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Chlorine molar mass

A compound XC13 is 70.3% (by mass) chlorine. What is the molar mass of the compound What is the symbol and name of X ... [Pg.69]

There are two naturally occurring isotopes of chlorine chlorine-35 and chlorine-37. The mass of an atom of chlorine-35 is 5.807 X 10-23 g and that of an atom of chlorine-37 is 6.139 X 10-23 g. In a typical natural sample of chlorine, 75.77% of the sample is chlorine-35 and 24.23% is chlorine-37. What is the molar mass of a typical sample of chlorine ... [Pg.65]

E.30 The isotope silicon-28 has been proposed as a new standard for the molar masses of elements because it can be prepared to a very high degree of purity. The mass of one silicon-28 atom is 4.64567 X 10-23 g. If silicon were the standard used for molar mass (instead of carbon-12), 1 mol would be defined as the amount of substance that contains the same number of entities as there are atoms in exactly 28 g of silicon-28. In that case, what would be (a) the molar mass of carbon-12 (b) the (average) molar mass of chlorine ... [Pg.70]

M.3 Polychlorinated biphenyls (PCBs) were once widely used industrial chemicals but were found to pose a risk to health and the environment. PCBs contain only carbon, hydrogen, and chlorine. Aroclor 1254 is a PCB with molar mass 360.88 g-mol. Combustion of 1.52 g of Aroclor 1254 produced 2.224 g of CO, and combustion of 2.53 g produced 0.2530 g of H20. How many chlorine atoms does an Aroclor 1254 molecule contain ... [Pg.123]

The high-temperature contribution of vibrational modes to the molar heat capacity of a solid at constant volume is R for each mode of vibrational motion. Hence, for an atomic solid, the molar heat capacity at constant volume is approximately 3/. (a) The specific heat capacity of a certain atomic solid is 0.392 J-K 1 -g. The chloride of this element (XC12) is 52.7% chlorine by mass. Identify the element, (b) This element crystallizes in a face-centered cubic unit cell and its atomic radius is 128 pm. What is the density of this atomic solid ... [Pg.380]

In certain cases the organic dibasic acid is not sufficiently reactive for the purpose of polymerisation, and so it is replaced either with its anhydride or its acid chloride. For example polyamides (nylons) are often prepared by reaction of the acid chloride with the appropriate diamine. In the spectacular laboratory prepatation of nylon 6,6 this is done by interfacial polymerisation. Hexamethylenediamine is dissolved in water and adipyl chloride in a chlorinated solvent such as tetrachloromethane. The two liquids are added to the same beaker where they form two essentially immiscible layers. At the interface, however, there is limited miscibility and nylon 6,6 of good molar mass forms. It can then be continuously removed by pulling out the interface. [Pg.36]

C03-0126. A 6.82-g sample of a compound that contains silicon and chlorine is 16.53% by mass silicon. The molar mass Is less than 200 g/mol. Determine the molecular formula of the compound. [Pg.195]

C05-0021.A 2.96-g sample of a compound of mercury and chlorine is vaporized in a 1.000-L bulb at 307 °C, and the final pressure is found to be 394 torr. What are the molar mass and chemical formula of the compound ... [Pg.312]

C05-0071. Freons (CFCs) are compounds that contain carbon, chlorine, and fluorine in various proportions. They are used as foaming agents, propellants, and refrigeration fluids. Freons are controversial because of the damage they do to the ozone layer in the stratosphere. A 2.55-g sample of a particular Freon in a 1.50-L bulb at 25.0 °C has a pressure of 262 torr. What is the molar mass and formula of the compound ... [Pg.340]

Mendeleev, a chemist, examined the relative numbers of the atoms of different elements that combine in chemical compounds. In MgCl2, for example, each magnesium atom combines with two chlorine atoms. When he matched combining ability against molar mass, Mendeleev found the same sort of pattern as Lothar Meyer, with Li, Na, K, Rb, and Cs all combining 1 1 with Cl. Thus, each scientist was led to propose a table in which elements are arranged in rows of increasing mass, with breaks so that these five elements fall in the same column. [Pg.521]

Mendeleev also predicted the existence of elements that had not yet been discovered. His arrangement of the then-known elements left some obvious holes in the periodic table. For instance, between zinc (combines with 2 Cl) and arsenic (combines with 5 Cl) were holes for one element that would combine with three chlorine atoms and another that would combine with four. Mendeleev assigned these holes to two new elements. He predicted that one element would have a molar mass of 68 g/mol and chemical properties like those of aluminum, while the other would have a molar mass of 72 g /mol and chemical properties similar to silicon. These elements, gallium (Z = 31, M M = 69.7 g/mol) and germanium (Z = 32, M M — 72.6 g/mol), were discovered within 15 years. Chemists soon verified that gallium resembles aluminum in its chemishy, while germanium resembles silicon, just as Mendeleev had predicted. [Pg.521]

It follows that the molar mass of a typical sample of chlorine atoms is Molar mass of chlorine... [Pg.79]

A highly toxic gas that has been used in chemical warfare gives the following elemental analysis figures 12.1% carbon, 16.2% oxygen, and 71.7% chlorine by mass. Its molar mass is 98.9 g-moU1. Write the Lewis structure of this compound. [Pg.240]

When a 2.36-g sample of phosphorus was burned in chlorine, the product was 10.5 g of a phosphorus chloride. Its vapor took 1.77 times longer to effuse than the same number of moles of C02 under the same conditions of temperature and pressure. What is the molar mass and molecular formula of the phosphorus chloride ... [Pg.332]

