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Genome redundancy

The method is scale dependent. What happens with releves of 10 crrf What with 1 ha Moreover, the observations of Ellenberg (1960) on relative Standortkonstanz of sp>ecies (relative dependence on site factors) are often not considered. Note that an ecological interpretation of genome redundant size reinforces this concept (Bennett and Smith 1991). [Pg.154]

MUCH OF THE MAMMALIAN GENOME IS REDUNDANT MUCH IS NOT TRANSCRIBED... [Pg.320]

This is fundamental to the progress of genomics (and many other areas) of science. Generating data in a common exchangeable format, with a common lexicon of terms [47] in a single non-redundant location is a major goal. A number of examples exist, such as the DNA and protein sequence data in GenBank, EMBL or SwissProt [48-50]. [Pg.87]

J. A. Papin, N. D. Price, J. S. Edwards, and B. O. Palsson, The genome scale metabolic extreme pathway structure in Haemophilus influenzae shows significant network redundancy. J. Theor. Biol. 215, 67 82 (2002). [Pg.236]

Redundancies, which are overlaps at the same genomic position, were adjusted with the clustering method, in which sequences were merged together only when they showed hits for more than 50 amino acids with higher than 99% identity. [Pg.44]

Table 11.2. Genetic redundancies in small genomes of endosymbionts and... Table 11.2. Genetic redundancies in small genomes of endosymbionts and...
Proteome Genome size (kb) Number of ORFs Number of redundant sequences Redundancy (%)... [Pg.250]

The most common changes in mitochondria (and the only code changes that have been observed in cellular genomes) involve termination codons. These changes affect termination in the products of only a subset of genes, and sometimes the effects are minor because the genes have multiple (redundant) termination codons. [Pg.1042]

The T-odd bacteriophages Tl, T3, T5, and T7 are medium-sized phage with linear duplex DNA genomes. Replication of linear DNA in these and in many other genomes presents a problem. Even if the RNA primer segment is made at the very 3 end of the template strand, there will be a gap in the final replicated strand when the primer is digested out. Since there is no known enzyme that will add to the 3 end of a chain, this gap will remain unfilled. The problem is solved by terminal redundancy, the presence of a common 260-nucleotide... [Pg.1559]


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See also in sourсe #XX -- [ Pg.320 , Pg.321 ]




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