Big Chemical Encyclopedia

Chemical substances, components, reactions, process design ...

Articles Figures Tables About

Algebra logarithms

We may now take up the routine processes of differentiation. It is convenient to study the different types of functions—algebraic, logarithmic, exponential, and trigonometrical—separately. An algebraic function of x is an expression containing terms which involve only the operations of addition, subtraction, multiplication, division, evolution (root extraction), and involution. For instance, x2y + /x + y -ax = 1 is an algebraic function. Functions that cannot be so expressed are termed transcendental Univ Calif - L sized by Microsoft ... [Pg.35]

This model then leads us through a thicket of statistical and algebraic detail to the satisfying conclusion that going from small solute molecules to polymeric solutes only requires the replacement of mole fractions with volume fractions within the logarithms. Note that the mole fraction weighting factors are unaffected. [Pg.517]

Taking the logarithm of this operator—which is an algebraic function of the kind just mentioned—we have the corresponding eigenvalue relation ... [Pg.470]

If you have done little chemistry before, these pages are for you, too. They contain a brief but systematic summary of the basic concepts and calculations of chemistry that you should know before studying the chapters in the text. You can return to them as needed. If you need to review the mathematics required for chemistry, especially algebra and logarithms, Appendix I has a brief review of the important procedures. [Pg.29]

Figures 4.36 (a) and (b) display the same relaxation data expressed as stress retention, the first with an algebraic time scale showing the fast drop of stress at the start of test and the second with a logarithmic time scale showing a regular decrease of stress. Figures 4.36 (a) and (b) display the same relaxation data expressed as stress retention, the first with an algebraic time scale showing the fast drop of stress at the start of test and the second with a logarithmic time scale showing a regular decrease of stress.
Intrinsic viscosity is related to the relative viscosity via a logarithmic function and to the specific viscosity by a simple algebraic relationship. Both of these functions can be plotted on the same graph, and when the data are extrapolated to zero concentration they both should predict the same intrinsic viscosity. The specific viscosity function has a positive slope and the relative viscosity function has a negative slope, as shown in Fig. 3.7. The molecular weight of the polymer can be determined from the intrinsic viscosity, the intercept of either function, using the Mark-Houwink-Sakurada equation. [Pg.70]

We assume you have a basic facility with algebra and arithmetic. You should know how to solve simple equations for an unknown variable. You should know how to work with exponents and logarithms. That s about it for the math. At no point do we ask you to, say, consider the contradictions between the Schrodinger equation and stochastic wavefunction collapse. [Pg.2]

As was noted in [28] this contribution may be obtained without any calculations at all. It is sufficient to realize that with logarithmic accuracy the characteristic momenta in the leading recoil correction in (10.3) are of order M and, in order to account for the leading logarithmic contribution generated by the polarization insertions, it is sufficient to substitute in (10.5) the running value of a at the muon mass instead of the fine structure a. This algebraic operation immediately reproduces the result above. [Pg.203]

The influence of the boundary layer on sorption kinetics disappears for times t /cnt. Note that Eq. 6 makes sense only if the expression in the logarithm is greater than 1. If this is not the case, then the right-hand side of Eq. 5 is already smaller than the left-hand side when sorption begins. In order to see when this is the case, we rewrite the logarithmic expression by replacing lin by Eq. 19-82 and 5 by Eq. 3 from above. After some algebraic manipulations we get ... [Pg.879]

Two other functions you re likely to encounter are square roots and logarithms. You can review your college algebra book for the nuances of these functions. For our purposes, however, it is more important that you are able to use these functions to generate numerically correct answers. Your calculator should have an x2 button and a Vx button. These operators are inverses of each other. That is, if you enter 10 on your calculator and then press x2, you get 100. Now if you press Vx, you get 10 back. Each operator undoes the effect of the other. [Pg.6]

Chemists use the p-function operator to express the concentrations of many ions. pOH for hydroxide ion, pCa for Ca2+, and so forth. The meaning of the p is the same in every case—take the logarithm of the concentration and then change the algebraic sign. [Pg.233]

Wald proceeds to calculate the contribution of each of his putative receptor spectra to the overall spectra using linear algebra. This subject will be addressed in Section 17.3.3 where it will be compared to the more appropriate (logarithmic) approach. [Pg.104]

In this unit you will find explanations, examples, and practice dealing with the calculations encountered in the chemistry discussed in this book. The types of calculations included here involve conversion factors, metric use, algebraic manipulations, scientific notation, and significant figures. This unit can be used by itself or be incorporated for assistance with individual units. Unless otherwise noted, all answers are rounded to the hundredth place. The calculator used here is a Casio FX-260. Any calculator that has a log (logarithm) key and an exp (exponent) key is sufficient for these chemical calculations. [Pg.237]

To review and summarize While the terms in V and in P do depend on the set of units which is selected, the quantity Sx does likewise, and in such a compensating manner that the algebraic sum in (2.4.10) is independent of the units used in the logarithmic arguments. We have thus arrived at the... [Pg.219]

Hint Solve the molarity ratio first, take its logarithm, multiply by 0.0592, divide by the number of moles of electrons, then subtract that value algebraically from e°. [Pg.471]

The solution of cubic or higher order algebraic equations (or more complicated equations involving sines, cosines, logarithms, or exponentials) becomes more difficult, and approximate or numerical methods must be used. As an illustration, consider the equation... [Pg.979]


See other pages where Algebra logarithms is mentioned: [Pg.430]    [Pg.430]    [Pg.430]    [Pg.430]    [Pg.212]    [Pg.9]    [Pg.42]    [Pg.107]    [Pg.199]    [Pg.80]    [Pg.46]    [Pg.98]    [Pg.663]    [Pg.17]    [Pg.13]    [Pg.108]    [Pg.103]    [Pg.63]    [Pg.187]    [Pg.62]    [Pg.492]    [Pg.114]    [Pg.663]    [Pg.719]    [Pg.108]    [Pg.110]    [Pg.113]    [Pg.663]    [Pg.663]    [Pg.470]    [Pg.107]    [Pg.6]    [Pg.571]    [Pg.4]    [Pg.784]    [Pg.404]   
See also in sourсe #XX -- [ Pg.21 ]




SEARCH



Logarithms

© 2024 chempedia.info