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Equilibrium ratio K

Tn energy and environmental-related technology it is often necessary to remove trace amounts of nonhydrocarbon polar solutes such as water and mercaptans from hydrocarbon streams. While equations of state have played a very important role in the correlation of phase equilibrium (K-ratios) of nonpolar and slightly polar mixtures, much less attention has been given to an equation of state for the more difficult problem of polar mixtures. [Pg.238]

The vapor-liquid equilibrium K-ratio can be calculated via the fugacity coefficients from an equation of state as a function of temperature, pressure, and compositions of liquid and vapor mixtures. [Pg.239]

Phase-equilibrium (K-ratio) data also can be used to determine the polar energy parameter. Equations 4 and 15 are used to calculate the phase equilibrium K-ratio and the parameter AP(TC) that fits the experimental data is chosen. [Pg.241]

A mass balance determines the equilibrium composition of vapor and liquid which are used to calculate a new set of equilibrium K-ratios. These steps are repeated until the K-ratios and the vaporized fraction do not vary. The tolerance of the function f(V/F), set to less than 10"4, was sufficient for most cases. [Pg.242]

H = enthalpy, calories per gram k = adjustable binary parameter K = vapor-liquid equilibrium K-ratio P = pressure, atmosphere R — gas constant, 0.08206 atmosphere liter/K T = temperature, K x, y = mole fraction in liquid and vapor V = molar volume, cubic centimeters per gram-mole v = vapor, gram-mole z = mole fraction of feed... [Pg.253]

In principle, if an estimate could be made of K, the equilibrium concentration ratio of hydrated to anhydrous cations, relation (15) would enable the approximate pA of the anhydrous species to be calculated. Although such an estimate may be derivable from absorption spectral data, no such calculation appears to have been reported. Conversely, if an upper estimate of pA is made from the (pAa)eqm value for the corresponding, appropriately methyl-substituted base, Eq. (15) can be used to furnish a lower limit to the extent of hydration in the cation. Taking quinazoline as an example ... [Pg.59]

The ratio of equilibrium K-values for two components measures their relative volatility ... [Pg.61]

The equilibrium condition for the distribution of one solute between two liquid phases is conveniently considered in terms of the distribution law. Thus, at equilibrium, the ratio of the concentrations of the solute in the two phases is given by CE/CR = K, where K1 is the distribution constant. This relation will apply accurately only if both solvents are immiscible, and if there is no association or dissociation of the solute. If the solute forms molecules of different molecular weights, then the distribution law holds for each molecular species. Where the concentrations are small, the distribution law usually holds provided no chemical reaction occurs. [Pg.725]

In Figure 9, the proportions of Fe(II)aq, Fe(III)aq, and Fe(OH)3(s) over time are illustrated, as well as the residence time of Fe(III)aq, as calculated using Equations (6)-(ll), and the rate for ki from Figure 8. The time required to reach steady-state conditions in terms of the Fe(III)aq/ Fe(II)aq ratio is, of course, dependent upon the k k ratio, and varies from 2 hours for kjki = 50, to 20 hours for kJki = 5 (Fig. 9). It is important to note, however, that attainment of isotopic equilibrium between Fe(II)jtime required to reach steady-state in terms of the concentration or molar ratios of Fe in various species, because is... [Pg.331]

K values. Equilibrium vaporization ratios or K values are widely used, particularly in the petroleum industry. [Pg.36]

Schiff s base formation occurs by condensation of the free amine base with aldehyde A in EtOAc/MeOff. The free amine base solution of glycine methyl ester in methanol is generated from the corresponding hydrochloride and triethylamine. Table 4 shows the reaction concentration profiles at 20-25°C. The Schiffs base formation is second order with respect to both the aldehyde and glycine ester. The equilibrium constant (ratio k(forward)/ k(reverse)) is calculated to be 67. [Pg.27]

