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Variational problems

For consistency we go back to the problem of the twisted cell discussed in Section 8.3.2, however, the director angles cp at the boundaries will be not constant but can be changed due to elastic and external torques. Let a nematic layer be confined by two plane surfaces with coordinates zj = — i/2 and Z2 = +d 2 and the director is allowed to be deviated only in the xy-plane through angle cp (there is no tilt, the angle 9 = ti/2 everywhere, and the azimuthal anchoring energy is finite). [Pg.272]

g is Frank energy density, F 2 are surface energies at opposite boundaries. Our task is to find the equilibrium alignment of the director everywhere between and at the solid surfaces. It is determined by minimization of the integral equation (10.19), i.e. by solution of the correspondent differential Euler equation for the bulk [Pg.272]

The first terms in both Eqs. (10.21) correspond to the craitribution from the bulk to the surface energy. How to understand the influence of the bulk on the surface In fact, the two equations (10.21) represent the balance of elastic and surface torques at each botmdary (indices 1 and 2). One of them comes from the bulk elasticity and deflects the director from the easy axis. The other is a torque from the surface forces that tries to hold the director at its equilibrium (easy) direction. The two equatirais themselves are brought about from the minimization procedure. [Pg.273]

Let show it using mathematics. As was said, the boundary conditions are not fixed and the free energy depends on them. Let tp(z) be a solution of the Euler equation for F(cp) with fixed boundary conditions i.e. Eq. (10.20). Now we shall make variation of the boundary conditions in order to find the minimum of free energy with the surface terms included. [Pg.273]

For example, we can calculate a derivative dF/d pi. If we fix zj, Z2 and (p2 and change only cpi, the new solution for cp(z) will get an increment 8cp(z). Correspondingly the free energy will get an increment AF. Ignoring highest order terms and [Pg.273]


The starting point of this approach is that the 3D restoration is implemented by the solution of the variational problem for the trade-off functional M , which favors in a weighted manner measured data (functional A) and a priori knowledge (functional B) ... [Pg.113]

S is the path length between the points a and b. The Euler equation to this variation problem yields the condition for the reaction path, equation (B3.5.14). A similar method has been proposed by Stacho and Ban [92]. [Pg.2354]

Let us emphasize that not model can be presented as a minimization problem like (1.55) or (1.57). Thus, elastoplastic problems considered in Chapter 5 can be formulated as variational inequalities, but we do not consider any minimization problems in plasticity. In all cases, we have to study variational problems or variational inequalities. It is a principal topic of the following two sections. As for general variational principles in mechanics and physics we refer the reader to (Washizu, 1968 Chernous ko, Banichuk, 1973 Ekeland, Temam, 1976 Telega, 1987 Panagiotopoulos, 1985 Morel, Solimini, 1995). [Pg.22]

Chernous ko F.L., Banichuk N.V. (1973) Variational problems of mechanics and control. Nauka, Moscow (in Russian). [Pg.376]

Ekeland I., Temam R. (1976) Convex analysis and variational problems. North-Holland, Amsterdam, Oxford. [Pg.377]

Prehse J. (1975) Two dimensional variational problems with thin obstacles. Math. Z. 143 (3), 279-288. [Pg.377]

Modern equipment is frequently eomposed of thousands of eomponents, all of whieh interaet within various toleranees. Failures often arise from a eombination of drift eonditions rather than the failure of a speeifie eomponent (Smith, 1993). For example, typieally an assembly toleranee exists only to limit the degradation of the assembly performanee. Being off target may involve later warranty eosts beeause the produet is more likely to break down than one whieh has a performanee eloser to the target value (Vasseur et al., 1992). This again is related to manufaeturing variation problems, and is more diffieult to prediet, and therefore less likely to be foreseen by the designer (Smith, 1993). [Pg.21]

Dreyfus, S.E. (1962) Variational Problems with Inequality Constraints, J. Math. Anal. Appl, 4, p. 297. [Pg.429]

As there is one equation (4.5) for each i, the variational problem is transformed into solving a set of Cl secular equations. Introducing the notation Hjj = ( H ) the matrix equation becomes... [Pg.102]

As illustrated above, even quite small systems at the CISD level results in millions of CSFs. The variational problem is to extract one or possibly a few of the lowest eigenvalues and -veetors of a matrix the size of millions squared. This cannot be done by standard diagonalization methods where all the eigenvalues are found. There are, however, iterative methods for extraeting one, or a few, eigenvalues and -veetors of a large matrix. The Cl problem eq. (4.6) may be written as... [Pg.109]

The variational problem is to minimize the energy of a single Slater determinant by choosing suitable values for the MO coefficients, under the constraint that the MOs remain orthonormal. With cj) being an MO written as a linear combination of the basis functions (atomic orbitals) /, this leads to a set of secular equations, F being the Fock matrix, S the overlap matrix and C containing the MO coefficients (Section 3.5). [Pg.314]

