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Molality conversion

The preceding sections have used standard molar concentration units for RNA and ions, indicated by brackets or the abbreviation M. Thermodynamic definitions of interaction coefficients are made in terms of molal units, abbreviated m, the moles of solute per kilogram of solvent water. Molal units have the convenient properties that the concentration of water is a constant 55.5 m regardless of the amount ofsolute(s) present, and the molality of one solute is unaffected by addition of a second solute. For dilute solutions, M and m units are interchangeable. We use molal units for the thermodynamic derivations in this section, and indicate later (Section 3.1) the salt concentrations where a correction for molar-molal conversion is required. [Pg.439]

Reactant charged Temp., °C. Molal conversion of reacted alcohol to ketone, % Unreacted alcohol, per cent... [Pg.210]

Reactant Ketone Molal conversion of reacted reactant to ketone, %... [Pg.211]

Mole Fraction—Molality Conversion for Henryan Activity Coefficients... [Pg.280]

The conversion is more involved because the molality is defined in terms of the mass of solvent but the molarity is defined in terms of the volume of solution. To carry out the conversion we need to know the density of the solution. [Pg.449]

Each concentration measure is convenient for some types of calculations but inconvenient for others. Consequently, a chemist may need to convert a concentration from one measure to another. Example illustrates the conversion from a mass-based concentration, percent by mass, to a mole-based concentration, molality. Mole... [Pg.832]

We have information about molarity (mol/L) and density (g/mL) and are asked to find molality (mol/kg) and mole fraction (mol/mol). A good way to approach conversions from molarity to another measure is to choose a convenient volume for the solution, determine its mass and the mass of solute, and find the mass of water by difference. Then convert mass of water to kilograms and to moles to complete the calculations. [Pg.833]

Lewis and Randall stated that in dilute solutions the activity coefficient of a strong electrolyte is the same in all solutions of the same ionic strength this statement was confirmed in thermodynamic deductions of activity coefficients. The molality version of 7 can be applied in a fully analogous way and allows a more straightforward treatment of solution properties. [Conversion of molality into molarity requires the solution densities e.g., for a solute of molar mass M and a solution of density q we have... [Pg.51]

The second approach involves simultaneous variation of the weight of catalyst and the molal flow rate so as to maintain W/F constant. One then plots the conversion achieved versus linear velocity, as shown in Figures 6.4c and 6Ad. If the results are as indicated in Figure 6Ad, mass transfer limitations exist in the low-velocity regime. If the conversion is independent of velocity, there probably are no mass transfer limitations on the conversion rate. However, this test is also subject to the sensitivity limitations noted above. [Pg.180]

At any point the molal flow rate of reactant A can be expressed in terms of the fraction conversion fA and the molal flow rate corresponding to zero conversion FA0. [Pg.263]

This equation is a very useful relation that indicates the reactor size necessary to accomplish a specified change in the degree of conversion for a fixed molal flow rate. It does require, however, a knowledge of the relationship between the reciprocal rate of reaction and the... [Pg.263]

Outlet molal flow rate Fraction conversion of limiting reagent at outlet Outlet concentration of limiting reagent FAfiU-fA out)... [Pg.271]

Equation 8.3.4 is an extremely useful expression relating in a simple manner the reactor volume, the molal flow rate at zero conversion, the change in fraction conversion accomplished in the reactor, and the reaction rate. A knowledge of any three of these quantities permits the fourth to be calculated directly. For reactor design purposes the two problems of primary interest can be readily solved using this equation. [Pg.272]

If the molal flow rate at zero fraction conversion is written in terms of the product of a... [Pg.272]

Levenspiel (11) has evaluated the right side of equation 8.3.14 for various values of n and SA. His results are presented in graphical form in Figure 8.8. For identical feed concentrations (CA0) and molal flow rates (FA0) the ordinate of the figure indicates the volume ratio required for a specified conversion level. [Pg.276]

In other words, the molal flow rate of A corresponding to zero fraction conversion at the inlet to the PFR element is equal to the sum of the net inlet flow rate and the amount that would have entered if none of the material in the recycle stream had undergone reaction. [Pg.296]