For the initiation by azo initiators only the dependence kp / kt0 5=f ([M]) has to be considered in a kinetic model [10]. Accordingly, an initiator exponent of 0.5 and a monomer exponent of 2 are valid. By adding amine the decomposition velocity of APS is increased by an orders of magnitude. The chain side reactions with the monomer and termination by chlorine atoms are then significantly suppressed which results in a monomer exponent of 2 and higher molar masses of the homopolymer [11]. The kinetics of 2.3 order in monomer and 0.47 order in initiation [59], explained by partial cyclization and termination of cyclized radicals, could not be confirmed. [Pg.139]

With the MMAO-activated catalyst system Nd( OPr)3/MMAO/halide donor a unique dependence of molar mass on the ratio of ftci/ Nd was obtained. Molar mass steadily decreases with increasing nci/nN(j-ratios (between 0.5 to 2.0) regardless of the type of chlorine source (Et2AlCl, fBuCl and Me3SiCl) [231]. [Pg.44]

For the whole cl/ Nd range studied ( ci/ Ndv = 2 to 5) BR with a bimodal distribution is obtained with the catalyst system Nd(N(SiMe3)2)3/TIBA/ DEAC. The bimodality of the polymer is attributed to two active centers. Contrary to the previous studies a larger fraction of the high molar mass BR is found at low chlorine contents ( ci/ Nd = 2) [318]. [Pg.45]

Molar masses of chemical compounds are equal to the sums of the molar masses of all the atoms in one molecule of that compound. If we have a chemical compound like NaCI, the molar mass will be equal to the molar mass of one atom of sodium plus the molar mass of one atom of chlorine. If we write this as a calculation, it looks like this ... [Pg.203]

If you have a subscript in a chemical formula, then you multiply the number of atoms of anything next to that subscript by the number of the subscript. For most compounds, this is easy. For example, in iron (II) chloride, or FeCh, you have one atom of iron and two atoms of chlorine. The molar mass will be equal to (1 atom x 56 grams/mole Fe) + (2 atoms x 35.5 grams/mole of chlorine) = 127 grams/mole of iron (II) chloride. [Pg.204]

By combining these ideas, Avogadro related the volume of a gas to the amount that is present (calculated from the mass). Avogadro divided Dalton s mass ratios by the molar masses of the elements to obtain the mole ratios. He realized that these mole ratios were the same as the volume ratios that Gay-Lussac had obtained. For example, 1 L of hydrogen gas reacts with 1 L of chlorine gas. Avogadro decided that there must be the same number of molecules in each litre of gas. Thus, Avogadro s hypothesis was formulated Equal volumes of all ideal gases at the same temperature and pressure contain the same number of molecules. [Pg.473]

Percent composition, also called percent by mass, is a useful piece of data to obtain when looking at the composition of certain substances. In percent composition problems you are asked to find the percent of the mass of an element in a compound as compared to the molar mass of the compound. A simple ratio will suffice and the result is multiplied by 100%. For CaCl2, for example, what percent of this compound is made up of chlorine The total mass is... [Pg.108]

Selective radical bromination of the p-methyl group by elemental bromine is performed in solution either thermally, photolytically, or in the presence of radical initiators. The reaction does not lead to any change in molar mass or distribution, and the only potential side reaction, which has to be controlled by adjusting the reaction conditions, is debromination between two p-bromobenzyl moieties. Under similar conditions radical chlorination leads to substitution on the benzylic site as well as on the methylene and methyl groups of isobutene units, with changes in molar mass. [Pg.702]

Analysis of a compound containing chlorine and lead reveals that the compound is 59.37% lead. The molar mass of the compound is 349.0 g/mol. What is the empirical formula for the chloride What is the molecular formula ... [Pg.349]

When 2.60 g of a substance that contains only indium and chlorine is dissolved in 50.0 g of tin(IV) chloride, the normal boiling point of the tin(IV) chloride is raised from 114.1°C to 116.3°C. If Ki, = 9.43 K kg mol for SnCU, what are the approximate molar mass and the probable molecular formula of the solute ... [Pg.479]

You may also want to know the mass of PGI3 that can be produced in the reaction of 1.45 g of phosphorus with the required mass of chlorine (4.98 g) when the reaction goes to completion, that is, when all of at least one of the reactants has been used completely. Because matter is conserved, the answer can be obtained by adding the masses of P4 and Gig used (giving 1.45 g + 4.98 g = 6.43 g of PGlg produced). Alternatively, Steps 3 and 4 can be repeated, but with the appropriate stoichiometric factor and molar mass. [Pg.1154]

Suppose you have 100.0 g of the unknown compormd. Because you know the sample includes 18.8 g of sodium, 29.0 g of chlorine, and 52.2 g of oxygen, use the molar mass to find the number of moles of each element. [Pg.427]

Note that although calcium and chlorine exist here as ions, the formula mass is the sum of the atomic masses. For this reason, calcium and chlorine are shown as atoms when adding the atomic masses of the ions. The formula mass in grams is the molar mass of CaCl2, 110.98 g. [Pg.119]


See other pages where Chlorine molar mass is mentioned: [Pg.80]    [Pg.80]    [Pg.536]    [Pg.72]    [Pg.88]    [Pg.66]    [Pg.180]    [Pg.196]    [Pg.111]    [Pg.15]    [Pg.238]    [Pg.536]    [Pg.59]    [Pg.111]    [Pg.989]    [Pg.990]    [Pg.992]    [Pg.365]    [Pg.302]    [Pg.374]    [Pg.114]   
See also in sourсe #XX -- [ Pg.3 , Pg.94 ]

See also in sourсe #XX -- [ Pg.3 , Pg.94 ]

See also in sourсe #XX -- [ Pg.90 ]




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