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Molar balances oxygen

Rogers defines the system according to Figure 2. He sets up elementary molar balances with respect to carbon, hydrogen, oxygen, nitrogen, and helium. The nomenclature adopted in this thesis is used to present Rogers mathematical models. [Pg.54]

The slowest timescale, by several orders of magnitude, is for the diffusive motion of liquid in the lateral direction within the membrane, Tmem = Idy = 8.3 X 10 s. On this slow timescale, we take the gas mole fractions Cy,Co, and Ay at steady-state, driven adiabatically by the changing water flux into the plenums. The well-stirred gas plenums are assumed to have constant pressure and inlet flow rates. On the cathode side the inlet gas is pure oxygen. The total molar concentration Cr, nondimensionalized by the saturation pressure Cs t T), is a constant of space and time and equals the molar concentration of the inlet gases. This yields the molar balance... [Pg.281]

CO2 changes oxygen molar balance equation (B.16). It becomes ... [Pg.390]

Stoichiometry in Reactive Systems. The use of molar units is preferred in chemical process calculations since the stoichiometry of a chemical reaction is always interpreted in terms of the number of molecules or number of moles. A stoichiometric equation is a balanced representation that indicates the relative proportions in which the reactants and products partake in a given reaction. For example, the following stoichiometric equation represents the combustion of propane in oxygen ... [Pg.334]

One molecule (or mole) of propane reacts with five molecules (or moles) of oxygen to produce three molecules (or moles) or carbon dioxide and four molecules (or moles) of water. These numbers are called stoichiometric coefficients (v.) of the reaction and are shown below each reactant and product in the equation. In a stoichiometrically balanced equation, the total number of atoms of each constituent element in the reactants must be the same as that in the products. Thus, there are three atoms of C, eight atoms of H, and ten atoms of O on either side of the equation. This indicates that the compositions expressed in gram-atoms of elements remain unaltered during a chemical reaction. This is a consequence of the principle of conservation of mass applied to an isolated reactive system. It is also true that the combined mass of reactants is always equal to the combined mass of products in a chemical reaction, but the same is not generally valid for the total number of moles. To achieve equality on a molar basis, the sum of the stoichiometric coefficients for the reactants must equal the sum of v. for the products. Definitions of certain terms bearing relevance to reactive systems will follow next. [Pg.334]

P, with the remainder oxygen. The mass spectrum of compound B yields a molar mass of 97.99 g-mol. Write the molecular formula of compound B. (c) Compound B reacts with an aqueous solution of calcium hydroxide to form compound C, a white precipitate. Write balanced chemical equations for the reactions in parts (a), (b), and (c). [Pg.101]

This experiment tells us that the products of the reaction, C02(g) and 2 H20(g), have 802 kj less internal energy than the reactants, CH4(y) and 2 02(g), even though we don t know the exact values at the beginning (Einitial) and end (Efinai) of the reaction. Note that the value AE = -802 kj for the reaction refers to the energy released when reactants are converted to products in the molar amounts represented by coefficients in the balanced equation. That is, 802 kj is released when 1 mol of methane reacts with 2 mol of oxygen. [Pg.301]

The value of the enthalpy change AH reported for a reaction is the amount of heat released or absorbed when reactants are converted to products at the same temperature and in the molar amounts represented by coefficients in the balanced equation. In the combustion reaction of propane discussed in the previous section, for instance, the reaction of 1 mol of propane gas with 5 mol of oxygen gas to give 3 mol of C02 gas and 4 mol of water vapor releases 2043 kj. The actual amount of heat released in a specific reaction, however, depends on the actual amounts of reactants. Thus, reaction of 0.5000 mol of propane with 2.500 mol of 02 releases 0.5000 X 2043 kj = 1022 kj. [Pg.306]

Unaccounted-for reactants involved in addition reaction(s) to the parent compound. Consider reactants from matrix (oxygen, excipients, container ingredients). Compare molar mass balance to weight mass balance i.e., molar mass balance may be more appropriate in this case. [Pg.194]