An exothermic reaction with the stoichiometry A 2B takes place in organic solution. It is to be carried out in a cascade of two CSTR s in series. In order to equalize the heat load on each of the reactors it will be necessary to operate them at different temperatures. The reaction rates in each reactor will be the same, however. In order to minimize solvent losses by evaporation it will be necessary to operate the second reactor at 120 °C where the reaction rate constant is equal to 1.5 m3/kmole-ksec. If the effluent from the second reactor corresponds to 90% conversion and if the molal feed rate to the cascade is equal to 28 moles/ksec when the feed concentration is equal to 1.0 kmole/m3, how large must the reactors be If the activation energy for the reaction is 84 kJ/mole, at what temperature should the first reactor be operated ... [Pg.312]

For 99% conversion of the S02, the inlet molal flow rate must be... [Pg.512]

We now wish to examine the heat capacity per unit mass to determine if it varies significantly with conversion. At the inlet conditions, the molal heat capacity of the gaseous feed will be equal to X(y CPi). Hence at / = 0, with Cp in units of calories per gram degree Kelvin and T in degrees Kelvin. [Pg.512]

The specific rate is k = 5.2 1 iter/gmol-hr at 82 C. Equal molal quantities the reactants are to be used. They are supplied as aqueous solutions, bicarbonate as 15 wt% and the chlorhydrin as 30 wt%. Production of glycol to be 20 kg/hr at 95% conversion. Specific gravity of the feed mixture 1.02. Find the required reactor volumes of a PFR and of a CSTR. [Pg.374]

In kinetics, similar relationships apply, but the volume of activation AV can be determined only from the pressure dependence of the rate coefficient k, since the partial molal volumes V of transition states are not directly measurable. Conversely, however, equation 4 can yield values of V. ... [Pg.46]

Frequently it is necessary to convert solute activity coefficients based on mole fraction to a molality basis, or vice versa. The equation for making this conversion can be derived in the following way. [Pg.381]

Solubility concentratiorrs can be expressed many ways, including molarity (mol/L), molality (mol/kg), mole fraction, weight percent, mass per unit volume (e g., g/L), etc. The conversion formttlas for solutiotts having different concentration units are presented in Table 1. [Pg.20]

The composition of a mixture need not be given in terms of the mole fractions of its components. Other scales of concentration are frequently used, in particular, when one of the components, say. A, can be designated as the solvent and the other (or others), B, (C,...) as the solute (or solutes). When the solute is an electrolyte capable of dissociation into ions (but not only for such cases), the molal scale is often employed. Here, the composition is stated in terms of the number of moles of the solute, m, per unit mass (1 kg) of the solvent. The symbol m is used to represent the molal scale (e.g., 5 m = 5 mol solute/1 kg solvent). The conversion between the molal and the rational scale (i.e., the mole fraction scale, which is related to ratios of numbers of moles [see Eq. (2.2)] proceeds according to Eqs. (2.32a) or (2.32b) (cf. Fig. 2.4) ... [Pg.61]

Then convert liters to kilograms using the given density of water. Thankfully, this is an easy one-to-one conversion 6 L of water becomes 61 of water. Finally, plug your values into the molality formula to determine the molality of your solution ... [Pg.192]

Consider such a reaction carried out at 100 C in a PFR. The feed rate of each reactant is 600 gmol/hr, the specific rate is 600 liters/gmol-hr and the molal volume is 16.4 liters/gmol. What reactor volume is needed for a conversion of 60% ... [Pg.354]


See other pages where Molality conversion is mentioned: [Pg.209]    [Pg.210]    [Pg.430]    [Pg.209]    [Pg.210]    [Pg.430]    [Pg.150]    [Pg.137]    [Pg.54]    [Pg.179]    [Pg.271]    [Pg.275]    [Pg.279]    [Pg.299]    [Pg.362]    [Pg.61]    [Pg.63]    [Pg.489]    [Pg.185]    [Pg.185]    [Pg.278]   
See also in sourсe #XX -- [ Pg.67 ]




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