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Equilibrium equation for

Develop equilibrium equations for the reactive absorption of CO2 into ... [Pg.207]

The equilibrium equations for a beam are derived to illustrate the derivation process and to serve as a review in preparation for addressing plates. Then, the plate equilibrium equations are derived for use in Chapter 5. Next, the plate buckling equations are discussed. Finally, the plate vibration equations are addressed. In each case, the pertinent boundary conditions are displayed. Nowhere in this appendix is reference needed to laminated beams or plates. All that is derived herein is applicable to any kind of beam or plate because only fundamental equilibrium, buckling, or vibration concepts are used. [Pg.495]

This review of the foregoing simple derivation will help you to understand the following derivation of the plate equilibrium equations. The major difference between plate and beam problems is that beams are one-dimensional and plates are two-dimensional. Therefore, beams have ordinary differential equations as governing equations whereas plates have partial differential equations. Moreover, in the derivation of the governing differential equations, there will necessarily be more force equilibrium and moment equilibrium equations for plates than for beams. [Pg.498]

Using the equilibrium equations for the system, this equation becomes... [Pg.53]

This forms eight vertices of a cube (see Figure 3.12). The equilibrium equations for the various species are... [Pg.57]

In the deduction of the Law of Mass Action it was assumed that the effective concentrations or active masses of the components could be expressed by the stoichiometric concentrations. According to thermodynamics, this is not strictly true. The rigorous equilibrium equation for, say, a binary electrolyte ... [Pg.23]

The equilibrium equation for the first step is shown in Scheme 5-2. Introducing the equilibrium constant Kw of water (Kw = [H+][0H ]/[H20] leads to the equation shown in Scheme 5-3. ATW can be combined with the constant K (defined by Kx = K[KW) to give the equation of Scheme 5-4. In the same way, the second step can be expressed as in Scheme 5-5. [Pg.89]

The first procedure is to use the rate equilibrium equations for electrons and ions at the quasi-steady state for a new guess of the particle densities. In the final result, quasi-steady balances of the positive ions and negative ions integrated over... [Pg.74]

EXAMPLE 20.1. Write an equilibrium equation for the reaction of NH, and H 0. and label each of the conjugate acids and bases. [Pg.302]

Step 1 Write the equilibrium equation for the dissociation of lead iodide. [Pg.166]

For the description of a pure quark phase inside the neutron star, as for neutrino-free baryonic matter, the equilibrium equations for the chemical potentials,... [Pg.128]

When damping is ignored, the three forces then acting on the mass are the resistance (K y), (he inertia force (M a), and the external applied force (Ft), The dynamic equilibrium equation for the undamped, clastic system then becomes,... [Pg.40]

Responses of MDOF systems are determined from the solution of the following dynamic equilibrium equation. This equation is the matrix form of the equilibrium equation for a SDOF system (Equation 6 t). [Pg.47]

A brief summary will be given of the Newmark numerical integration procedure, which is commonly used to obtain the time history response for nonlinear SDOF systems. It is most commonly used with either constant-average or linear acceleration approximations within the time step. An incremental solution is obtained by solving the dynamic equilibrium equation for the displacement at each time step. Results of previous time steps and the current time step are used with recurrence formulas to predict the acceleration and velocity at the current time step. In some cases, a total equilibrium approach (Paz 1991) is used to solve for the acceleration at the current time step. [Pg.180]

The two complexation equilibrium equations for the left and right complexation/decomplexation equilibria are (4) and (5) respectively. [Pg.4]

Values of and pK and the relevant equilibrium equations for a variety of weak acids are given on p. 13 of the SQA Data Booklet. [Pg.36]

As the salt solution has a pH >7, it is the salt of a weak acid and strong base. The strong base is KOH and, as it is fully ionised, we cannot write an equilibrium equation for its dissociation. [Pg.104]

Propanoic acid is the weak acid and the equilibrium equation for its dissociation is CHjCH COOHjaq) CH3CH2COO-(aq) + H"(aq)... [Pg.104]

Such a mechanism is a form of substrate-induced activation. If all of the binding steps are rapid relative to the ESA-to-EPA interconversion step, the initial-rate rapid-equilibrium equation for this scheme is... [Pg.26]