The reactor was operated in the co-current mode. The feed for methanol steam reforming was composed of 37.7% methanol, 45.3% water and balance argon. The feed for methanol combustion was composed of 10% methanol, 18.9% oxygen and 71.1% nitrogen. For the steam reforming reaction side, a H20/CH30H molar ratio of 1.2 was fed to the reactor. [Pg.368]

The reaction product of ytterbium metal with benzophenone in a 1 1 molar ratio could be determined by an X-ray structure [278]. The benzophenone dianion unsymmetrically bridges the ytterbium atoms in the HMPA solvate [Yb(OCPh2)2(HMPA)2]2. The aryl oxygen forms a Yb-O bond with a typical terminal bond length (Table 18), but also donates to the other ytterbium. A Yb-C a-bond involving the a-C-atom (2.59(5) A) balances the charge at Yb (II). Reaction of the dianionic complex with four equivalents of phenol HOC6H3tBu2-2,6-Me-4 afforded the mononuclear aryloxide complex Yb(OAr)2(HMPA)2 (Sect. 4.2) [72],... [Pg.222]

This is how we know how to balance chemical equations and work out the masses reacting together, because we know that equal molar masses contain the same numbers of particles. In a chemical equation like C + 02 —> C02, we always know that there will be one mole of carbon atoms reacting with one mole of oxygen molecules (02) to give one mole of carbon dioxide. Providing the chemical equation balances, any fraction of moles will also be true. One-tenth of a mole of carbon will require one-tenth of a mole of oxygen gas molecules (02), to make one-tenth of a mole of carbon dioxide gas (C02). [Pg.228]

The steady state molar oxygen balance for the segment is ... [Pg.134]

After substituting Equations 3.1.2 and 3.1.3 into Equation 3.1.1, the oxygen mole balance reduces to Equation 3.1.4 in Table 3.1.1. Because Equation 3.1.4 is an unsteady-state, first-order differential equation, we need an initial condition to calculate the constant of integration. Initially, the tank contains air, which has an oxygen concentration of approximately 21 % by volume. We could also write the mole balance for nitrogen, but in this case it is more convenient to write the total mole balance, which results in Equation 3.1.5. Once we write Equations 3.1.4 to 3.1.6, the nitrogen mole balance is not an independent equation. Equation 3.1.7 states that the molar flow rate is equal to the product of the molar density and the volmnetric flow rate. [Pg.108]

In theory, gasification processes can be designed so that the exothermic and endothermic reactions are thermally balanced. For example, consider reactions 2 and 5. The feed rates could be controlled so that the heat released balances the heat requirement. In this hypothetical case, the amount of oxygen required is 0.27 mol/mol of carbon, the amount of steam required is 0.45 mol/ mol of carbon, and the oxygen-to-steam molar ratio is 0.6 ... [Pg.277]

From the balanced chemical equation, you know that 2 mol of butane reacts with 13 mol of oxygen, producing 8 mol of carbon dioxide and 10 mol of water vapor. By examining this balanced equation, you are able to find mole ratios of substances in this reaction. Avogadro s principle states that equal volumes of gases at the same temperature and pressure contain equal numbers of particles. Thus, when gases are involved, the coefficients in a balanced chemical equation represent not only molar amounts but also relative volumes. For example, if 2 L of butane reacts, the reaction involves 13 L of oxygen and produces 8 L of carbon dioxide and 10 L of water vapor. [Pg.440]


See other pages where Molar balances oxygen is mentioned: [Pg.133]    [Pg.134]    [Pg.312]    [Pg.314]    [Pg.133]    [Pg.134]    [Pg.312]    [Pg.314]    [Pg.133]    [Pg.134]    [Pg.312]    [Pg.314]    [Pg.139]    [Pg.139]    [Pg.392]    [Pg.468]    [Pg.71]    [Pg.544]    [Pg.146]    [Pg.176]    [Pg.373]    [Pg.288]    [Pg.313]    [Pg.286]    [Pg.184]    [Pg.567]    [Pg.203]    [Pg.1583]    [Pg.234]   
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