Solute 69 unsaturated

Case III, An Excess of One Component Is Necessary.— It sometimes happens that an excess of one component is requisite for the formation of a double salt. Conversely, if the solid double salt is dissolved and the solution is evaporated, one of the components separates until the required excess of the other component has accumulated in the solution. This case is well illustrated by the mineral carnallite, KCl-MgCl2-6H20, one of the products of the Stassfurt mines. Let the point A (Fig. 20), represent a saturated solution of potassium chloride and the points, a saturated solution of magnesium chloride. An unsaturated solution of equivalent quantities of the two salts is then represented on the line OE, say at a. If the solution is evaporated at constant temperature (20°), the point a approaches the solubility curve of potassium chloride, viz., the line AC. At E, potassium chloride begins to separate and continues to do so until the representative point has moved to C, at which point carnallite makes its appearance. Since the separation of carnallite withdraws the two salts in equimolecular ratio from the solution, and since the solution now contains much more magnesium chloride than potassium chloride, the deposits of crystals of carnallite leave the solution unsaturated with respect to potassium chloride, and the latter salt steadily passes into solution again, while the deposit of carnallite increases. If, when the point C is reached, the crystals of potassium chloride are... 

In basic solution, unsaturated with zincate ions, the anode reaction may be written as... 

In this section, you learned the meanings of several important terms, such as solvent, solute, saturated solution, unsaturated solution, aqueous solution, and solubility. You need to know these terms in order to understand the material in the rest of the chapter. In section 8.2, you will examine the factors that affect the rate at which a solute dissolves in a solvent. You will also learn about factors that affect solubility. 

From the experimental value of x of the saturated solution at each temperature we calculate the theoretical value of at 18 °C for the solution (unsaturated or supersaturated) of the same concentration. We divide this value of x by the appropriate value of A determined, if necessary, by successive approximations to obtain the concentration of the saturated solution. 

It is evident that absorption reagents are not very selective and then the suitable choice of absorption reagents and, mainly, the order in which the individual gases are to be determined, are important. If complete analysis of common industrial gases by a volumetric method is of interest, then the following procedure must be employed. First, carbon dioxide is determined as it is readily soluble in all alkaline solutions, unsaturated hydrocarbons must be removed as the second component, and then... 

Key Terms Saturated solution Unsaturated solution Supersaturated solution... 

Catechol and related compounds dissolve silica in neutral solution, but it is not certain that a catalytic effect is involved. It is likely that these materials simply combine with Si(OH)4 as rapidly as it is liberated from the surface by the catalytic action of OH ion and thus keep the solution from becoming saturated. Above pH 11 the hydroxyl ions act in the same way, converting Si(OH)4 to silicate ions, thus keeping the solution unsaturated so that silica continues to dissolve. But below pH 11, even down to pH 3, the OH" ion is only the catalyst that controls the rate at which silica dissolves until the solution reaches saturation. 

Monomeric silica is strongly adsorbed onto the surface of hydrous aluminum oxides. There is a reaction between SiCOH) and crystalline Al(OH)j by which several reaction layers of Si02 are built up, with simultaneous decrease in pH of the suspension (68a). Formation of the first layer is rapid, but the second and third layers form progressively much more slowly. It would seem that diffusion of Al" " or AlOj" from the surface of the crystal must be involved, with the formation of a silica-rich aluminosilicate. A relatively low content of aluminum ion in the SiO-layer greatly reduces its solubility, thus explaining the deposition of SiO from a solution unsaturated with respect to pure amorphous silica. 

Kolbe reaction The pre >aration of saturated or unsaturated hydrocarbons by the electrolysis of solutions of the alkali salts of aliphatic carboxylic acids. Thus, ethanoic acid gives ethane,... 

The most common situation studied is that of a film reacting with some species in solution in the substrate, such as in the case of the hydrolysis of ester monolayers and of the oxidation of an unsaturated long-chain acid by aqueous permanganate. As a result of the reaction, the film species may be altered to the extent that its area per molecule is different or may be fragmented so that the products are soluble. One may thus follow the change in area at constant film pressure or the change in film pressure at constant area (much as with homogeneous gas reactions) in either case concomitant measurements may be made of the surface potential. 

The bromine test is applied first. The organic compound, if a liquid, is treated with 2-3 drops of liquid bromine or (preferably) a solution of bromine in carbon tetrachloride if the organic compound is a solid, it should first be dissolved in cold carbon tetrachloride or chloroform. The rapid absorption of the bromine (and consequent disappearance of the red colour) is a strong indication that the compound is unsaturated, and is therefore undergoing direct addition of the bromine. 

Oxidation, (a) Unsaturation test. Dissolve about o-i g. of cinnamic acid or of a soluble cinnamate in about 5 ml. of 10% NajCOg solution. To the cold solution add 1% aqueous KMn04 drop by drop. Immediate decolorisation denotes unsaturation. (Note. Many easily oxidisable substances, e.g.y formic acid, acetaldehyde, etc.y also rapidly decolorise alkaline permanganate. Cinnamates, however, do not reduce Fehling s solution.)... 

Deliquescence and efflorescence. A substance is said to deliquesce (Latin to become liquid) when it forms a solution or liquid phase upon standing in the air. The essential condition is that the vapour pressure of the saturated solution of the highest hydrate at the ordinary temperature should be less than the partial pressure of the aqueous vapour in the atmosphere. Water will be absorbed by the substance, which gradually liquefies to a saturated solution water vapour will continue to be absorbed by the latter until an unsaturated solution, having the same vapour pressure as the partial pressure of water vapour in the air, is formed. In order that the vapour pressure of the saturated solution may be sufficiently low, the substance must be extremely soluble in water, and it is only such substances (e.g., calcium chloride, zinc chloride and potassium hydroxide) that deliquesce. 

All hydrocarbons prepared by th -. Wurtz reaction contain small quantities of unsaturated hydrocarbons. These may be removed by shaking repeatedly with 10 pier cent, of the volume of concentrated sulphuric acid until the acid is no longer coloured (or is at most extremely pale yellow) each shaking should be of about 5 minutes duration. The hydrocarbon is washed with water, 10 pier cent sodium carbonate solution, water (twice), and dried with anhydrous magnesium or calcium sulphate. It is then distilled from sodium two distillations are usually necessary... 

Chakactkrisation of Unsaturatkd Aliphatic Hydrocarbons Unlike the saturated hydrocarbons, unsaturated aliphatic hydrocarbons are soluble in concentrated sulphuric acid and exhibit characteristic reactions with dUute potassium permanganate solution and with bromine. Nevertheless, no satisfactory derivatives have yet been developed for these hydrocarbons, and their characterisation must therefore be based upon a determination of their physical properties (boiling point, density and refractive index). The physical properties of a number of selected unsaturated hydrocarbons are collected in Table 111,11. 

Test the solution so obtained for unsaturation by adding cold 1 per cent, potassium permanganate solution a drop at a time. The immediate disappearance of the purple colour and the formation of a brown turbidity indicates the presence of a double bond Baeyer a test). It must be noted that many substances, not unsaturated, decolourise warm acid or neutral potassium permanganate solution. 

Unsaturated esters decolourise a solution of bromine in carbon tetrachloride and also neutral potassium permanganate solution. 

Crotonic acid is an example of an a(3-unsaturated acid, whilst vinylacetic acid is a acid. Upon heating the latter with a solution of an... 

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