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Equilibrium, re-establishment

However, the scent is primarily defined by the cis-isomers, and in particular the (3R,7S)-enantiomer. The cis-isomers can be separated by fractional distillation, and the equilibrium re-established by heating in the presence of sodium carbonate (Fig. 3.24). [Pg.92]

The kinetics of the reversible binding of NO to [Fe(OH2)6] can be followed by using flash photolysis and monitoring changes in the absorption spectrum. Irradiation of [Fe(OH2)5(NO)] at a wavelength of 532nm results in rapid dissociation of NO and loss of the absorptions at 336, 451 and 585 nm, i.e. the equilibrium above moves to the left-hand side. Following the flash , the equilibrium re-establishes itself within 0.2 ms (at 298 K) and the rate at which [Fe(OH2)5(NO)] reforms can be determined from the reap-... [Pg.985]

A large excess of Mgp2(s) is maintained in contact with 1.00 L of pure water to produce a saturated solution of Mgp2. When an additional 1.00 L of pure water is added to the mixture and equilibrium re-established, compared with the original saturated solution, will [Mg " "] be (a) the same (b) twice as large ... [Pg.832]

The addition of the sulphuric acid first neutralises the sodium hydroxide, and then gives a weakly acidic and therefore colourless solution. The sodium derivative (A) then undergoes further partial hydrolysis in order to re-establish the original equilibrium, and the sodium hydroxide thus formed again produces the pink coloration, which increases in depth as the hydrolysis proceeds. [Pg.134]

The mixture was prepared and allowed to achieve equilibrium to it was added an excess of urea which caused the immediate precipitation as urea nitrate of the free nitric acid present. As a result of the sudden removal of the nitric acid from the mixture, the system underwent change to re-establish the equilibrium however, the use of an excess of urea removed the nitric acid as it was produced from acetyl nitrate and acetic acid, and the consumption of acetyl nitrate proceeded to completion. Thus, by following the production of urea nitrate with the time from the addition of urea, the rate of the back reaction could be determined, and by extrapolating the results to zero time the equilibrium... [Pg.80]

To derive an explicit expression of the rate of desorption we restrict ourselves to nondissociative adsorption, listing references to other systems— such as multicomponent and multilayer adsorbates with and without precursors—for which such a treatment has been given, later. We look at a situation where the gas phase pressure of a molecular species, P, is different from its value, P, which maintains an adsorbate at coverage 6. There is then an excess flux to re-establish equilibrium between gas phase and adsorbate so that we can write [7-10]... [Pg.442]

Bergmann has suggested that oxidation is ruled out at positions (where hydration occurs readily) which are not accessible to the enzyme after the pteridine is adsorbed on it. Alternatively, the destruction of co-planarity by hydration may prevent adsorption of the pteridine on the enzyme. The case of xanthopterin (2-amino-4,6-dihydroxypteridine) may be relevant. The neutral species of this substance exists as an equilibrium mixture of approximately equal parts of the anhydrous and 7,8-hydrated forms (in neutral aqueous solution at 20°). Xanthine oxidase cataljrzes the oxidation of the anhydrous form in the 7-position but leaves the hydrated form unaffected and about two hours is required to re-establish the former equilibrium. [Pg.41]

Total reflux exists in a distillation column, whether a binary or multicomponent system, when all the overhead vapor from the top tray or stage is condensed and returned to the top tray. Usually a column is brought to equilibrium at total reflux for test or for a temporary plant condition which requires discontinuing feed. Rather than shut down, drain and then re-establish operating conditions later, it is usually more convenient and requires less... [Pg.21]

Reality Check Note that the equilibrium partial pressure of HI is intermediate between its value before equilibrium was established (0.80 atm) and that immediately afterward (1.00 atm). This is exactly what Le Chatelier s principle predicts part of the added HI is consumed to re-establish equilibrium. [Pg.339]

Figure 2.1 Decreasing the external pressure by dp causes the piston to move a distance dx. This increase in volume reduces the internal pressure by dp and re-establishes mechanical equilibrium. The process produces pressure-volume work. Figure 2.1 Decreasing the external pressure by dp causes the piston to move a distance dx. This increase in volume reduces the internal pressure by dp and re-establishes mechanical equilibrium. The process produces pressure-volume work.
The Reversible Process Process (iv) is a representation of a hypothetical reversible expansion in which p and / exl never differ by more than an infinitesimal dp. To carry out the process, pexl is decreased by an amount dp. An expansion then occurs so that V goes to V +dV). This causes the internal pressure to decrease by an amount dp and equilibrium is re-established. This process is repeated an infinite number of times until all of the d V changes add up to AV and V2 = V + AV is reached.g In each step, p never differs from pexl by more than an infinitesimal amount. The process is under control and can be reversed at any time by increasing the pressure by an infinitesimal amount. Hence, the name reversible" is applied to this process. [Pg.44]

