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Molar mass molecular formula determination

The empirical formula CH2 is not a stable substance. It is necessary to determine the molar mass to determine the molecular formula. If this hydrocarbon were a gas or an easily volatilized liquid, its molar mass could be determined from the density of the gas, as shown in Chapter 5. Supposing such a determination yields a molar mass of about 55 g/mol, what is the molecular formula ... [Pg.29]

Formulas describe the composition of compounds. Empirical formulas give the mole ratio of the various elements. However, sometimes different compounds have the same ratio of moles of atoms of the same elements. For example, acetylene, C2H2, and benzene, CeHe, each have 1 1 ratios of moles of carbon atoms to moles of hydrogen atoms. That is, each has an empirical formula CH. Such compounds have the same percent compositions. However, they do not have the same number of atoms in each molecule. The molecular formula is a formula that gives all the information that the empirical formula gives (the mole ratios of the various elements) plus the information of how many atoms are in each molecule. In order to deduce molecular formulas from experimental data, the percent composition and the molar mass are usually determined. The molar mass may be determined experimentally in several ways, one of which will be described in Chap. 12. [Pg.108]

This is an extension of an ideal gas law calcnlation involving molar mass. If you determine the molar mass of the gas, yon will be able to determine the molecular formula from the empirical formula. [Pg.125]

Therefore in order to calculate the molecular formula of a compound it is necessary to know its molar mass. Molar masses can be determined by a variety of physical measurements, including back titrations (for weak acids and bases) and weighing gases. Mass spectrometry is frequently used to determine the molar masses of molecular substances (Chapter 2). Automated instruments for determining the empirical and molecular formulas of organic compounds are available. [Pg.30]

The mass of a mole of elementary units, e.g. molecules or formula units, is named molar mass M. There is a simple relation between the molar mass M and the relative molecular mass Mr, if the mass m indicates the mass of a molecule or of a formula unit, the molar mass M is determined by ... [Pg.25]

As you will see shortly, the formula of a compound can be used to determine the mass percents of the elements present. Conversely, if the percentages of the elements are known, the simplest formula can be determined. Knowing the molar mass of a molecular compound, it is possible to go one step further and find the molecular formula. In this section we will consider how these three types of calculations are carried out. [Pg.56]

The molar mass of acetic acid, as determined with a mass spectrometer, is about 60 g/mol. Using that information along with the simplest formula found in Example 3.6, determine the molecular formula of acetic acid. [Pg.60]

To find the molecular formula of a compound, we need one more piece of information—its molar mass. Then all we have to do is to calculate how many empirical formula units are needed to account for the molar mass. One of the best ways of determining the molar mass of an organic compound is by mass spectrometry. We saw this technique applied to atoms in Section B. It can be applied to molecules, too and, although there are important changes of detail, the technique is essentially the same. [Pg.73]

The molecular formula of a compound is found by determining how many empirical formula units are needed to account for the measured molar mass of the compound. [Pg.74]

J 3 Determine the molecular formula of a compound from its empirical formula and its molar mass (Example F.3). [Pg.74]

F.13 Osmium forms a number of molecular compounds with carbon monoxide. One light-vellow compound was analyzed to give the following elemental composition 15.89% C, 21.18% O, and 62.93% Os. (a) What is the empirical formula of this compound (b) From the mass spectrum of the compound, the molecule was determined to have a molar mass of 907 g-mol 1. What is its molecular formula ... [Pg.75]

M.9 The stimulant in coffee and tea is caffeine, a substance of molar mass 194 g-mol When 0.376 g of caffeine was burned, 0.682 g of carbon dioxide, 0.174 g of water, and 0.1 10 g of nitrogen were formed. Determine the empirical and molecular formulas of caffeine, and write the equation for its combustion. [Pg.123]

The flowchart in Figure 3-15 outlines the process. From masses of products, determine masses of elements. Then convert masses of elements to moles of elements. From moles of the elements, find the empirical formula. Finally, use information about the molar mass to obtain the molecular formula. [Pg.166]

C03-0073. Determine the molecular formula and calculate the molar mass of each of the following essential amino acids ... [Pg.188]

C03-0089. Combustion analysis of 0.60 g of an unknown organic compound that contained only C, H, and O gave 1.466 g of carbon dioxide and 0.60 g of water in a combustion analysis. Mass spectral analysis showed that the compound had a molar mass around 220 g/mol. Determine the empirical formula and molecular formula. [Pg.190]