Of course, the equilibrium constant Km the latter equation does not have the same value as the ATin the equilibrium equation for ammonia. The numerical value of ATdepends on the particular reaction, the temperature, and the units used to describe concentration. For liquid solutions, the concentrations are usually expressed as molarity. For a mixture of gases, the concentration of each molecular species is commonly given either as molarity or as pressure in atmospheres. [Pg.132]

B. The Henderson-Hasselbalch equation is derived from the rearrangement of the equilibrium equation for dissociation of a weak acid. [Pg.3]

The kinetic model may be formulated using kinetic equations for all steps or using equilibrium equations for all but the slowest steps. The latter approach reduces the computational effort and leads to a kinetic expression, which is far easier to analyze. However, if a step, which is slow in reality, is modeled by an equilibrium equation, the micro-kinetic model becomes unrealistic and it may in some cases be the simplest to treat a problematic step by a kinetic equation. [Pg.84]

Next, let us consider the dependence of carrier concentration on for Bi- or Ag-doped PbS. This problem is related to the method of controlled valency, developed by Verwey and Kroger and Vink. It is assumed, as observed, that Bi substitutes for Pb in the crystal and acts as a donor. The equilibrium equations for this case are the six independent ones, eqn (1.204) to eqn (1.211), which describe the chemical equilibrium in pure PbS, and the following two equations ... [Pg.91]

The corresponding mass-action equilibrium equation for this reaction is... [Pg.201]

Estimation of the Ideal Values for d In c/d(r2) and dc/d . For the nonideal case we can use Equations 1-4 and 6 to obtain the basic sedimentation equilibrium equation for component i. In the Fujita notation (17) this equation is... [Pg.256]

Analysis of Mixed Associations from Conventional Sedimentation Equilibrium Experiments. In these experiments one measures a quantity Mieq (14, 28) instead of Mweq. The basic sedimentation equilibrium equation for each reactant is... [Pg.278]

The equilibrium constant Kc is the number obtained by multiplying the equilibrium concentrations of all the products and dividing by the product of the equilibrium concentrations of all the reactants, with the concentration of each substance raised to the power of its coefficient in the balanced chemical equation. No matter what the individual equilibrium concentrations may be in a particular experiment, the equilibrium constant for a reaction at a particular temperature always has the same value. Thus, the equilibrium equation for the decomposition reaction of N2O4 to give 2 N02 is... [Pg.531]

Write the equilibrium equation for each of the following reactions ... [Pg.532]

PROBLEM 13.1 The oxidation of sulfur dioxide to give sulfur trioxide is an important step in the industrial process for synthesis of sulfuric acid. Write the equilibrium equation for each of the following reactions ... [Pg.533]

Because gas pressures are easily measured, equilibrium equations for gas-phase reactions are often written using partial pressures rather than molar concentrations. For example, the equilibrium equation for the decomposition of N2Oq can be written as... [Pg.534]

When the reaction is carried out in a closed container, three phases are present at equilibrium solid calcium carbonate, solid calcium oxide, and gaseous carbon dioxide. If we were to write the usual equilibrium equation for the reaction, including all the reactants and products, we would have... [Pg.537]

Rearranging the equilibrium equation for the decomposition of CaC03 to combine the constants [CaC03], [CaO], and "K", we obtain... [Pg.537]

In this problem, Kc and all the equilibrium concentrations except one are known, and we re asked to calculate the unknown equilibrium concentration. First, we write the equilibrium equation for the reaction and solve for the unknown concentration ... [Pg.543]

Step 3. Substitute the equilibrium concentrations into the equilibrium equation for the reaction and solve for x. If you must solve a quadratic equation, choose the mathematical solution that makes chemical sense. [Pg.543]


See other pages where Equilibrium equation for is mentioned: [Pg.13]    [Pg.541]    [Pg.282]    [Pg.56]    [Pg.56]    [Pg.265]    [Pg.83]    [Pg.28]    [Pg.500]    [Pg.113]    [Pg.535]    [Pg.535]   
See also in sourсe #XX -- [ Pg.127 ]




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