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Kinetic collisions radius

On the other hand, if the rate constant for the quenching step exceeds that expected for a diffusion-controlled process, a modification of the parameters in the Debye equation is indicated. Either the diffusion coefficient D as given by the Stokes-Einstein equation is not applicable because the bulk viscosity is different from the microviscosity experienced, by the quencher (e.g. quenching of aromatic hydrocarbons by O, in paraffin solvents) or the encounter radius RAb is much greater than the gas-kinetic collision radius. In the latter case a long-range quenching... [Pg.173]

Modern gas-diffusion medium in low-temperature fuel cells is typically a highly porous carbon paper with porosity in the range of sgdl = 0.6-0.8 and with the mean pore radius in the order of 10 pm (10 cm). By the order of magnitude, the mean free path of molecules in atmospheric pressure air is = l/(A LO-fci ), where Nl = 2.686 10 cm is the Loschmidt number (number of molecules in a cubic centimetre of atmospheric pressure gas at standard temperature) and akin — 10 cm is the molecular cross-section for kinetic collisions. With this data we get 3 10 cm, or 3 10 pm. Obviously, mean pore radius in the GDL is nearly 3 orders of magnitude greater than I f and the physical mechanism of molecule transport is binary molecular diffusion. [Pg.24]

It is clear that the collision between two elastic but frictional spheres is inelastic due to the inevitable sliding at contact which yields the kinetic energy loss by frictional work. Furthermore, the preceding analyses of both Hertzian collision and frictional collision can also be applied to the particle-wall collision, where the radius of the wall is simply set to be infinitely large. [Pg.76]

For simplicity, it is assumed that the impact is a Hertzian collision. Thus, no kinetic energy loss occurs during the impact. The problem of conductive heat transfer due to the elastic collision of solid spheres was defined and solved by Sun and Chen (1988). In this problem, considering the heat conduction through the contact surface as shown in Fig. 4.1, the change of the contact area or radius of the circular area of contact with respect to time is given by Eq. (2.139) or by Fig. 2.16. In cylindrical coordinates, the heat conduction between the colliding solids can be written by... [Pg.133]

As in the kinetic theory of gases, a selected molecule is represented as a collision sphere of radius equal to the sum of the radii of the colliding molecules. The neighbors with which it collides are mass points. The uncorrected frequency of collision is given by the usual equation of the kinetic theory of gases ... [Pg.156]

As long as the particle radius is small so that the term 2r/7rA, is much smaller than unity, the molecules collide with particles at gas-kinetic rates. For larger particles, when 2r/ir t> 1, the collision rate becomes diffusion-controlled and increases with r rather than with r2. Setting approximately A, = Aair, one finds that the boundary between the two regimes lies near 0.1 p.m radius. [Pg.294]

In some cases P/j may be obtained experimentally from low-density gas-phase determinations of vibrational relaxation rates (although sometimes it is necessary to extrapolate downward to liquid state temperatures). At low densities (t ) can be obtained from gas kinetic theory collisional cross-sections once a radius has been chosen, while t, can be found experimentally. Their ratio gives P j, the transition probabihty per collision. Purely theoretical calculations of P j can be carried out in principle using quantum scattering theory, although this becomes difficult for molecules of even moderate size. A number of semiclassical procedures have been proposed among the most popular is the SSH model, which gives ... [Pg.489]

Excitation events can be used to increase the kinetic energy of ions, or to eject ions of a given mass-to-charge ratio from the cell by increasing the orbital radius until ions are lost by collisions with the cell plates. The background pressure of an... [Pg.341]

One of the assumptions of the kinetic molecular theory is that the volume of a gas particle is negligible. If this were the case, the ratio of the number of collisions of gas particles with the walls of the container compared to the number of collisions a given gas particle experiences with other gas particles should be quite high. Determine the volume of a cube (in L) filled with helium such that the ratio of the number of collisions of helium atoms with the container walls to the number of inter-molecular collisions for a given helium atom is 1 quin-tillion (1 quintillion = 1.00 X 10 ). The atomic radius of helium is 3.2 X 10 m. [Pg.193]

The assertion that gas molecules occupy no volume may seem at odds with reality because we know that all matter occupies space. What is actually implied by this postulate The essential idea is that, compared to the volume of empty space between particles, the volume of the particles themselves is not significant. One way to assess the validity of this assertion is to define the mean free path of the particles. The mean free path is the average distance a particle travels between collisions with other particles. In air at room temperature and atmospheric pressure, the mean free path is about 70 nm, a value 200 times larger than the typical radius of a small molecule like N2 or O2. (For comparison, the molecules in a liquid typically have a mean free path roughly the same as a molecular radius.) When we consider the cubic relationship of volume to distance, the difference in volume is on the order of 200 or 8 x 10. So the volume of empty space in a gas at room tem-peramre and pressure is on the order of 1 million times greater than the volume of the individual molecules the assumption in the kinetic theory that the volume of the molecules is negligible seems reasonable under these conditions. [Pg.180]


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Collision radius

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