C03-0125. A 3.75-g sample of compound that contains sulfur and fluorine contains 2.93 g of fluorine. The molar mass Is less than 200 g/mol. Calculate the percent composition of the compound and determine its molecular formula. [Pg.195]

We can use the ideal gas equation to calculate the molar mass. Then we can use the molar mass to identify the correct molecular formula among a group of possible candidates, knowing that the products must contain the same elements as the reactants. The problem involves a chemical reaction, so we must make a connection between the gas measurements and the chemistry that takes place. Because the reactants and one product are known, we can write a partial equation that describes the chemical reaction CaC2(. ) +H2 0(/) Gas -I- OH" ((2 q) In any chemical reaction, atoms must be conserved, so the gas molecules can contain only H, O, C, and/or Ca atoms. To determine the chemical formula of the gas, we must find the combination of these elements that gives the observed molar mass. [Pg.302]

Work out the molecular formula of the compound determined in Question 7(c) above, given that its molar mass is 58 gmol-1. (2)... [Pg.30]

A The molecular formula of acetic acid isC2H402. Determine the molar mass of acetic acid. [Pg.38]

We determine the molality of the solution, then the number of moles of solute present, and then the molar mass of the solute. Then we determine the compound s empirical formula, and combine this with the molar mass to determine the molecular formula. [Pg.305]

The empirical formula is C3H2N02, with a formula mass of 84.0 g/mol. This is one-half the experimentally determined molar mass. Thus, the molecular formula is C6H4N204. [Pg.306]

A reasonable empirical formula is C4H4S, which has an empirical mass of 84.1 g/mol. Since this is the same as the experimentally determined molar mass, the molecular formula of thiophene if C4H4S. [Pg.306]

The molecular formula may be determined by dividing the actual molar mass of the compound by the empirical molar mass. In this case the empirical molar mass is 46 g/mol. [Pg.90]

M.10 The bitter-tasting compound quinine is a component of tonic water and is used as a protection against malaria. When a sample of mass 0.487 g was burned, 1.321 g of carbon dioxide, 0.325 g of water, and 0.0421 g of nitrogen were produced. The molar mass. of quinine is 324 g-mol-1. Determine the empirical and molecular formulas of quinine. [Pg.147]

Take the freezing-point constant from Table 8.9. Use this -molality to calculate the moles of solute in the sample by multiplying it by the mass of solvent in kilograms. At this stage, determine the molar mass of the solute by dividing the given mass of solute by the number of moles present. For the molecular formula, decide how many atoms of sulfur are needed in each molecule to account for the molar mass. [Pg.526]

An elemental analysis of the hormone epinephrine is 59.0% carbon, 26.2% oxygen, 7.15% hydrogen, and 7.65% nitrogen by mass. When 0.64 g of epinephrine dissolved in 36.0 g of benzene, the freezing point decreased by 0.50°C. (a) Determine the empirical formula of epinephrine, (b) What is the molar mass of epinephrine (c) Deduce the molecular formula of epinephrine. [Pg.542]

In section 6.2, you learned how to calculate the empirical formula of a compound based on percentage composition data obtained by experiment. In section 6.3, you will learn how chemists use the empirical formula of a compound and its molar mass to determine the molecular formula of a compound. [Pg.214]

Chemists can use a mass spectrometer to determine the molar mass of a compound. They can use the molar mass, along with the molar mass of a known empirical formula, to determine the compound s molecular formula. For example, the empirical formula CH has a molar mass of 13 g/mol. We know, however, that acetylene, C2H2, and benzene, C6H6, both have the empirical formula CH. Suppose it is determined, through mass spectrometry,... [Pg.216]

The empirical formula of ribose (a sugar) is CH20. In a separate experiment, using a mass spectrometer, the molar mass of ribose was determined to be 150 g/mol. What is the molecular formula of ribose ... [Pg.217]


See other pages where Molar mass molecular formula determination is mentioned: [Pg.51]    [Pg.66]    [Pg.90]    [Pg.124]    [Pg.158]    [Pg.169]    [Pg.90]    [Pg.15]    [Pg.88]    [Pg.91]    [Pg.200]   


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