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Middle peak

Now what about the intensities Why s the middle peak larger Get out a marker and draw an A on one proton and a B on the other. OK. There s only one way for A and B to spin in the same direction—Both A and Bare plus or both A and B are minus. But there are two ways for them to spin opposite each other—A plus with B minus B plus with A minus. This condition happens two times. Both A and B plus happen only one time. Both A and B minus happen only one time. So what So the ratio of the intensities is 1 2 1. Ha You got it—a triplet. Do this whole business sitting on the —CH2— group. You get a quartet—four lines—because the —CH2— protons are adjacent to a methyl group. They are split B Y three to give FOUR lines (Fig. 138). [Pg.286]

Whereas a single TPR peak of benzene (T a = 230°C) was reported for n-hexane (62b), a peculiar triple benzene peak system (with values of 210°, 230°, and 255°C, respectively) was observed with 1,3-, 1,4- and 2,4-hexadienes as adsorbates (62c) (Fig. 4b). The middle peak (the only one for n-hexane) was absent during thermodesorption of benzene, therefore this can be tentatively assigned to the ring closure step (as discussed in Section II,B,2). [Pg.287]

Fig. 4 shows the SEC/UV/IR trace of a blend of a styrene/ acryllc/acid terpolymer resin and a melamine resin. It is seen that there are three distinct peaks in the SEC/UV trace for this blend. The SEC/UV/IR traces show that the peak at 185 ml corresponds to the polymer backbone the middle peak at 205 ml is associated with the melamine resin and the third peak at "220 ml has a strong UV absorbing characteristic and is acidic in nature and may well be caused by reaction by-products between catalyst, solvent and monomers. The melamine resin is melt blended with the terpolymer resin. This chromatogram indicates that only physical mixing occurs. The SEC/IR/UV information shown in this example is quite helpful in establishing proper blending conditions. [Pg.10]

Figure 71 shows the 13C spectra of pyridine at different loading levels and after a pretreatment with HC1. It is seen that the resonance of the y carbon of pyridine (middle peak) is very sensitive to its chemical state, and Maciel et al. developed a model of pyridine exchange between Bronsted, Lewis, and hydrogen-bonding acid sites as well as the physisorbed state. The same authors used the 15N signal of a fixed quantity of adsorbed pyridine as a kind of urface indicator. Pyridine is displaced by n-butylamine according to the sequence... [Pg.323]

Since the nonequivalent methyl groups are each split by the vicinal CH proton, we expect to see two separate doublets. At 300 MHz, unfortunately, the pattern appears to be a classical triplet, usually an indication of a CH3—CH2 moiety—impossible to reconcile with the structural formula and the integration. Higher resolution would pull apart the middle peak to show two doublets. [Pg.169]

Because the absorbing proton feels three different magnetic fields, it absorbs at three different frequencies in the NMR spectrum, thus splitting a single absorption into a triplet. Because there are two different ways to align one proton with and one proton against —that is, TaJ-t, and i-aTb—the middle peak of the triplet is twice as intense as the two outer peaks, making the ratio of the areas under the three peaks 1 2 1. [Pg.508]

The four-line pattern of c is due to successive splittings by Ha and Hfc. (If 7ac and /be were equal—as they would have to be if, for example, Ha and He were equivalent—the middle peaks of c would merge to give the familiar 1 2 1 triplet.)... [Pg.434]

With increasing temperature, the two outermost peaks gradually converge with the middle peak. At 693°C only a single peak is observed, consistent with the average symmetry of the P-phase. In P-quartz, the Si position has point symmetry 2, which requires the CSA orientations of the equivalent Si sites (related by 3-fold screw axes that parallel the point... [Pg.220]

Consider the ensemble of many sample paths with the length N [0, N], N, 2N],..., and also consider the distribution of their local Lyapunov exponents P(X). Figure 1 shows an example of P(X) and restricted phase portrait of the map (X ,X +i) in the case of standard maps, where the distribution P(X) reveals three peaks in general when the time interval N becomes large enough, the middle peak is gradually abolished, though the first... [Pg.466]

Let us return, however, to the problem of the middle peaks in cyclic voltammo-grams. As pointed out earlier, Genies and coworkers22 assumed that they might be the result of the phenazine nucleus insertion into the growing polymer, but such an interpretation was controversial25,32,33. On the basis of CV measurements carried out in solutions... [Pg.878]

The middle peak, which is connected to the inflection point of the isotherm, appears clearly for all faces, while the third peak, in the most positive part of the potential range of the dl region, is visible for some faces. For the (111) face, the general pattern (Figs. 35 and 36) is that of a huge double peak—which corresponds to the middle peak (its double shape is not yet explained). [Pg.73]

Fig. 39), a systematic change of the C(E) curves was observed for the first time the more negative capacity peak increases with the number of atomic steps at the gold surface in parallel, the middle peak decreases and the more positive peak shifts negatively. The most negative capacity peak seems connected to adsorption of chloride ion on monoatomic steps at the surface and the middle peak to adsorption on the terraces (see TLK model. Section III.4). [Pg.78]

Since the nonequivalent methyl groups are each split by the vicinal CH proton, we expect to see two separate doublets. At 300 MHz, unfortunately, the pattern appears to be a classical triplet, usually an indication of a CH3—CH2 moiety—impossible to reconcile with the structural formula and the integration. Higher resolution would pull apart the middle peak to show two doublets. Actually, in an earlier study at lower resolution (100 MHz), the two doublets overlapped to show four peaks. To remove the coincidence of the inner peaks that caused the apparent triplet, we used the very useful technique of titration with deuterated benzene, which gave convincing evidence of two doublets at 20% C6D6/80% CDC13 and optimal results at about a 50 50 mixture (Fig. 4.49). [Pg.184]

The distinction between the three phases can therefore be readily realized on the respective intensities of individual bands from the first group. The peak at 498 cm (e.g. with the small Raman shift) in heterogenite sample is the most intense, while the middle peak of asbolane ( 539 cm ) and the peak with the higher shift (621 cm ) of lithiophorite have the highest intensity. [Pg.247]


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