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Titration calculations

8-12 appear to give the best results, no single choice of dielectric is appropriate for all pKa calculations. When calculating pKa values, it is best to examine the sensitivity of the results to the choice of dielectric and, if possible, calibrate the dielectric against known pKa values. [Pg.370]

Here are some examples to illustrate stoichiometry calculations in volumetric analysis. The key step is to relate moles of titrant to moles of analyte. We also introduce the Kjeldahl titration as a representative volumetric procedure. [Pg.123]

The calcium content of urine can be determined by the following procedure  [Pg.123]

Step J Precipitate Ca2+ with oxalate in basic solution  [Pg.123]

Step 2 Wash the precipitate with ice-cold water to remove free oxalate, and dissolve the solid in acid to obtain Ca2+ and H2C204 in solution. [Pg.123]

Step 3 Heat the solution to 60°C and titrate the oxalate with standardized potassium permanganate until the purple end point of Reaction 7-1 is observed. [Pg.123]

From the volume of titrant, calculate the number of moles of titrant consumed. [Pg.125]

From the stoichiometry of the titration reaction, relate the unknown moles of analyte to the known moles of titrant. [Pg.125]

Stoichiometry is the ratio of substances participating in a chemical reaction. [Pg.125]

Retain an extra, insignificant digit until the end of the calculations to prevent round-off error. [Pg.126]

Consider the titration of an unknown chloride solution with standard Ag  [Pg.126]


From the results of the titration calculate the millimoles of calcium present in the water. It may be expressed, if desired, as the equivalent mineral acidity (EMA) in terms of mg CaC03 per litre of water (i.e. parts per million of CaC03). In general, if the titre is A mL of sodium hydroxide of molarity B for an aliquot volume of V mL, the EMA is given by (AB x 50 x 1000)/V... [Pg.210]

Run a blank on the reagents, but use 0.1M acid and alkali solutions for the titrations calculate the blank to 0.5M sodium hydroxide. Subtract the blank (which should not exceed 0.5 mL) from the volume neutralised by the original precipitate. [Pg.305]

In titration calculations, you must consider the reaction stoichiometry. [Pg.71]

This equation will be useful as we explore titration calculations in Sections 4.6 and 4.7. [Pg.73]

By means of a pipette, transfer a portion of approx lOg of the sample to a tared 250 ml beaker, rewelgh and dissolve in 100ml of benzene. Move the soln to a 250-ml separatory funnel and shake the contents of it with a 50-ml portion of neutral distilled water. After separation of layers run die water layer into the above 250-ml beaker. Repeat the operation using another 50ml of discd w and transfer the bottom layer to the same beaker. Add to beaker several drops of bromomethyl blue indicator. If the soln turns yellow titrate immediately with standard 0.01N NaOH. soln and if hlue titrate immediately with standard 0.0IN sulfuric acid. The change of color is taken as end point. Run a blank detn on 100ml of benzene alone and correct die volume alkali of acid required for titration. Calculate the percentage of acidity as nitric acid or alkalinity as Na carbonate as follows ... [Pg.139]

Note Methyl Red is partly decolorized by nitrous acid, hence it is advisable to add the indicator towards the end of the titration Calculations for Total Acidity in Terms of HjSO ... [Pg.717]

This process is called a titration, and it s often used by chemists to determine the molcirity of acids and bases. In a titration calculation, you generally know the identity of an acid or base of unknown concentration, and you know the identity and molarity of the acid or base that you re going to use to neutralize it. Given this information, you then follow six simple steps ... [Pg.238]

Theoretical titration curves for enzymes can be calculated from known crystal structures and first principles of electrostatics. Key amino acids at the active site have significantly perturbed pK values and unusual regions in which they are partially protonated over a wide pH region.3 In principle, such titration calculations can identify the active site of a protein whose structure is known, but whose function is not. [Pg.199]

The titration calculations for this problem are of four types ... [Pg.202]

Landmarks in a titration. Calculations for the titration of MES with NaOH are shown in Table 11-2. The calculated... [Pg.204]

In this expression, aZn2+ is given by Equation 12-17 and aY4- is given by Equation 12-4. For particular values of pH and [NH3], we can compute K and proceed with titration calculations as in Section 12-3, substituting K" for K s. An assumption in this process is that EDTA is a much stronger complexing agent than ammonia, so essentially all the EDTA binds Zn2+ until the metal ion is consumed. [Pg.239]

