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Laplace transforms inversion of

After transforming equations into the Laplace domain and solving for output variables as functions of s, we sometimes want to transform back into the time domain. This operation is called mission or inverse Laplace tran ormation. We are translating from Russian into English. We will use the notation. [Pg.308]

There are several ways to invert functions of s into functions of t. Since s is a complex number, a contour integration in the complex s plane can be used. [Pg.309]

Another method is simply to look up the function in mathematics tables. [Pg.309]

The most common inversion method is called partial fractions expansion. The function to be inverted, F,), is merely rearranged into a series of simple functions  [Pg.309]

Then each term is inverted (usually by inspection because they are simple). The total time-dependent function is the sum of the individual time-dependent functions [see Eq. (7.3)]. [Pg.309]


Eq. 4 is amenable to solution techniques based on the numerical inversion of Laplace-transformed equations these calculations can be performed rapidly and are therefore suitable for calibration. In Figure 1, typical soil/bentonite column predictions are shown to highlight the effect of the influent mixing zone on the spatial contaminant distributions for low-flow systems. The simulation results, which were generated for column conditions described by Khandelwal et al. (1998), indicate that the mixing zone has a significant influence on the shape of the spatial contaminant distribution and, therefore should be considered explicitly in estimating sorption parameters from spatial column data. [Pg.122]

Hyperbolic functions frequently appear in electrochemical problems, for instance in the inversion of Laplace transforms. An important example of the use of the cosh function is in the expression for the differential capacity of the electrolyte double layer following the Gouy-Chapman model (Chapter 3) which has a minimum value and is symmetric around this minimum—compare Fig. 3.6 with the cosh function in Fig. A1.4. [Pg.404]

Duffy, D., On the numerical inversion of Laplace transforms Comparison of three new methods on characteristic problems from applications, ACM Transactions on Mathematical Software, Vol. 19, No. 3, 1993, pp. 333-359. [Pg.411]

As pointed out above, the critical point in finding the solution to a differential equation using Laplace transforms is the inversion of the Laplace transforms. In this section we will study a method developed by Heaviside for the inversion of Laplace transforms known as Heaviside or partial-fractions expansion. [Pg.440]

Exponential / 7.2.5 Exponential Multiplied by Time / 7.2.6 Impulse (Dirac Delta Function 8 d) Inversion of Laplace Transforms Transfer Functions... [Pg.597]

Previous sections dealt with the analytical development of Laplace transform and the inversion process. The method of residues is popular in the inversion of Laplace transforms for many applications in chemical engineering. However, there are cases where the Laplace transform functions are very complicated and for these cases the inversion of Laplace transforms can be more effectively done via a numerical procedure. This section will deal with two numerical methods of inverting Laplace transforms. One was developed by Zakian (1969), and the other method uses a Fourier series approximation (Crump 1976). Interested readers may also wish to perform transforms using a symbolic algebra language such as Maple (Heck 1993). [Pg.383]

Crump, K. S. Numerical Inversion of Laplace Transforms Using a Fourier Series Approximation, J. Assoc. Comput. Machinery, 23, 89-96 (1976). [Pg.390]

Zakian, V. Numerical Inversion of Laplace Transform, Electronics Letters, 5, 120-121 (1969). [Pg.390]

Elimination of Ci and C3 from these equations will result in the desired relation between inlet Cj and outlet Co concentrations, although not in an exphcit form except for zero or first-order reactions. Alternatively, the Laplace transform could be found, inverted and used to evaluate segregated or max mixed conversions that are defined later. Inversion of a transform hke that of Fig. 23-8 is facilitated after replacing the exponential by some ratio of polynomials, a Pade approximation, as explained in books on hnear control theory. Numerical inversion is always possible. [Pg.2075]

In practice, inverse transformation is most easily achieved by using partial fractions to break down solutions into standard components, and then use tables of Laplace transform pairs, as given in Table 3.1. [Pg.39]

In classical control theory, we make extensive use of Laplace transform to analyze the dynamics of a system. The key point (and at this moment the trick) is that we will try to predict the time response without doing the inverse transformation. Later, we will see that the answer lies in the roots of the characteristic equation. This is the basis of classical control analyses. Hence, in going through Laplace transform again, it is not so much that we need a remedial course. Your old differential equation textbook would do fine. The key task here is to pitch this mathematical technique in light that may help us to apply it to control problems. [Pg.10]

