing a batch reactor, it will be necessary to solve simultaneously one form of the material balance equation and one form of the energy balance equation (equations 10.2.1 and 10.2.5 or equations derived therefrom). Since the reaction rate depends both on temperature and extent of reaction, closed form solutions can be obtained only when the system is isothermal. One must normally employ numerical methods of solution when dealing with nonisothermal systems. [Pg.353]

Equations 12.7.28 and 12.7.29 provide a two-dimensional pseudo homogeneous model of a fixed bed reactor. The one-dimensional model is obtained by omitting the radial dispersion terms in the mass balance equation and replacing the radial heat transfer term by one that accounts for thermal losses through the tube wall. Thus the material balance becomes... [Pg.504]

Note that the rate of formation of A is rA, as defined in section 1.4 for a reactant, this is a negative quantity. The rate of disappearance of A is (-rA), a positive quantity. It is this quantity that is used subsequently in balance equations and rate laws for a reactant. For a product, the rate of formation, a positive quantity, is used. The symbol rA may be used generically in the text to stand for rate of reaction of A where the sign is irrelevant and correspondingly for any other substance, whether reactant or product. [Pg.27]

Our treatment of chemical kinetics in Chapters 2-10 is such that no previous knowledge on the part of the student is assumed. Following the introduction of simple reactor models, mass-balance equations and interpretation of rate of reaction in Chapter 2, and measurement of rate in Chapter 3, we consider the development of rate laws for single-phase simple systems in Chapter 4, and for complex systems in Chapter 5. This is... [Pg.681]

There are probably multiple pathways in the conversion of an organic nitrate into N O, some chemical and some enzymatic. For the former the presence of thiol groups appears to be necessary [57, 58]. The overall reaction is shown in Eq. (10). This is not a balanced equation and does not reflect fully the course of the reaction. A number of studies have shown that thiols, both in vivo and in vitro, can affect this process. In most cases it appears that thiols act as a reducing agent, being converted to disulfide, while nitrite is released (Eq. (11)). [Pg.213]

Step 5 Double check your balanced equation and be sure the coefficients are the lowest possible whole numbers. [Pg.46]


See other pages where Balanced equation and is mentioned: [Pg.163]    [Pg.147]    [Pg.56]    [Pg.223]    [Pg.673]    [Pg.222]    [Pg.182]    [Pg.224]    [Pg.41]    [Pg.154]    [Pg.502]    [Pg.175]    [Pg.276]    [Pg.73]    [Pg.354]    [Pg.220]    [Pg.21]   
See also in sourсe #XX -- [ Pg.571 ]




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Balance equation

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