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Volume gas stoichiometry

Gas Stoichiometry Molar Volume Method Gas Stoichiometry Ideal Gas Equation Method Volume-Volume Gas Stoichiometry... [Pg.391]

Another type of gas law problem involves stoichiometry. Gas stoichiometry problems are just like all other stoichiometry problems—you must use moles. In addition, one or more gas laws are necessary. Let s look at a gas stoichiometry problem. What volume, in liters of oxygen gas, collected over water, forms when 12.2 g ofKCl03 decompose according to the following equation ... [Pg.92]

Gas volume relations from equations Gas stoichiometry involving mass Basic assumptions of the kinetic theory of gases Predictions of the kinetic theory... [Pg.401]

This information will help you with a certain type of gas stoichiometry problem. When a gas reacts to produce another gas, you can use Gay-Lussac s law of combining volumes to find the volumes of the gases. The following Sample Problem shows you how. [Pg.501]

There are ways other than density to include volume in stoichiometry problems. For example, if a substance in the problem is a gas at standard temperature and pressure (STP), use the molar volume of a gas to change directly between volume of the gas and moles. The molar volume of a gas is 22.41 L/mol for any gas at STP. Also, if a substance in the problem is in aqueous solution, then use the concentration of the solution to convert the volume of the solution to the moles of the substance dissolved. This procedure is especially useful when you perform calculations involving the reaction between an acid and a base. Of course, even in these problems, the basic process remains the same change to moles, use the mole ratio, and change to the desired units. [Pg.326]

In gas stoichiometry problems, what is the bridge between amount in moles and volume ... [Pg.460]

Tliis is a gas stoichiometry problem that requires knowledge of Avogadro s law to solve. Avogadro s law states that the volume of a gas is directly proportional to the number of moles of gas at constant temperatiue and pressure. [Pg.118]

We now consider gas stoichiometry problems at temperatures and pressures other than STP. At STP you know that molar volume is 22.4 L/mol, and you have used it to solve those problems. In this section, you must first calculate the molar volume at the given temperature and pressure. Once you know the molar volume, you can solve all gas stoichiometry problems in exactly the same way. [Pg.406]

The stoichiometry path may be summarized as given quantity mol given mol wanted wanted quantity. In a gas stoichiometry problem, the first or third step in the path is a conversion between moles and liters of gas at a given temperature and pressure. If you are given volume, you must convert to moles if you find moles of wanted substance, you must convert to volume. These conversions are made with the ideal gas equation, PV = nRT. You have already made conversions like these. For example, in Example 14.3, you calculated the volume occupied by 0.393 mol N2 at 24°C and 0.971 atm. You used the ideal gas equation solved for V. [Pg.408]

In a gas stoichiometry problem, either the given quantity or the wanted quantity is a gas at specified temperature and pressure. The problem is usually solved in two steps, the order of which depends on whether the gas volume is the wanted quantity or the given quantity. [Pg.409]

Gas stoichiometry problems are usually solved in two steps. However, using RT/P for molar volume makes it possible to solve... [Pg.414]

P the total pressure, aHj the mole fraction of hydrogen in the gas phase, and vHj the stoichiometric coefficient of hydrogen. It is assumed that the hydrogen concentration at the catalyst surface is in equilibrium with the hydrogen concentration in the liquid and is related to this through a Freundlich isotherm with the exponent a. The quantity Hj is related to co by stoichiometry, and Eg and Ag are related to - co because the reaction is accompanied by reduction of the gas-phase volume. The corresponding relationships are introduced into Eqs. (7)-(9), and these equations are solved by analog computation. [Pg.85]

Notice that the volume of H2 gas is twice the volume of O2 gas, as required by the stoichiometry of the overall reaction. [Pg.1411]

Be sure, especially in stoichiometry problems involving gases, that you are calculating the values such as volume and pressure of the correct gas. You can avoid this mistake by clearly labeling your quantities that means, mol of 02 instead of just mol. [Pg.84]


See other pages where Volume gas stoichiometry is mentioned: [Pg.410]    [Pg.411]    [Pg.413]    [Pg.414]    [Pg.416]    [Pg.410]    [Pg.411]    [Pg.413]    [Pg.414]    [Pg.416]    [Pg.469]    [Pg.433]    [Pg.361]    [Pg.405]    [Pg.405]    [Pg.407]    [Pg.414]    [Pg.416]    [Pg.92]    [Pg.29]    [Pg.385]    [Pg.459]    [Pg.524]    [Pg.275]    [Pg.336]    [Pg.75]    [Pg.92]   
See also in sourсe #XX -- [ Pg.385 , Pg.393 ]




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