Clearly, if a situation were achieved such that exceeded Np, the excess energy could be absorbed by the rf field and this would appear as an emission signal in the n.m.r. spectrum. On the other hand, if Np could be made to exceed by more than the Boltzmann factor, then enhanced absorption would be observed. N.m.r. spectra showing such effects are referred to as polarized spectra because they arise from polarization of nuclear spins. The effects are transient because, once the perturbing influence which gives rise to the non-Boltzmann distribution (and which can be either physical or chemical) ceases, the thermal equilibrium distribution of nuclear spin states is re-established within a few seconds. [Pg.55]

C16-0016. Suppose that the right-hand view represents equilibrium and the left-hand view represents a displacement from equilibrium. Draw a molecular picture showing how the left-hand view would react to re-establish equilibrium. [Pg.1161]

The temperature at which this condition is satisfied may be referred to as the melting point Tm, which will depend, of course, on the composition of the liquid phase. If a diluent is present in the liquid phase, Tm may be regarded alternatively as the temperature at which the specified composition is that of a saturated solution. If the liquid polymer is pure, /Xn —mS where mS represents the chemical potential in the standard state, which, in accordance with custom in the treatment of solutions, we take to be the pure liquid at the same temperature and pressure. At the melting point T of the pure polymer, therefore, /x2 = /xt- To the extent that the polymer contains impurities (e.g., solvents, or copolymerized units), ixu will be less than juJ. Hence fXu after the addition of a diluent to the polymer at the temperature T will be less than and in order to re-establish the condition of equilibrium = a lower temperature Tm is required. [Pg.568]

While capillary pressure can be determined independently through experiments implementing a series of equilibrium states, this can be very time consuming, particularly if the entire capillary pressure function is to be reconciled. Furthermore, as there can be difficulties in re-establishing identical states of initial saturation, it is most desirable to determine capillary pressure and relative permeability functions simultaneously, from the same experiment. [Pg.375]

Figure 2.107(a) shows UV-visible spectra of the BQT (obtained at — 1.0 V) and BQ2" (obtained at —1.8 V) after the potential-step and the re-establish-ment of equilibrium. The spectrum of BQT is consistent with that obtained... [Pg.208]

The effect of concentration changes were observable in the two systems described above. For the system A + B c C + D, an increase in the concentration of A and/or B will shift the position of equilibrium to the right-hand side. For example, on increasing the concentration of A, some of the added A reacts with substance B to produce more C and D until equilibrium is re-established. Similarly, if the concentration of C and/or D is increased, the position of equilibrium is shifted to the left-hand side. Removal of a component, e.g. substance A, will cause the system to respond in such a way as to oppose the change, i.e. the decrease in the concentration of A. Therefore, the equilibrium position shifts to the left-hand side. [Pg.84]

The rate constant is measured in units of moles dnr3 sec /(moles dnr3)", where n = a + b. Time may also be in minutes or hours. It should be noted that in case where the reaction is slow enough, the thermal equilibrium will be maintained due to constant collisions between the molecules and k remains constant at a given temperature. However, if the reaction is very fast the tail part of the Maxwell-Boltzmann distribution will be depleted so rapidly that thermal equilibrium will not be re-established. In such cases rate constant will not truly be constant and it should be called a rate coefficient. [Pg.4]

Schmidlin s experiment here described shows very clearly the equilibrium between hexaphenylethane and triphenylmethyl. The disappearance of the colour on shaking the substance with air indicates that the yellow radicle, present in equilibrium, is removed as (colourless) peroxide. The re-establishment of the equilibrium by renewed dissociation of (colourless) hexaphenylethane proceeds so slowly that the formation of the yellow radicle in the decolorised solution can be observed without difficulty. [Pg.353]

The vapour fraction of the solute is moved down the column by the carrier gas and the equilibrium between the two phases is destroyed. However, in an attempt to re-establish an equilibrium, solute molecules leave the liquid phase restoring the partial pressure above the solution. The solute vapour which has been moved down the column encounters fresh solvent and a new equilibrium is established. [Pg.119]

Your teacher will give you a table that lists four equilibrium systems and the changes you will make to each system. In the appropriate column, record your predictions for each test. If you predict that the change will cause the system to re-attain equilibrium by shifting toward the reactants, record left. If you predict that the system will re-establish equilibrium by shifting toward the products, record right. ... [Pg.358]


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See also in sourсe #XX -- [ Pg.69 ]




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