Let us first state a few important points about the application of Laplace transform in solving differential equations (Fig. 2.1). After we have formulated a model in terms of a linear or linearized differential equation, dy/dt = f(y), we can solve for y(t). Alternatively, we can transform the equation into an algebraic problem as represented by the function G(s) in the Laplace domain and solve for Y(s). The time domain solution y(t) can be obtained with an inverse transform, but we rarely do so in control analysis. [Pg.11]

Inversion with a table of Laplace transforms gives the results, A = Aq expC k1t) (12)... [Pg.71]

For a model with a known transfer function the several moments can be obtained directly without need for inversion of the transform. This a consequence of a property of the derivative of the Laplace transform, namely certain limits as s= 0 ... [Pg.542]

This solution is then inversely transformed by use of a table of Laplace transforms (see Table 5.3) to obtain the desired solution ... [Pg.112]

We shall now determine the inverse Laplace transform of this function to find the concentration of B at time t. In tables of Laplace transforms the following pair has been found ... [Pg.233]

The most common approach to solution of partial differential equations of the type represented by (7) involves the use of Laplace transformation (Crank, 1957). The method involves transforming the partial differential equation into a total differential equation in a single independent variable. After solving the total differential equation inverse transformation of the solution can be carried out in order to reintroduce the second independent variable. Standard Laplace transforms are collected in tables. [Pg.144]

The measurable linear viscoelastic functions are defined either in the time domain or in the frequency domain. The interrelations between functions in the firequenpy domain are pxirely algebraic. The interrelations between functions in the time domain are convolution integrals. The interrelations between functions in the time and frequency domain are Carson-Laplace or inverse Carson-Laplace transforms. Some of these interrelations will be given below, and a general scheme of these interrelations may be found in [1]. These interrelations derive directly from the mathematical theory of linear viscoelasticity and do not imply any molecular or continuum mechanics modelling. [Pg.96]

The relaxation modulus G(t) is the value of the transient stress per unit strain in a step-strain experiment. This type of experiment may be achieved with modem rotary rheometers with a limited resolution in time (roughly 10 2 s). If one wishes to evaluate G(t) at shorter times, it is necessary to derive G(t) from the high frequency G (co) data by an inverse Carson-Laplace transform. [Pg.96]

In example 8.9 the Laplace transform technique was used to solve a time dependent problem. Inversing the Laplace transform is not straightforward. For complicated time dependent boundary conditions the convolution theorem can be used to find the inverse Laplace transform efficiently. If H(s) is the solution obtained in the Laplace domain, H(s) is represented as a product of two functions ... [Pg.747]

At this point, the inverse Laplace transformation of equation (6.5.19) is carried out. In order to do this, one must consult a table of Laplace transforms such as the one given in appendix A. Operating on each term individually, one obtains... [Pg.269]

The final step is to perform inverse Laplace transformation on c x, s) to obtain c x, t). Using the table of Laplace transformations, inverse transformation of equation (6.5.27) results in... [Pg.270]

Some ordinary differential equations can be solved by using some theorems of Laplace transforms which transform a differential equation into an algebraic equation. If this equation can be solved for the transform of the unknown function, and if the inverse transform can be found, the equation is solved. [Pg.264]

The quantities qi, qi and have the dimensions cm-1. They are inverse screening lengths. Later we shall see that qo also plays a role in the equilibrium structure of the ionic solution. Equation (9.2.15) can be solved by means of Laplace transformation with respect to time. When the solutions are multiplied by <5c (q, 0) and Sc (q, 0) and ensemble-averaged we obtain... [Pg.210]

The determination of the density of states for s classical oscillators by the method of Laplace transforms is of limited value because this can be obtained by other methods as well. Of much greater interest is the fact that the product of the quantum oscillators in Eq. (6.48) can be inverted by the Laplace transform method. However, it requires solving the inverse Laplace transform integral (Forst, 1971, 1973 Hoare and Ruijgrok, 1970) ... [Pg.180]

A second important property of Laplace transforms is expressed in the integration theorem (Steinfeld et al., 1989 Forst, 1973). If p E) is the inverse Laplace transform of 2(P)> then the integral of p( ), given by N( ) is... [Pg.182]


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