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Steady-state kinetic treatment of enzyme catalysis

2 Steady-state kinetic treatment of enzyme catalysis [Pg.336]

The steady-state rate equation is obtained according to following rules (King and Altman method) if no loop is involved  [Pg.336]

The free enzyme, E binds to A (first substrate) to form binary complex, EA which then interacts with B (second substrate) to form ternary complex, EAB. The two ternary complexes EAB and EPQ interconvert. The release of P (first product) forms EQ which then dissociates to E and Q (second product) in an ordered sequence, kj 10 are rate constants. [Pg.336]

Write down all possible basic pattern with n - 1 lines (n = number of enzyme forms i.e. enzyme-containing species), in which all lines are connected without closed loops e.g.  [Pg.337]

Write a distribution equation for each enzyme form, e.g., E/Eo = Ne/D where Ne and D are the numerator (for E) and denominator terms respectively. [Pg.337]


See also in sourсe #XX -- [ Pg.336 ]




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