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Charge and Mass Balances

Difficult equilibrium problems can be tackled by writing all the relevant chemical equilibria plus two more equations the balances of charge and mass. We now examine these two conditions. [Pg.266]

Solutions must have zero total charge. [Pg.266]

The charge balance is an algebraic statement of electroneutrality The sum of the positive charges in solution equals the sum of the negative charges in solution. [Pg.266]

Suppose that a solution contains the following ionic species H , OH , H2PO4, HP04, and PO . The charge balance is [Pg.266]

Equation 12-8 appears unbalanced to many people. The right side of the equation has much more charge than the left side you might think. But you would be wrong. [Pg.266]


To summarize, the equation for a nuclear reaction is balanced when the total charge and total mass number of the products equals the total charge and total mass number of the reactants. This conservation requirement is one reason why the symbol for any nuclide includes its charge number (Z) as a subscript and its mass number as a superscript. These features provide a convenient way to keep track of charge and mass balances. Notice that in the equation for neutron decay, the sum of the subscripts for reactants equals the sum of the subscripts for products. Likewise, the sum of the superscripts for reactants equals the sum of the superscripts for products. We demonstrate how to balance equations for other reactions as they are introduced. [Pg.1564]

Ernest Rutherford was the first person to observe a binuclear reaction, hi 1919, he exposed a sample of nitrogen to a particles from a naturally radioactive source. He observed the production of protons and deduced from the requirements of charge and mass balance that the other product was oxygen-17 ... [Pg.1574]

If we introduce the monomer-complexation by means of equation (1) and write the new charge and mass balances as... [Pg.333]

Consider the sodium nltrate/goethite suspension titrated in the presence and absence of lead ion. The following equations governing the titrations are easily derived from the charge and mass balance equations ... [Pg.136]

The direction of a reaction can be assessed straightforwardly by comparing the equilibrium constant (Keq) and the ratio of the product solubility to the substrate solubility (Zsat) [39]. In the case of the zwitterionic product amoxicillin, the ratio of the equilibrium constant and the saturated mass action ratio for the formation of the antibiotic was evaluated [40]. It was found that, at every pH, Zsat (the ratio of solubilities, called Rs in that paper) was about one order of magnitude greater in value than the experimental equilibrium constant (Zsat > Keq), and hence product precipitation was not expected and also not observed experimentally in a reaction with suspended substrates. The pH profile of all the compounds involved in the reaction (the activated acyl substrate, the free acid by-product, the antibiotic nucleus, and the product) could be predicted with reasonable accuracy, based only on charge and mass balance equations in combination with enzyme kinetic parameters [40]. [Pg.296]

Now that we have considered the charge and mass balances, we are ready for the systematic treatment of equilibrium.10 Here is the general prescription ... [Pg.150]

Both [CaOH ) and [HS04 ] are 105 times less than rCa2+] and [SO ], so it was reasonable to neglect [CaOH+] and [HS04 ] in the charge and mass balances. [Pg.153]

G. Write the charge and mass balances for dissolving CaF2 in water if the reactions are... [Pg.155]

H. Write charge and mass balances for aqueous Ca3(P04)2 if the species are Ca2+ CaOH % CaP04, PO HPO, H2P04, andH3P04. [Pg.155]

State the meaning of the charge and mass balance equations. [Pg.155]

The general treatment of acid-base systems begins with charge and mass balances and equilibrium expressions. There should be as many independent equations as chemical species. Substitute a frac-... [Pg.265]

Ionization of the oxide/water interface and the resultant electrical double layer have been studied intensively by a variety of techniques within the last decade. Although many electrical double layer and adsorption models have been proposed, few are sufficiently general to consider surface equilibria in complex electrolyte solutions. Recently we proposed a comprehensive adsorption model for the oxide/water interface which can simultaneously estimate adsorption density, surface charge, and electro-kinetic potential in a self-consistent manner (jL, 2, 3). One advantage of the model was that it could be incorporated within the computer program, MINEQL ( ), by adding charge and mass-balance equations for the surface. [Pg.299]

A schematic representation of the system is given in Figure 14.8. In this case, the output quantities are the current Yi = I and the mass Ya = M. In addition to the charge and mass balances the equation governing the change of mass can be established... [Pg.283]

