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Molecular formula from

This hybrid is used in one form to measure highly accurate m/z values to obtain excellent elemental compositions of ions and therefore molecular formulae from molecular ions in the other form, it is used to obtain MS/MS data at high resolution. [Pg.402]

EXAMPLE F.3 Sample exercise Determining the molecular formula from the empirical formula... [Pg.74]

Molecular formulae from high-resolution mass measurements... [Pg.351]

Atoms and their symbols were introduced in Chap. 3 and 1. In this chapter, the representation of compounds by their formulas will be developed. The formula for a compound (Sec. 4.3) contains much information of use to the chemist. We will learn how to calculate the number of atoms of each element in a formula unit of a compound. Since atoms are so tiny, we will learn to use large groups of atoms—moles of atoms—to ease our calculations. We will learn to calculate the percent by mass of each element in the compound. We will learn how to calculate the simplest formula from percent composition data, and to calculate molecular formulas from simplest formulas and molecular weights. The procedure for writing formulas from names or from knowledge of the elements involved will be presented in Chaps. 5. ft. and 13. [Pg.58]

Obtain the two unknowns from your instructor. One will have an identifying number, and the other will have an identifying letter. For the one identified by a number, obtain its molecular formula from your instructor. Record all information. [Pg.235]

Rather, look for evidence of the presence or absence of a few common functional groups with very characteristic absorptions. Start with OH, C=O, and NH groups in Figure 2.7 since a yes/no answer is usually available. A yes answer for any of these groups sharpens the focus considerably. Certainly the answer will contribute to development of a molecular formula from the mass spectrum (Chapter 1) and to an entry point for the NMR spectra (Chapters 3-6). These other spectra, in turn, will suggest further leads in the IR spectrum. [Pg.82]

If a high-resolution mass spectrum is not available, it is still possible to obtain information about the molecular formula from the low-resolution spectrum. In the mass spectrum of benzene, shown in Figure 15.5, the molecular ion appears at mlz 78. In addition, there is a smaller peak at mlz 79, called the M + 1 peak, that is 6.8% of the intensity of the Mt peak. The M + 2 peak, at mlz 80, is 0.2% of the Mt peak. The M + 1 and M + 2 peaks are caused by the presence of isotopic atoms of heavier mass in some of the molecules. Their intensities relative to the Mt peak can be used to deduce information about the formula. Let s look at how these peaks arise in more detail. [Pg.620]

Empirical and molecular formulas from experimental data... [Pg.8]

Q Calculate empirical and molecular formulas from elemental compositions. [Pg.34]

To determine the molecular formula from percent composition and molecular mass data or from the empirical formula and molecular mass data... [Pg.196]

A differeut method may be used to calculate the molecular formula from perceut compositiou data plus a molar mass First, calculate the mass of each elemeut iu 1.00 mol of compouud. Next, calculate the uumber of moles of each of the elemeuts iu the mole of compouud. Those results yield the molecular formula. Use this method to calculate the molecular formula of a hydro-carbou (a compouud of carbou aud hydrogen only) that contains 87.73% C and has a molar mass of 82.0 g/mol. [Pg.217]

To calculate the properties of each gas in a mixture of gases To calculate molar masses from mass data along with pressure, volume, temperature data, and to use the molar masses thus calculated to enable calculation of molecular formulas from empirical formulas... [Pg.327]

Formulas describe the composition of compounds. Empirical formulas give the mole ratio of the various elements. However, sometimes different compounds have the same ratio of moles of atoms of the same elements. For example, acetylene, C2H2, and benzene, CeHe, each have 1 1 ratios of moles of carbon atoms to moles of hydrogen atoms. That is, each has an empirical formula CH. Such compounds have the same percent compositions. However, they do not have the same number of atoms in each molecule. The molecular formula is a formula that gives all the information that the empirical formula gives (the mole ratios of the various elements) plus the information of how many atoms are in each molecule. In order to deduce molecular formulas from experimental data, the percent composition and the molar mass are usually determined. The molar mass may be determined experimentally in several ways, one of which will be described in Chap. 12. [Pg.108]

Once we know a compound s molecular formula from its mass spectral data and the identity of its functional group from its IR spectrum, we can then use its H NMR spectrum to determine its structure. A suggested procedure is illustrated for compound X, whose molecular formula (C4Hjj02) and functional group (C=0) were determined in Section 13.7. [Pg.517]

Determining a Molecular Formula from an Empirical Formula... [Pg.263]

For more practice calculating a molecular formula from percent composition, go to Supplemental Practice Problems in Appendix A. [Pg.335]

The steps in determining empirical and molecular formulas from percent composition or mass data are outlined below. As in other calculations, the route leads from mass through moles because formulas are based on the relative numbers of moles of elements in each mole of compound. [Pg.337]

The ratio of the amount of carbon to that of chlorine (or hydrogen) is 0.8992 1.349 = 0.6666, which is close to 2 3. The numbers of moles form the ratio 2 3 3 therefore, the empirical formula is C2H3CI3. Additional measurements would be necessary to find the actual molecular mass and the correct molecular formula from among C2H3CI3, C4HgClg, or any higher multiples (C2H3Cl3) . [Pg.36]

The first piece of information we try to get is the molecular formula from the mass spectral formula weight and the percent composition from a combustion analysis if available. If we don t have a molecular formula, we can still get a minimum count on the number of carbons and hydrogens from the NMR spectra, which will be discussed later. [Pg.393]

Empirical and molecular formulas from experimental data Molar masses from gas density, freezing-point, and boiling-point measurements... [Pg.5]

The most simple filters are calculated directly from the molecular formula, from the element composition, or from an extended description of the atom types of a molecule. Extended atom types are notations of atoms that include more information than just the element name (e.g., level of hybridization, membership in a certain functional group, etc.). Many molecular properties are usable as filter descriptors [24-27]. [Pg.571]

Figure 18.2 Pregi method of microanalysis. Generations of students will recall having calculated, with anxiety, molecular formulae from the masses of carbon dioxide and water trapped in the removable absorbers. In a more recent version, the reaction gases pass over copper powder to reduce the nitrogen oxides to nitrogen. Three thermal conductivity detectors (TCD) signal the presence of HjO, COj and Nj. The measurement of the three requires elements require around 10 minutes. Figure 18.2 Pregi method of microanalysis. Generations of students will recall having calculated, with anxiety, molecular formulae from the masses of carbon dioxide and water trapped in the removable absorbers. In a more recent version, the reaction gases pass over copper powder to reduce the nitrogen oxides to nitrogen. Three thermal conductivity detectors (TCD) signal the presence of HjO, COj and Nj. The measurement of the three requires elements require around 10 minutes.
The following plperl function will compute a molecular formula from an input SMILES. [Pg.118]

The following two examples deal with writing molecular formulas from molecular models and writing empirical formnlas from molecular formulas. [Pg.51]


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