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Binomial distribution standard deviation

Few populations, however, meet the conditions for a true binomial distribution. Real populations normally contain more than two types of particles, with the analyte present at several levels of concentration. Nevertheless, many well-mixed populations, in which the population s composition is homogeneous on the scale at which we sample, approximate binomial sampling statistics. Under these conditions the following relationship between the mass of a randomly collected grab sample, m, and the percent relative standard deviation for sampling, R, is often valid. ... [Pg.188]

The applicability of the Poisson distribution to counting statistics can be proved directly that is, without reference to binomial theorem or Gaussian distribution. See J. L. Doob, Stochastic Processes, page 398. The standard deviation of a Poisson distribution is always the square root of its mean. [Pg.271]

If n particles are drawn at random, the expected number of particles of type A is np and the standard deviation of many drawings is known from the binomial distribution to be... [Pg.646]

Transformation based on square root from data X = /X is applied when the test values and variances are proportional as in Poisson s distribution. If the data come from counting up and the number of units is below 10 transformation form X --fX + 1 and text X =s/X + /X I 1 is used. If the test averages and their standard deviations are approximately proportional, we use the logarithm transformation X =log X. If there are data with low values or they have a zero value, we use X =log (X+l). When the squares of arithmetical averages and standard deviations are proportional we use the reciprocal transformation X =l/X or X =1/(X+1) if the values are small or are equal to zero. The transformation arc sin [X is used when values are given as proportions and when the distribution is Binomial. If the test value of the experiment is zero then instead of it we take the value l/(4n), and when it is 1, l-l/(4n) is taken as the value and n is the number of values. Transforming values where the proportion varies between 0.30 and 0.70 is practically senseless. This transformation is done by means of special tables suited for the purpose. [Pg.114]

To check that the method can be used for isobaric data a set of perfect data are generated and random errors added to x, y, T, and tt in turn and all together to see what effect they have on our standard procedure. For large samples we expect 68% of the sample values to lie within one standard deviation of the perfect value of the selected variable. In the case of small samples, e.g., twelve data, error bounds are calculated using binomial probabilities for each of the above variables so that, with probability of 0.95, we expect 41-95% of the sample observations to lie within one standard deviation of the perfect value of the selected variable (the normal distribution is assumed). Twelve is a common number of data points with salt-saturated solutions and this shows the desirability of taking more experimental observations. [Pg.50]

For the 1500 buret readings sampled, the expected frequency F, is 150 in each class, with the assumption of no number bias. The calculated value of is 23,952/150 = 160, a value that at 9 degrees of freedom (the number of classes minus 1) lies far above the 99.9 percentile probability level and indicates pronounced number bias. The bias in this case is for small numbers and against large ones (a common type of bias for this type of reading). Another indication of number bias is obtained by comparing the observed standard deviation s = V23,952/9 = 52 with that calculated from the binomial distribution (Section 27-3) s = Vnp(l — p), which for n = 1500, p = 0.1, and 1 — p = 0.9 gives s = 2 for 10 equal classes of probability 0.1. [Pg.547]

For example, a substructure occurs 17.7 % in the whole data set, i.e. p = 0.177. In the subset of 33 active compounds (n = 33), 5.84 compounds (0.177 x 33) are expected to have this substructure, assuming that it has nothing to do with activity. This number is assumed as the mean of the binomial distribution, with a standard deviation equal to 2.19. If the actual number of compounds containing the considered substructure is 11, the number of standard deviations away from the mean is ... [Pg.214]

Both the binomial and Poisson distributions apply to discrete variables, whereas most of the random variables involved in experiments are continuous. In addition, the use of discrete distributions necessitates the use of long or infinite series for the calculation of such parameters as the mean and the standard deviation (see Eqs. 2.47, 2.48, 2.52, 2.53). It would be desirable, therefore, to have a pdf that applies to continuous variables. Such a distribution is the normal or Gaussian distribution. [Pg.39]

