Conductivity Titration of Baryta Water with Sulfuric Acid Solution

15 Conductivity Titration of Baryta Water with Sulfuric Acid Solution 

Problem Saturated barium hydroxide solution ( baryta water ) reacts with sulfuric acid in two ways on the one hand, hydronium ions react with hydroxide ions to form water molecules. On the other hand, Ba2+(aq) ions combine with S042 (aq) ions to an ion lattice solid barium sulfate is deposited. If one follows this precipitation reaction with a conductivity tester, in this particular case the current strength reverts to a value of almost zero neither the formed water nor the deposited solid barium sulfate conducts the electricity. 

Material Beakers, burette, magnet stirrer, measuring equipment for electrical conductivity and tester 0.1 M sulfuric add solution, saturated barium hydroxide solution ( baryta water ), universal indicator solution. 

Procedure (a) In the preliminary test, mix small amounts of 0.1 M sulfuric acid solution and saturated barium hydroxide solution. Observe and explain the precipitation of white crystal deposit, (b) Place 50 ml of barium hydroxide solution in a beaker, add the indicator solution, switch on the magnetic stirrer, and dip the conductivity tester into the solution. Fill the burette with sulfuric 

Observation The electric current decreases to zero, but increases rapidly after the color of the indicator changes from blue to red. 

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