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Millimole 1/1000 mole

As the molecular weight of H2SO4 is 98.078 it follows that 1 kg contains 10.196 mol hence the predominant ions are present to the extent of about 1 millimole per mole of H2SO4 and the total concentration of species in equilibrium with the parent acid is 4.16 millimole per mole. Many of the physical and chemical properties of anhydrous H2SO4 as a nonaqueous solvent stem from these equilibria. [Pg.711]

We first determine [Mg2+], and then determine the value of in order to compare it to the value of Ksp. We express molarity in millimoles per milliliter, entirely equivalent to moles per liter. [Pg.469]

For instance, surfactants dissolve in water and give rise to low surface tension even at very low concentrations (a few grams per liter or 1-100 mmol/L) of the solution therefore, these substances are also called surface-active molecules (surface-active agents or substances). On the other hand, most inorganic salts increase the surface tension of water. All surfactant molecules are amphiphilic, which means that these molecules exhibit hydrophilic and hydrophobic properties. Ethanol reduces the surface tension of water, but one will need over a few moles per liter to obtain the same reduction as when using a few millimoles of surface-active agents. [Pg.40]

The concentration of ozone taken up by the media containing linolenic acid is plotted against time after addition in Figure 8. The rate of ozone breakdown is constant (ozone uptake linear with time) for the first two min until about 0.12 ml ozone are absorbed and then the rate decreases sharply, reaching a steady-state rate of ozone uptake between 10-12 min. This first break in the curve corresponds to an ozone uptake of 0.12 ml + (24 moles/liter) = 0.005 millimoles (or 10 M). This is equivalent to 1 mole of linolenic acid added per mole ozone absorbed. Thiobarbituric acid reactant production is also plotted on the same axis. This compound (TBA reactant) probably arises by formation of a three-carbon fragment (malondialdehyde) from the ozone-induced oxidation of linolenic acid (23). The rate of TBA reactant formation is also linear for the first 2 min at which point the curve undergoes a less pronounced break. Malondialdehyde formation ceases immediately when the ozone is shut off (Scrub 1 on). An oxygen control sample produced no malondialdehyde. [Pg.68]

The general scheme for preparation in the laboratory has a number of alternatives, the choice of a particular method being determined by the availability of the starting acetylene, r CsCH, the desired scale of the preparation (e.g. a few millimoles, 100 mmolar, 1 molar or more) and a number of other factors. The most versatile method, suitable for working on scales varying from a few mmoles to -0.5 mole, is the reaction of a lithium alkynylide with a carbonyl compound in THF(-hexane) ... [Pg.79]

Figure 9A. Reflection spectra of 0.1 M octahedral AgBr (Dispersion C of Reference 23) in 0.3% gelatin at 23°C., pBr 3, pH 6.5 with added 5,5 -dichloro-3,3 -9-triethul-thiacarbocyanine bromide in millimoles per mole AgBr... Figure 9A. Reflection spectra of 0.1 M octahedral AgBr (Dispersion C of Reference 23) in 0.3% gelatin at 23°C., pBr 3, pH 6.5 with added 5,5 -dichloro-3,3 -9-triethul-thiacarbocyanine bromide in millimoles per mole AgBr...
The results were plotted as millimoles of hydrogen chloride evolved as a function of time and the shape of the curve, and the time required for HC1 evolution representing 0.1 mole % (0.058 wt % ) decomposition of the poly (vinyl chloride) was noted. [Pg.316]

The results in Table X reveal that hydrotreating under the reaction conditions and catalyst specified in Table I reduced the moles of azaanthracenes and azaphenanthrenes by ca. 83%. However, it is important to note that the decrease of 6.7 millimoles in reactants (mass 179) essentially equals, within the limits of data precision, the increase of 6.3 millimoles in products (masses 181 through 189). Consequently, for the given catalyst, the reaction conditions were insufficiently severe to convert intermediate products to hydrocarbons and NH. ... [Pg.63]

Number of moles = (number of liters) x (molar concentration) or Number of millimoles = (number of milliliters) x (molar concentration)... [Pg.212]

As indicated in Table 1-1, grams may be converted to milligrams and moles can be converted to millimoles simply by multiplying each of the appropriate values by 103. For example, 0.025 mol of a molecule is equal to 25 mmol ... [Pg.5]

