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Newton’s law constant

It is helpful to distinguish three different types of problem to which Newton s laws of motion may be applied. In the simplest case, no force acts on each particle between collisions. From one collision to the next, the position of the particle thus changes by v,5f, where v, is the (constant) velocity and 6t is the time between collisions. In the second situation, the particle experiences a constant force between collisions. An example of this type of motion would be that of a charged particle moving in tr uniform electric field. In the third case, the force on the particle depends on its position relative to the other particles. Here the motion is often very difficult, if not impossible, to describe analytically, due to the coupled nature of the particles motions. [Pg.367]

For a Hquid under shear the rate of deformation or shear rate is a function of the shearing stress. The original exposition of this relationship is Newton s law, which states that the ratio of the stress to the shear rate is a constant, ie, the viscosity. Under Newton s law, viscosity is independent of shear rate. This is tme for ideal or Newtonian Hquids, but the viscosities of many Hquids, particularly a number of those of interest to industry, are not independent of shear rate. These non-Newtonian Hquids may be classified according to their viscosity behavior as a function of shear rate. Many exhibit shear thinning, whereas others give shear thickening. Some Hquids at rest appear to behave like soHds until the shear stress exceeds a certain value, called the yield stress, after which they flow readily. [Pg.166]

The term static bead generally denotes the pressure in a fluid due to the head of fluid above the point in question. Its magnitude is given by the apphcation of Newton s law (force = mass X acceleration). In the case of bquids (constant density), the static headp/, Pa (lbf/ft ) is given by... [Pg.889]

When applying Newton s law to a moving automobile, acceleration depends on the excess of power over that required for constant-speed driving, namely P -P,.. From this it follows that the instantaneous acceleration (a) of the vehicle at a given road speed (V) is... [Pg.99]

The elastic stress curve in figure perfectly follows elastic strain [2]. This constant is the elastic modulus of the material. In this idealized example, this would be equal to Young s modulus. Here at this point of maximum stretch, the viscous stress is not a maximum, it is zero. This state is called Newton s law of viscosity, which states that, viscous stress is proportional to strain rate. Rubber has some properties of a liquid. At the point when the elastic band is fully stretched and is about to return, its velocity or strain rate is zero, and therefore its viscous stress is also zero. [Pg.784]

Derive Eq. (4.9) by considering a unit mass at the surface of an expanding sphere of uniform density and radius R(t) using Newton s laws supplemented by a repulsive force per unit mass AR/3 and taking kc2 as an integration constant which can be identified with —2 x the total energy per unit mass in the case when A = 0. [Pg.150]

This is a statement of Newton s law of viscosity and the constant of proportionality fi is known as the coefficient of dynamic viscosity or, simply, the viscosity, of the fluid. The rate of change of the shear strain is known as the rate of (shear) strain or the shear rate. The coefficient of viscosity is a function of temperature and pressure but is independent of the shear rate y. [Pg.30]

Newton s law states that for a liquid under shear, the shear stress T is proportional to the shear rate. In this sense, most of the unpigmented vehicles used in the paint and printing ink industries are considered ideal or Newtonian liquids. The ratio of the shear stress t to the shear rate D is thus a constant t), dependent only on temperature and pressure. This is not true for specialized gel varnishes and thixotropic systems, which are designed to have special rheological properties. [Pg.104]

In this region, Newton s law is applicable and the value of R /pu2 constant giving ... [Pg.152]

For the Newton s law regime, R /pu2 is a constant and equal to 0.22 for a spherical particle. Therefore, substituting in equation 3.81 and putting i = 0 for vertical motion, and using the negative sign for downward motion (and neglecting the effect of added mass) ... [Pg.178]

The molecular dynamics method is based on the time evolution of the path (p (t), for each particle to feel the attractions and repulsions from all other particles, following Newton s law of motion. The simplest case is a dilute gas following the hard sphere force field, where there is no interaction between molecules except during brief moments of collision. The particles move in straight lines at constant velocities, until collisions take place. For a more advanced model, the force fields between two particles may follow the Lennard-Jones 6-12 potential, or any other potential, which exerts forces between molecules even between collisions. [Pg.111]

A common simplification is to assume constant (equivalent to assuming that Re is always in the Newton s law range). It is then convenient to define a dimensionless frequency and amplitude ... [Pg.309]

Equation (5.5) is known as Hooke s Law and simply states that in the elastic region, the stress and strain are related through a proportionality constant, E. Note the similarity in form to Newton s Law of Viscosity [Eq. (4.3)], where the shear stress, r, is proportional to the strain rate, y. The primary differences are that we are now describing a solid, not a fluid, the response is to a tensile force, not a shear force, and we do not (yet) consider time dependency in our tensile stress or strain. [Pg.384]

For the case of continuous deformation under a constant tensile stress, we can write, by analogy to Newton s Law of Viscosity [Eq. (4.3)], a relationship between tensile strain rate, e, tensile stress, a, and Trouton s coefficient, k, as... [Pg.454]

The Problem You ve just cooked your pizza in a 450°F oven. You take it out and set it in a room that s 72°F. For the density of this pizza, the constant, k, in Newton s Law of Cooling is 0.0843. What will the temperature of your pizza be after five minutes Will it be cool enough to eat ... [Pg.144]

According to Newton s law, the stress S is proportional to the viscosity gradient or flow dyldt. The proportionality constant is the coefficient of viscosity often referred to as simple viscosity rj, so S = t)(dy/dt). [Pg.24]

In classical mechanics, Newton s laws of motion determine the path or time evolution of a particle of mass, m. In quantum mechanics what is the corresponding equation that governs the time evolution of the wave function, F(r, t) Obviously this equation cannot be obtained from classical physics. However, it can be derived using a plausibility argument that is centred on the principle of wave-particle duality. Consider first the case of a free particle travelling in one dimension on which no forces act, that is, it moves in a region of constant potential, V. Then by the conservation of energy... [Pg.29]

Consider a simple constant-volume reactor or bomb, with no external work done on the system. Assume, however, that heat can be transferred to the system at a rate given by Newton s law of cooling as... [Pg.651]

We will discuss quantum mechanics extensively in Chapters 5 and 6. It provides the best description we have to date of the behavior of atoms and molecules. The Schrodinger equation, which is the fundamental defining equation of quantum mechanics (it is as central to quantum mechanics as Newton s laws are to the motions of particles), is a differential equation that involves a second derivative. In fact, while Newton s laws can be understood in some simple limits without calculus (for example, if a particle starts atx = 0 and moves with constant velocity vx,x = vxt at later times), it is very difficult to use quantum mechanics in any quantitative way without using derivatives. [Pg.25]


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See also in sourсe #XX -- [ Pg.237 , Pg.241 ]




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