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Transformation equations for the

Let us consider now the more complicated case of an arbitrary excitation. The approach to be followed in this case uses the Laplace transform. From Eqs. (16.249) through (16.251), the transformed equations for the displacement and stress can be written as... [Pg.753]

Finally, we see from the Fourier transform equations, for the structure factor Fhu and the electron density p x, y, z), that any change in real space (e.g., the repositioning of an atom) affects the amplitude and phase of every reflection in diffraction space. Conversely, any change in the intensities or phases in reciprocal space (e.g., the inclusion of new reflections) affects all of the atomic positions and properties in real space. There is no point-to-point correspondence between real and reciprocal space. With the Fourier transform and diffraction phenomena, it is One for all, and all for one (Dumas, The Three Musketeers, 1844). [Pg.169]

Therefore, we form the U-transformed equation for the Schrodinger unitary operator ... [Pg.252]

The transformation equations for the first derivatives are found using the chain rule. [Pg.224]

Use well-known approximation for the isotherm of disjoining pressure ri(h) = AJh, where A is the constant. The film s curvature can be expressed as K = -l/(tr). After some transformations we derive the equation for the thickness h of liquid film ... [Pg.617]

Farkas O and Schlegel H B 1998 Methods for geometry optimization In large molecules. I. An O(N ) algorithm for solving systems of linear equations for the transformation of coordinates and forces J. Chem. Phys. 109 7100... [Pg.2357]

At this point, we recall from elementary mechanics of materials the transformation equations for expressing stresses in an x-y coordinate system in temis of stresses in a 1-2 coordinate system. [Pg.74]

Discuss wfhether this relation is valid for anisotropic materials. That is, denwistrate whether a a angle-ply laminate of the same anisotropic laminae that are symmetric geometrically is antisymmetric or not. The transformation equations for anisotropic materials are given in Section 2.7. [Pg.222]

This is the procedure From the postulated kinetic scheme we write the differential rate equations. Take the Laplace transforms of the differential equations. Solve the resulting set of algebraie equations for the transforms of the concentrations. Then take the inverse transforms to obtain the coneentrations as funetions of time. [Pg.86]

Some coordinate transformations are non-linear, like transforming Cartesian to polar coordinates, where the polar coordinates are given in terms of square root and trigonometric functions of the Cartesian coordinates. This for example allows the Schrodinger equation for the hydrogen atom to be solved. Other transformations are linear, i.e. the new coordinate axes are linear combinations of the old coordinates. Such transfonnations can be used for reducing a matrix representation of an operator to a diagonal form. In the new coordinate system, the many-dimensional operator can be written as a sum of one-dimensional operators. [Pg.309]

The above rate equation is in agreement with that reported by Madhav and Ching [3]. Tliis rapid equilibrium treatment is a simple approach that allows the transformations of all complexes in terms of [E, [5], Kls and Kjp, which only deal with equilibrium expressions for the binding of the substrate to the enzyme. In the absence of inhibition, the enzyme kinetics are reduced to the simplest Michaelis-Menten model, as shown in Figure 5.21. The rate equation for the Michaelis-Menten model is given in ordinary textbooks and is as follows 11... [Pg.137]

This partial differential equation is most conveniently solved by the use of the Laplace transform of temperature with respect to time. As an illustration of the method of solution, the problem of the unidirectional flow of heat in a continuous medium will be considered. The basic differential equation for the X-direction is ... [Pg.395]

The equation is most conveniently solved by the method of Laplace transforms, used for the solution of the unsteady state thermal conduction problem in Chapter 9. [Pg.603]

Chapter 8 consists of the following in Sect. 8.2 the physical model of the process is described. The governing equations and conditions of the interface surface are considered in Sects. 8.3 and 8.4. In Sect. 8.5 we present the equations transformations. In Sect. 8.6 we display equations for the average parameters. The quasi-one-dimensional model is described in Sect. 8.7. Parameter distribution in characteristic zones of the heated capillary is considered in Sect. 8.8. The results of a parametrical study on flow in a heated capillary are presented in Sect. 8.9. [Pg.351]