Formation constants for EDTA are expressed in terms of [Y4-], even though there are six protonated forms of EDTA. Because the fraction (aY4 1 of free EDTA in the form Y4 depends on pH, we define a conditional (or effective) formation constant as K = aYj Kf = MY" 4 /[M"+ [EDTA], This constant describes the hypothetical reaction Mn+ + EDTA MY 1-4, where EDTA refers to all forms of EDTA not bound to metal ion. Titration calculations fall into three categories. When excess unreacted M"+ is present, pM is calculated directly from pM = — log M l+]. When excess EDTA is present, we know both [MY"-4] and [EDTA], so IM"+] can be calculated from the conditional formation constant. At the equivalence point, the... [Pg.246]

Suppose that 50.0 mL of 0.010 0 M MgS04 are titrated with 0.020 0 M EDTA at pH 10.0, using the apparatus in the figure with an S.C.E. reference electrode. Analyte contains 1.0 X 10 4M Hg(EDTA)2- added at the beginning of the titration. Calculate the... [Pg.322]

At the endpoint, there is no more FeCl2 for reaction, so the further addition of purple KMn04 will make the whole solution purple because it can no longer be converted to colorless MnCl2 ifaO 3778 g ore sample requires 38 60 ml ofO 02105 M KMn04 for titration, calculate the percentage of ron m the original sample... [Pg.198]

A 45.34 ml sample of FeS04 requires 35.76 ml of 0.1047 N Na2Cr207 solution for titration. Calculate the normality of the FeS04 solution. [Pg.323]

HNO3 solution for titration Calculate the molanty of the Ba(OH)2 and HN03 solutions... [Pg.325]

A 0.3217 g sample of KHC204 requires 31.09 ml of NaOH for titration, whereas a 0.2135 g sample requires 29.63 ml of KMn04 for titration. Calculate the molarity and normality of each of these solutions. [Pg.327]

Na2S203 solution is reauired for the titration. A 0,5965, g sample of KH(I03)2 requires 26.43 ml NaOH solution for titration. Calculate the normality and... [Pg.327]

Primary Sequences Titration Calculated from Titration Expected... [Pg.140]

Another example of a titration calculation could involve a neutralisation reaction in which the ratio of the number of moles of acid to alkali is not 1 1. The example below shows how such a calculation could be carried out. [Pg.142]

Stoichiometric relations using the concept of the mole titration calculations... [Pg.8]

O The following data were collected during a titration. Calculate the concentration of the sodium hydroxide solution. [Pg.404]

Bromine, 0.1 N (7.990 g Br per 1000 mL) Dissolve 3 g of potassium bromate (KBr03) and 15 g of potassium bromide (KBr) in sufficient water to make 1000 mL, and standardize the solution as follows Transfer about 25 mL of the solution, accurately measured, into a 500-mL iodine flask, and dilute with 120 mL of water. Add 5 mL of hydrochloric acid, stopper the flask, and shake it gently. Then add 5 mL of Potassium Iodide TS, restopper, shake the mixture, allow it to stand for 5 min, and titrate the liberated iodine with 0.1 N Sodium Thiosulfate, adding Starch TS near the end of the titration. Calculate the normality. Store this solution in dark, amber-colored, glass-stoppered bottles. [Pg.970]

This relationship is the one that you will need for most titration calculations. The equation applies whether the titrant is an acid or a base. [Pg.573]

For each of the following precipitation titrations, calculate the cation and anion concentrations at equivalence as well as at reagent volumes corresponding to 20.00 mL, 10.00 mL, and 1.00 mL of equivalence. Construct a titration curve from the data, plotting the p-function of the cation versus reagent volume. [Pg.366]

A solution prepared by dissolving a 0.2256-g sample of electrolytic iron wire in acid was passed through a Jones reductor. The iron(Il) in the resulting solution required a 35.37-mL titration. Calculate the molar oxidant concentration if the titrant used was (a) Ce (product Ce +). [Pg.583]

Use a spreadsheet to do the calculations and plot the titration curves for the following titrations. Calculate potentials after the addition of titrant corresponding to 10%, 20%, 30%, 40%,... [Pg.586]

Gas laws, including the ideal gas law, Dalton s law, and Graham s law Stoichiometric relations using the concept of the mole titration calculations Mole fractions molar and molal solutions... [Pg.5]

The titration calculation is begun with the charge-balance equation for the solution being titrated, which is as before... [Pg.175]


See other pages where Titration calculations is mentioned: [Pg.536]    [Pg.71]    [Pg.123]    [Pg.123]    [Pg.125]    [Pg.236]    [Pg.204]    [Pg.324]    [Pg.325]    [Pg.327]    [Pg.109]    [Pg.469]    [Pg.952]    [Pg.861]    [Pg.336]    [Pg.426]    [Pg.557]   
See also in sourсe #XX -- [ Pg.165 ]

See also in sourсe #XX -- [ Pg.368 ]

See also in sourсe #XX -- [ Pg.161 ]




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