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Thermodynamic Analysis of Gas Turbines

We can solve this equation iteratively (C, is a function of the arithmetic mean temperature) to obtain T4 = 747.5K, which is the isentropic exit temperature for which CP = 33.4 J/mol K as was shown earlier. The isentropic work rate is given by [Pg.137]

If we assume a turbine efficiency of 0.75, the real work becomes 508.9 x 0.75 = 381.675 kj, and the exit temperature can be computed to be 892.1 K. Now in general, around 50% of the work generated by the turbine is used to drive the compressor, which means that the net generation of electricity is only 0.5 x 381.657 = 190.8 kj. This means that the total system has a thermodynamic efficiency of 190.8/831.6 = 0.23 Now the hot gas stream allowed to exit the system at 892.1 K still has exergy. We can compute the total exergy rate by the method described earlier  [Pg.137]


Thermodynamic Analysis of Gas Turbine Cycles with Chemical Reactions... [Pg.105]

Vakil, H. B., "Thermodynamic Analysis of Gas-Turbine Cycles with Chemical Reactions," In reference 18, p. 538 (1981). [Pg.440]


See other pages where Thermodynamic Analysis of Gas Turbines is mentioned: [Pg.136]    [Pg.240]   


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