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Orbital outermost

Ionization Potential (IP) The ionization potentiai of a compound is defined as the energy requited to remove a given electron from the molecule s atomic orbit (outermost shell) and is expressed in electron volts (eV). One electron volt is equivalent to 23,053 cal/mol. [Pg.13]

The electron configuration is the orbital description of the locations of the electrons in an unexcited atom. Using principles of physics, chemists can predict how atoms will react based upon the electron configuration. They can predict properties such as stability, boiling point, and conductivity. Typically, only the outermost electron shells matter in chemistry, so we truncate the inner electron shell notation by replacing the long-hand orbital description with the symbol for a noble gas in brackets. This method of notation vastly simplifies the description for large molecules. [Pg.220]

There are several issues to consider when using ECP basis sets. The core potential may represent all but the outermost electrons. In other ECP sets, the outermost electrons and the last filled shell will be in the valence orbital space. Having more electrons in the core will speed the calculation, but results are more accurate if the —1 shell is outside of the core potential. Some ECP sets are designated as shape-consistent sets, which means that the shape of the atomic orbitals in the valence region matches that for all electron basis sets. ECP sets are usually named with an acronym that stands for the authors names or the location where it was developed. Some common core potential basis sets are listed below. The number of primitives given are those describing the valence region. [Pg.84]

If IS offen convenienf to speak of the valence electrons of an atom These are the outermost electrons the ones most likely to be involved m chemical bonding and reac tions For second row elements these are the 2s and 2p electrons Because four orbitals (2s 2p 2py 2pf) are involved the maximum number of electrons m the valence shell of any second row element is 8 Neon with all its 2s and 2p orbitals doubly occupied has eight valence electrons and completes the second row of the periodic table... [Pg.9]

Question. Which low-lying states of NO would you expect to feature in the He I ultraviolet photoelectron spectrum of NO (Consider removal of an electron from only the three outermost orbitals of NO.) Indicate whether a long or short vibrational progression would be anticipated in each case. [Pg.303]

Removal of an electron from the outermost, n lp, orbital results in the configuration... [Pg.303]

For a bond to form, the outermost tt lobes must rotate so that favorable bonding interaction is achieved—a positive lobe with a positive lobe or a negative lobe with a negative lobe. If twro lobes of like sign are on the same side of the molecule, the two orbitals must rotate in opposite directions—one clockwise and one counterclockwise. This kind of motion is referred to as disrotatory. [Pg.1183]

In what main group(s) of the periodic table do element(s) have the following number of filled p orbitals in the outermost principal level ... [Pg.161]

We see that the neutral fluorine atom has seven valence electrons that is, seven electrons occupy the outermost partially filled cluster of energy levels. This cluster of energy levels, the valence orbitals, contains one electron less than its capacity permits. Fluorine, then, has the capacity for sharing one electron with some other atom which has similar capacity. If, for example, another fluorine atom approaches, they might share... [Pg.279]

The reason usually cited for the great similarity in the properties of the lanthanides is that they have similar electronic configurations in the outermost 6s and 5d orbitals. This occurs because, at this point in the periodic table, the added electrons begin to enter 4f orbitals which are fairly deep inside the atom. These orbitals are screened quite well from the outside by outer electrons, so changing the number of 4/electrons has almost no effect on the chemical properties of the atom. The added electrons do not become valence electrons in a chemical sense—neither are they readily shared nor are they readily removed. [Pg.412]

Again it is a useful approximation to consider just the set of equivalent orbitals of the outermost subshell. Then... [Pg.65]

Thus the orbitals and r electrons lie in the outermost part of the valence shell of ethane. They should play a critical role in determining the chemical properties of the molecule. Some theories have ascribed the barrier to internal rotation to these orbitals. It should be noted that the existence of r electrons in ethane is not a novelty, and was first pointed out by Mullikcn in 1935. [Pg.19]

IB Each metal atom will lose one 4s-electron. V+, Mil, Co4, and Ni will have one electron in the 4s-orhital, but Cr+ and Cu will have zero electrons in the 4s-orbital. Because their outermost valence electrons will be in 3c/-orbitals and not the 4s-orbital, their radii should be smaller than the other cations. [Pg.979]

According to the old quantum theory, the orbit of an electron moving in such a field consists of a number of elliptical segments. Each segment can be characterized by a segmentary quantum number n, in addition to the azimuthal quantum number Ic, which is the same for all segments. In all cases it is found that about half of the entire orbit lies in the outermost (j.th) region. [Pg.713]

Now that we know how to determine hybridization states, we need to know the geometry of each of the three hybridization states. One simple theory explains it all. This theory is called the valence shell electron pair repulsion theory (VSEPR). Stated simply, all orbitals containing electrons in the outermost shell (the valence shell) want to get as far apart from each other as possible. This one simple idea is all you need to predict the geometry around an atom. First, let s apply the theory to the three types of hybridized orbitals. [Pg.78]

C07-0027. Construct an accurately scaled composite contour drawing on which you superimpose a 2s orbital, a 2 Px orbital, and the outermost portion of a 3 Px orbital of the same atom. (Use different colors to distinguish the different orbitals.) What does your contour drawing tell you about the importance of the = 2 orbitals for chemical interactions when the 3 Px orbital contains electrons ... [Pg.480]

Kr]5sU 5, xenon s outermost electrons can be promoted relatively easily into 5 d orbitals,... [Pg.627]

The electron shells of all the elements in Group 1, for instance, are filled, except for a single electron in an outermost s orbital. In fact, most of the elements in any column of the periodic table have the same number of electrons in their outermost orbitals, the orbitals involved in chemical reactions. Those orbitals are usually the same type orbital—5, p, d, or/, though there are a few exceptions. As mentioned in Chapter 4, vanadium (Z = 23) has an unexpected quirk in the arrangement of the electrons in its outer orbitals. Platinum (Z = 78) exhibits a similar anomaly, as do a few other elements. Most elements, however, play by the rules. This is why the elements in a group behave similarly. [Pg.59]

In the PP theory, the valence electron wave function is composed of two parts. The main part is the pseudo-wave function describing a relatively smooth-varying behavior of the electron. The second part describes a spatially rapid oscillation of the valence electron near the atomic core. This atomic-electron-like behavior is due to the fact that, passing the vicinity of an atom, the valence electron recalls its native outermost atomic orbitals under a relatively stronger atomic potential near the core. Quantum mechanically the situation corresponds to the fact that the valence electronic state should be orthogonal to the inner-core electronic states. The second part describes this CO. The CO terms explicitly contain the information of atomic position and atomic core orbitals. [Pg.181]

Secondly, correlations in the initial state can lead to experimental orbital momentum densities significantly different from the calculated Hartree-Fock ones. Figure 3 shows such a case for the outermost orbital of water, showing how electron-electron correlations enhance the density at low momentum. Since low momentum components correspond in the main to large r components in coordinate space, the importance of correlations to the chemically interesting long range part of the wave function is evident. [Pg.208]


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See also in sourсe #XX -- [ Pg.117 ]




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