Given these assumptions, the distribution of the observed total number of counts according to probability theory should be binomial with parameters N and p. Because p is so small, this binomial distribution is approximated very well by the Poisson distribution with parameter Np, which has a mean of Np, and a standard deviation of Np. The mean and variance of a Poisson distribution are numerically equal so, a single counting measurement provides an estimate of the mean of the distribution Np and its square root is an estimate of the standard deviation /Np. When this Poisson approximation is valid, one may estimate the standard uncertainty of the counting measurement without repeating the measurement (a Type B evaluation of uncertainty). [Pg.199]

Although all the assumptions stated above are needed to ensure that the distribution of the total count is binomial, not all the assumptions are needed to ensure that the Poisson approximation is valid. In particular, if the source contains several long-lived radionuclides, or if long-lived radionuclides are present in the background, but all atoms decay and produce counts independently of each other, and no atom can produce more than one count, then the Poisson approximation is still useful, and the standard deviation of the total count is approximately the square root of the mean. [Pg.199]

If the above expression is expanded according to the binomial theorem, the distribution of the probabilities obtained from the expansion is known as the binomial distribution. According to elementary statistics, as n becomes larger, the binomial distribution approaches the normal distribution. Since work sampling studies involve large sample sizes, the normal distribution is a satisfactory approximation of the binomial distribution. Rather than use the binomial distribution, it is more convenient to use the distribution of a proportion, with a mean p and a standard deviation of /pq/n as the approximately normally distributed random variable. [Pg.1449]

One can easily recognize the exponential law of radioactive decay in the above formula. The correspondence (N)(f) N means that the exponential law applies to the expected number of atoms rather than to the concrete numbers that are measured. The latter show a fluctuation about those expectations according to the standard deviation of the binomial distribution... [Pg.423]

The table is arranged in terms of the product, Np, where N is the sample size and p is the fixed probability for the entire population. For this distribution Np = p. = c, i.e., both the mean and the variance are equal to Np. The standard deviation is a =. yi. Values in the body of the table represent the cumulative probability of X or more successes in N trials (the same as for the binomial table) or in sampling, the values represent the probability of X or more acceptances in sample of N items. In either case the fixed probabihty for the whole population is p. [Pg.608]

As in the underlying binomial distribution, There is the mean value of x and is equal to np where n is the number of trials. The variance of a Poisson distribution also is np, as you can see by letting the factor (1 — p) in Eq. (5.78) go to 1. The standard deviation from the mean of a Poisson distribution (rr) thus is the square root of the mean. [Pg.275]

Example 12 (continued) Suppose we want to find the predictive distribution for 30-day survival of a 60-year old male patient who does not have shock or renal failure and is given a stent. Let the draws of the intercept, the slope coefficient for age, the slope coefficient for male, and the slope coefficient for stent be in columns cl, c2, c3, and c6, respectively. We let column c8 equal draws for the linear predictor for that male. Then we let column c9 draws from the exponential of c8 divided by one plus the exponential of c8 for that male. Then we let c 10 be a random draw from a binomial(l, clO). Each observation has its own success probability that is its value in cIO. The summary statistics for the 2000 draws from the predictive distribution are mean. 9615 and standard deviation. 19245. [Pg.199]

In statistics, the binomial distribution describes the number of successes that occur in m independent trials, when the probability of success in each trial is the same. In our case, the m independent trials correspond to the m noninteracting systems success of a trial corresponds to the double excitation of the electrons in a system, each of which occurs with the probability IVd-According to the theory of binomial distributions, the average number of double excitations (i.e. the average number of successes in m trials) and the standard deviation in the number of double excitations are given as... [Pg.17]

For np > 5 and n( 1 - p) > 5, an approximation of binomial probabilities is given by the standard normal distribution where z is a standard normal deviate and... [Pg.97]


See other pages where Binomial distribution standard deviation is mentioned: [Pg.2825]    [Pg.759]    [Pg.31]    [Pg.869]    [Pg.11]    [Pg.64]    [Pg.31]    [Pg.570]    [Pg.214]    [Pg.103]    [Pg.287]    [Pg.663]    [Pg.262]    [Pg.2825]    [Pg.72]    [Pg.9]    [Pg.119]    [Pg.39]    [Pg.120]    [Pg.156]    [Pg.55]    [Pg.275]    [Pg.20]    [Pg.147]   
See also in sourсe #XX -- [ Pg.37 ]




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