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Elimination transition state for

Fig. 2. Calculated /i-elimination transition state for Me2AlEt, and elimination product... Fig. 2. Calculated /i-elimination transition state for Me2AlEt, and elimination product...
Ab initio and density functional calculations of the thermal syn elimination transition states for E reaction of organic amine oxide, sulfoxide, and phosphoxide have confirmed the expected planar geometry and known order of reactivity.71... [Pg.379]

This can be circumvented by choosing alkyl groups with no P H, eg, methyl, neopentyl, trimethylsilylmethyl, phenyl and other aryl groups, and benzyl. The linear transition state for -elimination can also be made stericaHy impossible. The most successful technique for stabilization combines both principles. The pentahaptocyclopentadienyl ring anion (Cp) has six TT-electrons available to share with titanium. Biscyclopentadienyltitanium dichloride... [Pg.154]

The dependence on steric bulk is attributed to the steric requirements imposed by the bulky trimefliylamine leaving group. In the transition state for anti elimination, steric repulsion is increased as R and increase in size. When the repulsion is sufficiently large, the transition state for syn elimination is preferred. [Pg.391]

The degree of vibrational excitation in a newly formed bond (or vibrational mode) of the products may also increase with increasing difference in bond length (or normal coordinate displacement) between the transition state and the separated products. For example, in the photodissociation of vinyl chloride [9] (reaction 7), the H—Cl bond length at the transition state for four-center elimination is 1.80 A, whereas in the three-center elimination, it is 1.40 A. A Franck-Condon projection of these bond lengths onto that of an HCl molecule at equilibrium (1.275 A) will result in greater product vibrational excitation from the four-center transition state pathway, and provides a metric to distinguish between the two pathways. [Pg.222]

The proposed catalytic cycle of the ruthenium-catalyzed intermolecular Alder-ene reaction is shown in Scheme 21 (cycle A) and proceeds via ruthenacyclopentane 100. Support for this mechanism is derived from the observation that the intermediate can be trapped intramolecularly by an alcohol or amine nucleophile to form the corresponding five-or six-membered heterocycle (Scheme 21, cycle B and Equation (66)).74,75 Four- and seven-membered rings cannot be formed via this methodology, presumably because the competing /3-hydride elimination is faster than interception of the transition state for these substrates, 101 and 102, only the formal Alder-ene product is observed (Equations (67) and (68)). [Pg.584]

A transition state for the direct methane elimination from the Pt(IV) complex having two PH3 ligands was not observed. Phosphine loss occurred concomitantly with the reductive elimination. However, the authors were able to estimate an activation barrier of ca. 16 kcal/mol for direct elimination from this Pt(IV) complex (PH3)2Cl2PtCH3(H) using artificial restraints for the geometry optimization. This value is very close to the 16.5 kcal barrier obtained for reductive elimination... [Pg.285]

Zavada et ai (1973) have related the trans/cis olefin ratio in the product to competing syn- and anti-mechanisms for elimination. The transition state for syn-elimination [ 176] is stabilized by co-ordinative interactions with the cation. [Pg.352]

Figure 11. Schematic representation of the transition states for the two different pathways in the reductive elimination of H-OCOH from RuH(r -OCOHXPH3)3 [41]. Bond distances are in A. Two PH3 ligands which are perpendicular to this plane are omitted here for brevity. Figure 11. Schematic representation of the transition states for the two different pathways in the reductive elimination of H-OCOH from RuH(r -OCOHXPH3)3 [41]. Bond distances are in A. Two PH3 ligands which are perpendicular to this plane are omitted here for brevity.
Selenoxide syn-eliminations are another reaction type favoured by less polar solvents (Reich, 1979). The planar 5-membered, pericyclic transition state for syn-elimination of [39] was mimicked by the racemic proline-based cis-hapten [39] to give 28 monoclonal antibodies (Appendix entry 8.5) (Zhou et al., 1997). Abzyme SZ-cts-42F7 converted substrate [40] exclusively into... [Pg.273]

Saunders10 and by Sims and coworkers11 have shown that the magnitude of the leaving-group heavy-atom isotope effect varies linearly with the extent of C—X bond rupture in the transition state for concerted elimination reactions and for nucleophilic substitution reactions, respectively. Since the magnitude of the isotope effect is directly related to the amount of C—X bond rupture in the transition state, these isotope effects provide detailed information about the structure of the transition state. [Pg.895]

Much evidence supports the conclusion that the elimination of the group HX from alkyl halides by bases is a trans elimination reaction. This means that the atoms H and X leave from the opposite site of the incipient double bond. It is mostly explained by assuming that the electrons which are left by the leaving proton and which will form the double bond prefer to attack the leaving group X from the rear (50). The transition state for the elimination, if it is concerted, is most stable if H, X, and the carbon atoms 1 and 2 lie on one plane, which in most molecules is best realized in the trans position (51). ... [Pg.59]

Ab initio methods using the 6-31 + G basis sets have been used in a theoretical study of competing, S n2 and El reactions of NCCH2CH2CI with HO and HS in the gas phase. The antiperiplanar elimination transition state, which is favoured over those for n2 and El(gauche) reactions, is more lcB-like than that for the slower El anti) reaction of ethyl chloride. [Pg.397]

The results observed in this system unambiguously support free-radical stability as a significant governing principle. By far the major product (62) is derived by attack on CS a minor product (63) is due to attack on C6 and hydrogen migration is effectively eliminated. These results show clearly that steric hindrance is of some importance in these reactions, although the transition states for some of these reactions q>pear to be remarkably early. ... [Pg.298]

There is a pronounced preference for the formation of a trans double bond in the Claisen-Schmidt condensation of methyl ketones. This stereoselectivity arises in the dehydration step. In the transition state for elimination to a cis double bond, an unfavorable steric interaction between the ketone substituent (R) and the phenyl group occurs. This interaction is absent in the transition state for elimination to the trans double bond. [Pg.60]


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