Figures 1 to 3 present calculated equilibrium molar ratios of products to reactants as a function of temperature and total pressure of 1 and 100 atm. for the gas-carbon reactions (4), (7), and (5), (6), (4), (7), respectively. Up to 100 atm. over the temperature range involved, the fugacity coefficients of the gases are close to 1 therefore, pressures can be calculated directly from the equilibrium constant. From Fig. 1, it is seen that at temperatures above 1200°K. and at atmospheric pressure, the conversion of carbon dioxide to carbon monoxide by the reaction C - - COj 2CO essentially is unrestricted by equilibrium considerations. At elevated pressures, the possible conversion markedly decreases hence, high pressure has little utility for this reaction, since increased reaction rate can easily be obtained by increasing reaction temperature. On the other hand, for the reaction C -t- 2H2 CH4, the production of methane is seriously limited at one atmosphere pressure and practical operating temperatures, as seen in Fig. 2. Obviously, this reaction must be conducted at elevated pressures to realize a satisfactory yield of methane. For the carbon-steam reaction. Figures 1 to 3 present calculated equilibrium molar ratios of products to reactants as a function of temperature and total pressure of 1 and 100 atm. for the gas-carbon reactions (4), (7), and (5), (6), (4), (7), respectively. Up to 100 atm. over the temperature range involved, the fugacity coefficients of the gases are close to 1 therefore, pressures can be calculated directly from the equilibrium constant. From Fig. 1, it is seen that at temperatures above 1200°K. and at atmospheric pressure, the conversion of carbon dioxide to carbon monoxide by the reaction C - - COj 2CO essentially is unrestricted by equilibrium considerations. At elevated pressures, the possible conversion markedly decreases hence, high pressure has little utility for this reaction, since increased reaction rate can easily be obtained by increasing reaction temperature. On the other hand, for the reaction C -t- 2H2 CH4, the production of methane is seriously limited at one atmosphere pressure and practical operating temperatures, as seen in Fig. 2. Obviously, this reaction must be conducted at elevated pressures to realize a satisfactory yield of methane. For the carbon-steam reaction.
The Hammond Postulate applies only if both forward reactions are fast. Obtain energies for the transition states leading to 1 -propyl and 2-propyl radicals (propane+F end andpropane+F center). Draw an energy diagram for each hydrogen abstraction reaction (place the diagrams on the same axes). Do these diagrams indicate that use of the Hammond Postulate is justified Calculate the barrier for each reaction, and calculate the relative concentrations of 1-propyl and 2-propyl radicals that would form at 298 K if each reaction were irreversible. Use equation (2). How does this (kinetic) ratio compare to the equilibrium (thermodynamic) ratio of these radicals ... [Pg.41]

A hydrocarbon feed gas is to be treated in an existing four-theoretical-tray absorber to remove butane and heavier components. The recovery specification for the key component, butane, is 75 percent. The composition of the exit gas from the absorber and the required liquid-to-gas ratio are to be estimated. The feed-gas composition and the equilibrium K values for each component at the temperature of the (solute-free) lean oil are presented in the following table ... [Pg.19]

K represents the balance between products and starting materials in a system at equilibrium. K is the ratio of the molar concentrations of products divided by the molar concentrations of the starting materials, each raised to the power of their stoichiometric coefficients. As K increases, the reaction becomes increasingly product-favored. [Pg.401]

Examples of such kinetic treatments were provided by work on chiral 1,1,2,2-tetramethylcyclopropane-dg and rra 5 -l-ethyl-2-methylcyclopropane . At 350.2 °C, the first substrate approached cis, trans equilibrium with rate constant A , and suffered loss of optical activity with a rate constant k The ki k ratio was 1.7 P . The second substituted cyclopropane, at 377.2 °C, exhibited kinetic behavior dictated by kf.k = 2.0 1. Using steady-state kinetic treatments and the most-substituted-bond hypothesis, these rate constant ratios were calculationally transformed into / (cyclization) (rotation) ratios of 11 1 and 0.29 1, ratios different by a factor of 38. [Pg.480]

This means that the cis-trans selectivity depends solely on the difference between the free standard enthalpies AGg - AGf of the transition states for the insertion reaction with the anti and the syn form of the polybutadienyl cw-butadiene complex e and f, respectively, independently of their concentration ratio in the anti-syn equilibrium K. To explain the cis-trans selectivity of 93 % cis and 4 % trans attributed to the ligand-free allylnickel(II) cation, a stability difference between the transition states of about 1.9 kcal mol (8 kJ mof ) must be assumed, which can easily arise from the different steric conditions for the necessary coordination of the next double bond in the anti and the syn forms e and f of the catalyst complex. [Pg.303]


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Equilibrium ratios

K-ratios

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