The above formulation can be generalized to a general multidimensional case in the form invariant under any coordinate transformation, as was done before for the ground-state case. We consider the general Hamiltonian given by Eq. (32). The formulation can be carried out in the same way as before. The equation for the additional term w is given by... [Pg.132]

The K-matrix method is essentially a configuration interaction (Cl) performed at a fixed energy lying in the continuum upon a basis of "unperturbed funetions that (at the formal level) includes both diserete and eontinuous subsets. It turns the Schrodinger equation into a system of integral equations for the K-matrix elements, which is then transformed into a linear system by a quadrature upon afinite L basis set. [Pg.368]

Integrating this equation between the limits of f = 0 and t, taking into account that at f = 0 the potential E = E, and performing simple transformations, we obtain an equation for the potential decay curve ... [Pg.207]

The combination of Eqs. (28) and (22) gives the Laplace transform of the impulse response H(p) which allows us to solve Eq. (21). By the inverse transformation, the relation which gives the output of the linear system g(t) (the thermogram) to any input/(0 (the thermal phenomenon under investigation) is obtained. This general equation for the heat transfer in a heat-flow calorimeter may be written (40, 46) ... [Pg.213]

In the preceding F = fc(r, r), H = tc(r, vt)G = k(vt, v) and the normalization constant C is fixed by equating the volume integral of n to unity. For further tractability, Sano and Mozumder expand (r v) in a Taylor s series and retain the first two terms only. The validity of this procedure can be established a posteriori in a given situation. At first, the authors obtain equations for the time derivatives of the expectation values and the correlations of dynamical variables. Then, for convenience of closure and computer calculation, these are transformed into a set of six equations, which are solved numerically. The first of these computes lapse time through the relation... [Pg.276]

We will not present here how to derive the first Pontryagin s equation for the probability Q(t, x0) or P(f,x0). The interested reader can see it in Ref. 19 or in Refs. 15 and 18. We only mention that the first Pontryagin s equation may be obtained either via transformation of the backward Kolmogorov equation (2.7) or by simple decomposition of the probability P(t, xq) into Taylor expansion in the vicinity of xo at different moments t and t + t, some transformations and limiting transition to r — 0 [18]. [Pg.371]

Equations (31) and (32) are unchanged, with W (Rx), W(2, (R>j, and now being 2x2 matrices. The adiabatic-to-diabatic transformation, as for the n-state case, eliminates any poles in both the first- and second-derivative coupling matrices at conical intersection geometries but in this case Eq. (52) yields... [Pg.301]

In order to solve the wave equation for the hydrogen atom, it is necessary to transform the Laplacian into polar coordinates. That transformation allows the distance of the electron from the nucleus to be expressed in terms of r, 9, and (p, which in turn allows the separation of variables technique to be used. Examination of Eq. (2.40) shows that the first and third terms in the Hamiltonian are exactly like the two terms in the operator for the hydrogen atom. Likewise, the second and fourth terms are also equivalent to those for a hydrogen atom. However, the last term, e2/r12, is the troublesome part of the Hamiltonian. In fact, even after polar coordinates are employed, that term prevents the separation of variables from being accomplished. Not being able to separate the variables to obtain three simpler equations prevents an exact solution of Eq. (2.40) from being carried out. [Pg.50]

In the Heisenberg picture the operators themselves depend explicitly on the time and the time evolution of the system is determined by a differential equation for the operators. The time-dependent Heisenberg operator AH(t) is obtained from the corresponding Schrodinger operator As by the unitary transformation... [Pg.455]

Equation 23.4-6 is one form of the performance equation for the bubbling-bed reactor model. It can be transformed to determine the amount of solid (e.g., catalyst) holdup to achieve a specified /A or cA ... [Pg.587]


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