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Zero kinetic energy condition

Within the above TPQ framework, even if the reference function is well chosen with respect to the physical solution, the quantization conditions (i.e. Eq.(1.50)) may admit spurious energy roots whose associated configurations satisfy the zero kinetic energy conditions at the respective tiuming points. It is to be expected that this occurs because of high frequency error, or noise , which is magnified upon performing the second order differentiation. In order to filter out such solutions, one must compare the noise... [Pg.218]

Given both of these, the imposition of a zero-kinetic energy condition, at the turning points, generates the physical solutions. [Pg.220]

If the scalet solutions only converged to the Schrodinger equation, for the physical energies, then one could implement a TPQ analysis by simply imposing (approximate) zero kinetic energy conditions starting at the respective quantization scales, a (r(), for each of the turning points. [Pg.251]

When reaction products are formed in a finite region, rather than a point source, it is best to extract the ions with a combination of acceleration and drift regions which are consistent with the Wiley-McLaren space focusing condition (Wiley and McLaren, 1955). Specific ratios of acceleration and drift distances for given electric fields are imposed so that the ion TOP is independent of the precise initial position of ionization. This is easily explained as follows. Suppose that two ions (with initially zero kinetic energy) are formed at positions Uj + 8 and tij — 8 as measured from the second acceleration, or drift region. Clearly the ion closer to the drift region will reach this... [Pg.152]

Clearly, if the above conditions are not satisfied, then the TPQ condition would not be able to distinguish between the physical and unphysical solutions to the Schrodinger equation, since any such solution will have zero kinetic energy at their corresponding turning points. [Pg.220]

In general, it is difficult to develop a TPQ analysis within the scalet representation because the (approximate) conditions to be imposed (i.e zero kinetic energy) can only be done at scales, oq, that can be close to asch- At the Schrodinger scale asch-, the scalet equation solutions are close to the corresponding Schrodinger equation solution they are converging to, and the local structure of the TPQ conditions would be incapable of efficiently distinguishing between physical and unphysical solutions. [Pg.252]

The temperature of a gas is related to the kinetic energy of its particles. For example, if we have a gas at 200 K in a rigid container and heat it to a temperature of 400 K, the gas particles will have twice the kinetic energy that they did at 200 K. This also means that the gas at 400 K exerts twice the pressure of the gas at 200 K. Although you measure gas temperature using a Celsius thermometer, all comparisons of gas behavior and all calculations related to temperature must use the Kelvin temperature scale. No one has yet achieved the conditions for absolute zero (0 K), but we predict that the particles will have zero kinetic energy and exert zero pressure at absolute zero. [Pg.354]

The first condition asserts that the kinetic energy of the system, relative to the fixed point, is constantly zero, and refers to mechanical equilibrium. [Pg.32]

The kinetic energy carried in by the projectile, rlab, is not fully available to be dissipated in the reaction. Instead, an amount Tcm must be carried away by the center of mass. Thus, the available energy to be dissipated is r,ab — Tcm = T0. The energy available for the nuclear reaction is Q + Tq. To make the reaction go, the sum Q+T0 must be greater than or equal to zero. Thus, rearranging a few terms, the condition for having the reaction occur is that... [Pg.253]

The kinetic-energy terms of the various energy balances developed h include the velocity u, which is the bulk-mean velocity as defined by the equati u = m/pA Fluids flowing in pipes exhibit a velocity profile, as shown in Fi 7.1, which rises from zero at the wall (the no-slip condition) to a maximum the center of the pipe. The kinetic energy of a fluid in a pipe depends on actual velocity profile. For the case of laminar flow, the velocity profile parabolic, and integration across the pipe shows that the kinetic-ertergy should properly be u2. In fully developed turbulent flow, the more common in practice, the velocity across the major portion of the pipe is not far fro... [Pg.118]

Attack by bromide on the allylic cation is a strongly exothermic process, so the reverse reaction has a large activation energy. At —80 °C, few collisions take place with this much energy, and the rate of the reverse reaction is practically zero. Under these conditions, the product that is formed faster predominates. Because the kinetics of the reaction determine the results, this situation is called kinetic control of the reaction. The 1,2-product, favored under these conditions, is called the kinetic product. [Pg.677]

This equation (3) is to be used provided p— V(r)>0, while p(r) is zero if p— V(r) =S0. This is readily recognized to be a condition stemming from the semi-classical nature of the TF theory. Electrons are not allowed to occupy regions of negative kinetic energy, i.e. there are no electrons in classically forbidden regions. [Pg.93]


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