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Electronegativities from atomic radii

The physical properties of metal alkoxides depend primarily on the characteistics of the metal (e.g., the electronegativity, valence, atomic radius, and coordination number) and secondarily on the characteristics of the alkyl group (e.g., the size and shape). There is a change from the solid, nonvolatile ionic alkoxides of some of the alkali metals to the volatile covalent liquids of elements of valence 3, 4, 5, or 6 (e.g., Al, Si, Ti, Zr, Sb, and Te), whereas alkoxides of metals with intermediate electronegativities, such as La and Y, are mainly solids (Table 5.1). [Pg.263]

The electron configuration or orbital diagram of an atom of an element can be deduced from its position in the periodic table. Beyond that, position in the table can be used to predict (Section 6.8) the relative sizes of atoms and ions (atomic radius, ionic radius) and the relative tendencies of atoms to give up or acquire electrons (ionization energy, electronegativity). [Pg.133]

All the elements in a main group have in common a characteristic valence electron configuration. The electron configuration controls the valence of the element (the number of bonds that it can form) and affects its chemical and physical properties. Five atomic properties are principally responsible for the characteristic properties of each element atomic radius, ionization energy, electron affinity, electronegativity, and polarizability. All five properties are related to trends in the effective nuclear charge experienced by the valence electrons and their distance from the nucleus. [Pg.702]

As it is mentioned, electronegativity is dependent upon atomic radius. In the periodic table, as a period is crossed from left to right, atomic radius decreases, and hence the ability of an atom to attract valence electrons increases. However, as you descend a group, atomic radius increases and therefore ability of an atom to attract valence electrons decreases. So consequently, electronegativity decreases from top to bottom in a group and increases from left to right across a period. [Pg.7]

The electronegativity of an atom depends on the radius of the atom. The atomic radius decreases and attraction exerted on valence electrons by the nucleus increases from left to right in a period. Atomic radius increases and attraction exerted on valence electrons by nucleus decreases from top to bottom. Therefore, electronegativity increases from left to right and decreases from top to bottom in the periodic table. [Pg.41]

Germanium is disposed in the center of group 14 of the periodic table of the elements. Increased stability of divalent species, which is more pronounced for tin and lead, begins from this element. The main characteristics of these atoms, such as atomic radius, energy of ionization, electron affinity, electronegativity and other features, are presented in parallel in a review12. [Pg.1487]

Electronegativity decreases down a column of the periodic table as the atomic radius increases, pushing the valence electrons farther from the nucleus. [Pg.44]

The first reason for the enhancement effect was the formation of the more favorable structure for luminescence. The studies on the effect of different halogen anion compounds (KC1, KBr and KI) on the morin-hsDNA systems were conducted. The results showed that at the same concentrations and conditions (<1.0x10 3mol/L), KCI weakened the fluorescent intensity of the system, while both KBr and KI enhanced it, and the enhancement order was KI > KBr. It is proposed that the lone electron pair of electronegative I (or Br ), bonds to the conjugated system of morin, and that the combined system then interacted with fsDNA. With the increase of atomic radius from Br to I, the attraction between nucleus and outer electrons of... [Pg.377]

The electronegativity values increase across each row of the periodic table because the nuclear positive charge is increasing and the atomic radius decreasing. Hence the closer the outer level of electrons is to the nucleus, the more difficult to attract electrons from the atom. [Pg.73]

Consider the elements Li, K, Cl, C, Ne, and Ar. From this list select the element that (a) is most electronegative, (b) has the greatest metallic character, (c) most readily forms a positive ion, (d) has the smallest atomic radius, (e) forms ir bonds... [Pg.957]

This chart shows the variation in an important property of the metals from K through Ge. Is the property atomic radius, electronegativity, or first ionization energy Explain your choice. [Section 23.1]... [Pg.996]

It is clear from this formulation that if we read electronegativity equation starting with the right hand of it we get the consistency of the present picture when the competition between the density and its gradient approaches the atomic radius limit (the HOMO radius) then the equivalent potential of the evolved electrons identifies the Mulliken electronegativity... [Pg.303]


See other pages where Electronegativities from atomic radii is mentioned: [Pg.742]    [Pg.605]    [Pg.121]    [Pg.55]    [Pg.397]    [Pg.692]    [Pg.550]    [Pg.852]    [Pg.817]    [Pg.817]    [Pg.852]    [Pg.135]    [Pg.285]    [Pg.172]    [Pg.69]    [Pg.69]    [Pg.680]    [Pg.117]    [Pg.237]    [Pg.11]    [Pg.22]    [Pg.20]    [Pg.926]    [Pg.612]    [Pg.605]    [Pg.121]    [Pg.291]    [Pg.45]    [Pg.94]    [Pg.39]    [Pg.561]    [Pg.69]    [Pg.413]    [Pg.181]    [Pg.195]    [Pg.302]    [Pg.302]    [Pg.118]   
See also in sourсe #XX -- [ Pg.146 ]




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