Examples 2 moles of water implies n(H20) = 2 mol 0.5 moles of sodium chloride implies w(NaCl) = 0.5 mol 3 millimoles of iron implies n(Fe) = 3 mmol, but such statements should be avoided whenever there might be ambiguity. [Pg.46]

The relative amounts of reactants and products involved in a reaction maybe the ratio of moles, millimoles, or masses. [Pg.37]

Millimoles of solute Definition of miUi- / Moles of solute... [Pg.304]

Note that the number of millimoles per milliliter is equal to the number of moles per liter, and thus millimoles per milliliter is another way to define molarity. This equivalent definition makes many problems easier because quantities used in chemical laboratories are often measured in millimoles and milliliters. [Pg.305]

If quantities of solute and solution are given in units other than moles and liters or millimoles and milliliters, respectively, they can be changed to one of these sets of units to calculate the molarity. [Pg.305]

Because molarity is a ratio, like speed and density, it can be used as a conversion factor. Wherever it appears, the symbol M can be replaced by the ratio moles per liter (mol/L) or millimoles per milliliter (mmol/mL). For example, a concentration of 3.11 M can be used as any of the following factors ... [Pg.305]

Molarity may also be defined as the number of millimoles per milliliter of solution (but not the number of moles per milliliter of solution or the number of millimoles per liter of solution). [Pg.311]

We can now calculate the concentration of the HCl solution. The volume of NaOH solution used is the difference between the initial and final buret readings. The concentration of NaOH is known, and thus the number of millimoles (or moles) of NaOH can be calculated. From the way a titration is run and the fact that the mole ratio of HCl to NaOH in the balanced equation is 1 1, the number of millimoles of HCl is equal to the number of millimoles of NaOH. The concentration of the HCl solution is calculated by dividing that number of millimoles by the number of milliliters of the HCl solution. [Pg.317]

The concentration of a solute depends on the quantities of both the solute and the solution (or solvent). Molarity is defined as the number of moles of solute per liter of solution. Molarity is calculated by dividing the number of moles of solute by the volume of the solution in liters, or alternatively, by dividing the number of millimoles of solute by the milliliters of solution. Because molarity is a ratio, it can be used as a conversion factor to change the volume of solution into the number of moles of solute, or vice versa. [Pg.321]

Note moles per liter or millimoles per milliliter, not moles per milliliter)... [Pg.167]

It must be emphasized that such stoichiometric stability constants are dependent, inter alia, upon the ionic strength of the solution, and, in reporting experimental results, the ionic strength of the experimental solutions should always be specified. Further, the numerical value of a stoichiometric constant will depend upon the units used, viz. mole fractions, molar, molal, millimole, and so on, and which is used should always be made clear. [Pg.4547]

To compute [H+] at a given point in the titration, we must determine the moles of H+ remaining at that point and divide by the total volume of the solution. Before we proceed, we need to consider a new unit, which is especially convenient for titrations. Since titrations usually involve small quantities (burets are typically graduated in milliliters), the mole is inconveniently large. Therefore, we will use the millimole (abbreviated mmol), where... [Pg.294]

A 1.0 M solution thus contains 1.0 mole of solute per liter of solution oi equivalently, 1.0 millimole of solute per milliliter of solution. Just as we obtain the number of moles of solute from the product of the volume in liters and the molarity, we obtain the number of millimoles of solute from the product of the volume in milliliters and the molarity. [Pg.294]


See other pages where Millimole 1/1000 mole is mentioned: [Pg.427]    [Pg.393]    [Pg.648]    [Pg.269]    [Pg.412]    [Pg.256]    [Pg.590]    [Pg.219]    [Pg.326]    [Pg.330]    [Pg.14]    [Pg.190]    [Pg.191]    [Pg.803]    [Pg.324]    [Pg.33]    [Pg.73]    [Pg.40]    [Pg.219]    [Pg.33]    [Pg.191]    [Pg.197]    [Pg.198]    [Pg.6]    [Pg.48]    [Pg.304]    [Pg.305]   
See also in sourсe #XX -- [ Pg.377 , Pg.393 ]




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