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Hydrogen amount needed, calculation

The Preparation of Ammonium HeptafluozirconateflV). In a platinum bowl, dissolve 20 g of zirconium(IV) oxide in a hot 40% hydrogen fluoride solution taken in an excess of 20% relative to the calculated amount needed to convert the zirconium(IV) oxide to the tetrafluoride. Cool the solution in a bath with ice to 5 °C and filter it through a paper filter (preliminarily cover the funnel with a thin layer of paraffin). [Pg.210]

A variation of the general method for the synthesis of 2-amino-selenazoles is to avoid the use of the free a-halogenocarbonyl compound and in its place react the corresponding ketone and iodine with selenourea.This procedure is also taken from thiazole chemistry. By contrast with thiourea, the reaction with selenourea needs a longer reaction time and the work up of the reaction mixture is somewhat more difficult. Usually an excess of the ketone is used. In the preparation of 2-amino-4-( n-nitrophenyl)selenazole, a very high yield, calculated on the amount of iodine used, was obtained. To explain this peculiar result, the oxidative action of the nitro group was invoked. This liberates free iodine from some of the hydrogen iodide eliminated in the condensation reaction, and the free iodine then re-enters into the reaction. [Pg.348]

To calculate the amount of hydrogen produced by electrolysis powered from a wind energy conversion system within a year, the efficiency of the AC/DC (or DC-DC ) conversion 0/c) and the energy consumption of the electrolyzer (ecel) per newton cubic meter of H2 production need to be defined. The efficiency of a standard AC/DC converter ranges from 80% to 95% [41]. High values of t]c occur in the conversion of large amounts of power. Typical values of ecel range from 5 to 6 kWh/Nm3. [Pg.172]

For application purposes not only the excess adsorption, but also the compressed H2 in the void space of the material needs to be taken into account for calculating the total storage capacity. As an example, in Figure 6 the contribution of excess adsorption and compression on the total storage amount is visualised in a qualitative way for hydrogen stored at 298 K and 77 K. This example shows that for high temperatures and pressures the compression contribution gains importance, while at 77 K. the contribution of excess adsorption is more important. [Pg.74]

In atmospheric or low-pressure hydrogenation the volume of hydrogen needed for a partial or total reduction should be calculated. This is imperative for partial hydrogenations when the reduction has to be interrupted after the required volume of hydrogen has been absorbed. In exact calculations vapor pressure of the solvent used must be considered since it contributes to the total pressure in the apparatus. If oxide-type catalysts are used, the amount of hydrogen needed for the reduction of the oxides to the metals must be included in the calculation. [Pg.12]

The calculated amounts of the catalyst, reactant and solvent (if needed) are then placed in the hydrogenation vessel. Utmost care must be exercised in loading the hydrogenation container with catalysts which are pyrophoric, especially when highly volatile and flammable solvents like ether, methanol, ethanol, cyclohexane or benzene are used. The solution should be added to the catalyst in the container. If the catalyst must be added to the solution this should be done under a blanket of an inert gas to prevent potential ignition. [Pg.12]

When the reduction of stored NO is accomplished at 150 °C, the reaction shows a significant induction period (Figure 13.17). The decrease in the H2 concentration is accompanied by the evolution of NH3 and of minor amounts of N2 however, a time delay is observed between product evolution and H2 uptake. Therefore, the rate of reaction is low at this temperature and a critical high surface concentration of activated hydrogen species is needed for the reaction to occur. The regeneration of the catalyst is not complete, since only 80% of the stored NO could be reduced after prolonged treatment with H2 at 150 °C. Also, the calculated overall N2 selectivity is very poor, below 20%, and ammonia represents the main reaction product. [Pg.428]

We have already seen that a chemist who weighs 1 mg of hydrogen atoms in the shape of hydrogen molecules actually weighs 3 x 1020 molecules. Because the number of weighed particles is extremely large even when weighing minute amounts of a substance, we needed a new unit to represent the number of particles. This new unit will now be introduced with the help of two calculations ... [Pg.41]

In the case of the recent experiment with hydrogen-like carbon the nontrivial QED effects contribute an observable amount (see Table 1). We need to mention that, due to some delay of the final publications of the experimental result [1] and theoretical calculations [10], no actual theoretical predictions have been published. Most of the presentations (conference and seminar talks and posters) dealt with unaccurate theoretical predictions because it was believed that nothing had been known on the two-loop corrections. However, that was not the case, because from the beginning of the theoretical calculations up to recent re-calculations it was clearly stated ed [6] that the (Za)2 term in Eq. (4) is of pure kinematic origin and so the result is valid in any order of the expansion in a for the anomalous magnetic moment of a free electron, and in particular... [Pg.654]

Table I compares for each temperature and for CH4/O2 ratios in the feed of 10/1, 20/1, 50/1, and 500/1, the ratio of oxygen needed to convert the hydrogen produced by reaction to that actually present in the feed. These calculations are the average for the yields shown on Figure 6. When the ratio is equal to unity, exactly a sufficient amount of oxygen is in the feed to maintain the lead redox cycle. When the ratio of needed-to-available oxygen is significantly greater than one, which is the case at 500/1 and no oxygen, then oxygen to combust the H2 and to produce CO2 must come from the PbO of the catalyst. Hence the observed deactivation. Table I compares for each temperature and for CH4/O2 ratios in the feed of 10/1, 20/1, 50/1, and 500/1, the ratio of oxygen needed to convert the hydrogen produced by reaction to that actually present in the feed. These calculations are the average for the yields shown on Figure 6. When the ratio is equal to unity, exactly a sufficient amount of oxygen is in the feed to maintain the lead redox cycle. When the ratio of needed-to-available oxygen is significantly greater than one, which is the case at 500/1 and no oxygen, then oxygen to combust the H2 and to produce CO2 must come from the PbO of the catalyst. Hence the observed deactivation.

See other pages where Hydrogen amount needed, calculation is mentioned: [Pg.166]    [Pg.378]    [Pg.724]    [Pg.567]    [Pg.154]    [Pg.128]    [Pg.101]    [Pg.38]    [Pg.430]    [Pg.215]    [Pg.233]    [Pg.150]    [Pg.248]    [Pg.30]    [Pg.41]    [Pg.249]    [Pg.759]    [Pg.58]    [Pg.33]    [Pg.55]    [Pg.30]    [Pg.84]    [Pg.55]    [Pg.2]    [Pg.145]    [Pg.180]    [Pg.233]    [Pg.378]    [Pg.197]    [Pg.58]    [Pg.287]    [Pg.7]    [Pg.155]    [Pg.76]    [Pg.114]    [Pg.258]    [Pg.7]    [Pg.508]   
See also in sourсe #XX -- [ Pg.427 ]




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