G. Decher, Science, 1997, 277, 1232 J.B. Schlenoff, H. Ly and M. Li, Charge and mass balance in polyelectrolyte multilayers, J. Am. Chem. Soc., 1998, 120, 7626-7634 I. Ichinose, S. Mizuki, S. Ohno, H. Shiraishi and T. Kunitake, Preparation of cross-linked ultrathin films based on layer-by-layer assembly polymers, Polym. J. 1999,31, 1065-1070. [Pg.80]

C NOTE THAT LINEAR CHARGE AND MASS BALANCE EQUATIONS ARE ASSIGNED FIRST ROW... [Pg.560]

The numerical integration of the mass conservation equations consists basically in a time-iterative method with two sequential steps for each increment of time. In the first one, the transport of ions between each cell is calculated, yielding transient concentrations that are used in the second one, where the chemical equilibria and charge and mass balance equations are solved within each volume element. The first corresponds to the transport phenomena term in the differential conservation equation of each species, and the second corresponds to the rates of production of ions in those same equations. In this way, the model obtains new values that are used to perform the integration forward in time. [Pg.542]

For example, iron(II) can be determined by titration with dichromate, so combination of the appropriate half-reactions [VII] and [XIII], so as to achieve a charge and mass balance, gives the overall reaction [XVI] ... [Pg.4853]

As we shall see for every kind of solution, pH calculations are, as a rule, always possible from a purely mathematical point of view. Indeed, the expressions of equilibria and those of charge and mass balances are always required to provide the same number of equations as the number of unknowns. However, the resulting polynomial equations may be difficult to solve because their order is higher than 2 in the existing unknown. Then numerical calculations may be made. Additionally, they can be performed with pocket calculators. Another way is to make approximations, which greatly simplify the solution of the problem (see below) in Eqs. (5.5) and (5.6), no parameter is characteristic of some particular acid, provided it is strong. The result is that every strongly acidic solution exhibits the same pH value for the same analytical concentration in the above Eqs. (5.1), (5.3), and (5.4), we have not set up... [Pg.79]

The general relation permitting the pH calculation is found by expressing the water ion product and the charge and mass balances of the solution. If C is the analytical concentration of the base, the following system of equations holds ... [Pg.81]

The pH can be caleulated rigorously by taking into account all the relations that must be satisfied (charge and mass balances, equilibrium dissociation constants, water ion product). The resulting equation, however, is difficult to solve. An approximation of the resulting equation consists of neglecting the concentrations [H3O+] and [OH ] in the charge balance relation. It results then in... [Pg.93]

Before solving this system, note that it differs from the previous one by the presence of sodium ions in the charge and mass balances. Solving this system is difficult. An approximation can be done under some conditions. It results from the fact that the intermediary species can be considered as resulting from the reaction of the diacid H2 A with the base A , the two species being at the same concentration, according to... [Pg.95]

Example 1 Let s consider a mixture of ammonia and acetic acid in aqueous solution, at the respective analytical concentrations 5 x 10 mol/L and 2 x 10 mol/L. The system of the necessarily satisfied relations (water ion product, charge and mass balances, equilibrium ionization constants) can be reduced to only one equation, which is of the fourth order in [H3O+]. It is difficult to solve it quickly. Calculations are made considerably easier by applying the concept under study. The first step is the search for the preponderance area of the different species. It is made by drawing the acidity scale (Fig. 5.7). [Pg.101]

Vs(s) does not appear, since ao (s) is, strictly speaking, the activity of the building element (0" — Vg) and also contains configurational effects with respect to Vs(s). Neither do electrical effects occur, since we refer to the same position x=s (i.e. 0(x=s) cancels out). Since both Eq. (5.252) and the charge and mass balances refer to concentrations, we must, as already mentioned, derive activity coefficients from the surface core model. [Pg.236]


See other pages where Charge and Mass Balances is mentioned: [Pg.154]    [Pg.156]    [Pg.929]    [Pg.154]    [Pg.405]    [Pg.288]    [Pg.929]    [Pg.7074]    [Pg.116]    [Pg.63]    [Pg.361]    [Pg.904]    [Pg.581]    [Pg.266]    [Pg.267]    [Pg.580]    [Pg.349]    [Pg.272]    [Pg.400]    [Pg.104]    [Pg.289]    [Pg.340]    [Pg.443]   


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