The variational problem may again be formulated as a secular equation, where the coordinate axes are many-electron functions (Slater determinants), <, which are orthogonal (Section 4.2). [Pg.315]

It should be noted that the integral equations [2] determining the elements Kp B. aE derived as an energy-variational problem, correspond also to the stationary condition of the variational functional proposed by Newton (9). Thus the K-matrix elements obeying equation [2] guarantee a stationary value for the K-matrix on the energy shell. [Pg.370]

Due to the size of the variational problem, a large Cl is usually not a practicable method for recovering dynamic correlation. Instead, one usually resorts to some form of treatment based on many-body perturbation theory where an explicit calculation of all off-diagonal Cl matrix elements (and the diagonalization of the matrix) are avoided. For a detailed description of such methods, which is beyond the scope of this review, the reader is referred to appropriate textbooks295. For the present purpose, it suffices to mention two important aspects. [Pg.242]

The 2x2 PMO treatment neglects the numerically comparable interactions with acceptor ctch " and ctc H " orbitals. Thus (unlike He - He), it is numerically nnjustified to consider the 2 x 2 (ctCh, ecu ) secular determinant as a valid approximation to the full (uch, cc H, cch", cch ") variational problem. [Pg.230]

Vol. 1560 T. Bartsch, Topological Methods for Variational Problems with Symmetries. X, 152 pages. 1993. [Pg.208]

A) Simply solve the variational problem and hope to take care of the symmetry restrictions after the energy optimisation ... [Pg.45]

In contrast to the symmetry requirements, the virial theorem is a dynamical requirement and, with the exception of atoms, can only be tested once the solution of the variational problem has been carried through. Or, to be a little more cautious, the imposition of the virial theorem on the form of a model of the molecular electronic structure is not easy. (It should be said at this point that the simple form,... [Pg.48]

If one has determined the operator 7 by a method which does not simultaneously determine the CMO s, then Eq. (26) can be looked upon as a one-electron Schroedinger equation to be solved for the CMO s. In this sense, the Fock operator can be thought of as an effective one-electron hamiltonian. Thus, a one-electron variational problem can be set up namely, we require... [Pg.39]

Assuming uniform prior probabilities, we maximise S subject to these constraints. This is a standard variation problem solved by the use of Lagrangian multipliers. A numerical solution using standard variation methods gives i.p6j=. 05435, 0.07877, 0.11416, 0.16545, 0.23977, 0.34749 with an entropy of 1.61358 natural units. [Pg.339]

The variational Dirac-Coulomb and the corresponding Levy-Leblond problems, in which the large and the small components are treated independently, are analyzed. Close similarities between these two variational problems are emphasized. Several examples in which the so called strong minimax principle is violated are discussed. [Pg.177]

Analysis and Modelling of Atomic and Molecular Kohn-Sham Potentials derivation see [26,27]) the variational problem can be rewritten as... [Pg.111]

Using the definition of the energy functional advanced in Eq. (55), we can state the variational problem leading to El as ... [Pg.201]

In Fig. 7, we present a general scheme, comprising the intra- and inter-orbit optimizations appearing in the variational problem described by Eq. (138). We discuss this optimization process with reference to only three of the infinite number of orbits into which Hilbert space is decomposed. These orbits are... [Pg.204]

C. Garrod and J. Percus, Reduction of iV-particle variational problem. J. Math. Phys. 5, 1756 (1964). [Pg.56]

C. GarrodandJ.K.Percus, Reduction ofV-particle variational problem. 7. MarAPfiyi. 5,1756(1964). [Pg.254]

Fig. 10. Defeclivity observed by the digital image comparison method (a) wafer map showing color variation problem after CMP, and (b) the same wafer using a modified computer algorithm. Fig. 10. Defeclivity observed by the digital image comparison method (a) wafer map showing color variation problem after CMP, and (b) the same wafer using a modified computer algorithm.
Now consider the variation problem with + 1 functions where we have added another of the basis functions to the set. We now have the matrices 7/( +0 and and the new determinantal equation... [Pg.11]

The upshot of these considerations is that a series of matrix solutions of the variation problem, where we add one new function at a time to the basis, will result in a series of eigenvalues in a pattern similar to that shown schematically in Fig. 1.2, and that the order of adding the functions is immaterial. Since we suppose that our ultimate basis n oo) is complete, each of the eigenvalues will become exact as we pass to an infinite basis, and we see that the sequence of -basis solutions converges to the correct answer from above. The rate of convergence at various levels will certainly depend upon the order in which the basis functions are added, but not the ultimate value. [Pg.14]


See other pages where Variational problems is mentioned: [Pg.40]    [Pg.385]    [Pg.85]    [Pg.127]    [Pg.73]    [Pg.69]    [Pg.157]    [Pg.381]    [Pg.190]    [Pg.45]    [Pg.48]    [Pg.48]    [Pg.40]    [Pg.34]    [Pg.162]    [Pg.162]    [Pg.481]    [Pg.229]   


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