Big Chemical Encyclopedia

Chemical substances, components, reactions, process design ...

Articles Figures Tables About

Independent increments

There are many ways we could assign probability distribution functions to the increments N(t + sk) — N(t + tk) and simultaneously satisfy the independent increment requirement expressed by Eq. (3-237) however, if we require a few additional properties, it is possible to show that the only possible probability density assignment is the Poisson process assignment defined by Eq. (3-231). One example of such additional requirements is the following50... [Pg.168]

In other words, if we assume that the counting function N(t) has statistically independent increments (Eq. (3-237)), and has the property that the probability of a single jump occurring in a small interval of length h is approximately nh but the probability of more than one jump is zero to within terms of order h, (Eq. (3-238)), then it can be shown 51 that its probability density functions must be given by Eq. (3-231). It is the existence of theorems of this type that accounts for the great... [Pg.168]

Exercise. Write the M-equation for processes with independent increments, defined in (IV.4.7), and solve it. Using this solution show again that Pi becomes asymptotically Gaussian. [Pg.100]

Exercise. Let Y0 be the Wiener process and Yt, Y2,..., Yr random walks with different step sizes and transition probabilities. Show that Y0 + Yx + Y2 + + Yr is a process with independent increments, see (IV.4.7), and find its transition probability. [Pg.139]

Exercise. Consider the process with independent increments defined in (IV.4.7), whose M-equation was solved in an Exercise of V.l. Investigate how the Fokker-Planck approximation modifies the general solution. Conclude that for P(y, t y0,t0) the approximation is bad when t — t0[Pg.199]

It has the form (IV.4.8), as it should. The coefficients are the rm that characterized the A. Vice versa, it is now possible to construct a white noise process by taking any process with independent increments and differentiating it its rm are given by (6.4). [Pg.238]

Exercise. The Poisson process (IV.2.6) has independent increments. Show that it gives rise to a white noise with Tm = 1 for all ra. [Pg.238]

A process with independent increments can be generated by compounding Poisson processes in the following way. Take a random set of dots on the time axis forming shot noise as in (II.3.14) the density fx will now be called p. Define a process Z(t) by stipulating that, at each dot, Z jumps by an amount z (positive or negative), which is random with probability density w(z). Clearly the increment of Z between t and t + T is independent of previous history and its probability distribution has the form (IV.4.7). It is easy to compute. [Pg.238]

We have only shown that a compound Poisson process is at the same time a process with independent increments. The converse is proved in feller ii, p. 204. [Pg.239]

Differentiating the latter expression for parameter l/vj (reciprocal to the reaction rate) with respect to independent increment Akj in view of expression (4.76) and setting the derivative to zero gives the equation on optimal Akj ... [Pg.224]

The enormous complexity of spectra of large biomolecules such as proteins, polynucleotides, and polysaccharides has led to the development of three- and four-dimensional experiments. Two independently incremented evolution periods (t and t2), in conjunction with three separate Fourier transformations of them and of the acquisition period, result in a cube of data with three frequency coordinates. [Pg.201]

In passing we remark that Feller [218] replaces the process X = R, X2 = X + R.2, X3 = X2 + R3, . . with independent increments Rj by the Markov chain [X1.X2.X2. and calls this process pseudo-Poissonian. [Pg.259]

If 21(f) is a Markov process with continuous transition probabilities and T(t) a process with non-negative independent increments, then X(T(t)) is also a Markov process. Thus, this process is subordinated to 21(f) with operational time T(t). The process 7 (f) is called a directing (controlling) process. [Pg.259]

When the process 21(f) has independent increments, we again arrive at the above formula for p x,t). In particular, if 21(f) is Brownian motion with... [Pg.259]

Note that a renewal process with transition probability q(t), which is not necessarily a process with independent increments, can also be chosen as the controlling process (T(f). ... [Pg.260]

Such models of the one dimensional random walk of a particle with expectation times distributed independently according to the same pausing time law q(t) and independent increments (both from each other and from the expectation times) distributed with equal density p(x) are, as we have seen, are called Continuous-Time Random Walks. [Pg.260]

In this regime the typical distance from the origin of motion increases as the square root of time. Thus, the dispersion in turbulent flows at long times is analogous to molecular diffusion or random walks with independent increments and comparison of Eq. (2.24) with (2.16) relates the turbulent diffusion coefficient, Dt, to the integral of the Lagrangian correlation function, Tl, as... [Pg.27]

Vol, 1865 D. Applebaum, B.V. R. Bhat, J. Kustermans, J, M, Lindsay, Quantum Independent Increment Processes I, From Classical Probability to Quantum Stochastic Calculus. Editors M. Schtlrmann, U. Franz (2005) Vol, 1866 O.E. Barndorff-Nielsen, U. Franz, R. Gohm,... [Pg.466]

It should be noted that we integrate with respect to the forward variable y in (3.236). In this case, (3.236) has a very nice probabilistic interpretation. Consider the Brownian motion B t), which is a stochastic process with independent increments, such that B(t + s) - B(s) is normally distributed with zero mean and variance 2Dt. The corresponding transition probability density function p y, t x) is given by (3.237). Therefore the solution (3.236) has a probabilistic representation... [Pg.102]

This means that the number of the truly independent increments is only n. Let us try to exploit that. To this end, let us multiply Eq. (N.3) by a number , (Lagrange multiplier). [Pg.1174]

We initiate the random walk with Xq = 0. The quantity J is a random variable drawn from a certain probability distribution. In the classic model of a random walk the jump takes values 1 with equal probability. The increments of the random walk are the differences AX = X — X i = 8xi -, thus (X ) is a random process with independent increments. [Pg.225]

Adding more independent incremental delays to the pulse sequence followed by corresponding Fourier transformation steps leads to further increases in frequency dimensionality to yield 3D NMR, 4D NMR, and so on. A number of 3D and 4D experiments have found use, particularly in the assignment of the complex spectra that arise from proteins and carbohydrates. [Pg.3395]

The Poisson process counts the number of occurrences of events that are occurring randomly through time and have independent increments. This means that what happens (the occurrence or non-occurrence of events) in time intervals that do not overlap are independent of each other. While the events themselves are occurring at random times, the intensity rate at which they are occurring is constant. This means... [Pg.68]

What happens in one time interval is independent of what happens in another non-overlapping time interval, independent increments)... [Pg.69]

Zero occurrences. First we look at the case for zero occurrences of the event in the interval. Since there are independent increments... [Pg.97]


See other pages where Independent increments is mentioned: [Pg.318]    [Pg.89]    [Pg.238]    [Pg.238]    [Pg.239]    [Pg.29]    [Pg.210]    [Pg.449]    [Pg.152]    [Pg.298]    [Pg.132]    [Pg.1]    [Pg.86]    [Pg.1258]    [Pg.488]    [Pg.545]    [Pg.612]    [Pg.763]    [Pg.1282]    [Pg.1282]    [Pg.2370]    [Pg.1992]   
See also in sourсe #XX -- [ Pg.89 , Pg.139 , Pg.199 , Pg.238 ]




SEARCH



Incremental

Incrementalism

Increments

© 2024 chempedia.info