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Empirical formula experiments

The word empirical implies a result derived from experiment rather than theory. Similarly, a chemist calculates a compound s empirical formula while fully aware its value is based on experiment rather than theory. [Pg.281]

Background Many elements combine with oxygen or other nonmetals in various ratios i.e. FeO, Fe203, Fe304. This phenomenon demonstrates the Law of Multiple Proportions. In this experiment, you will analyze the ratios in which lead and chlorine can combine and from the data provided, be able to determine the empirical formulas of the compounds produced. [Pg.253]

This procedure will allow you to calculate the empirical formula of the substance. The experiment is often performed by reacting magnesium metal with atmospheric oxygen to form magnesium oxide. [Pg.282]

A variation of this experiment uses the mass of the anhydrous material (calculated from the difference between masses 1 and 3). The moles of the anhydrous material and water are then calculated from their respective masses and molar masses. The simplest ratio of the moles gives the empirical formula. [Pg.282]

When solutions of 19 are warmed above ca. —50°C, the appearance of a new set of lH NMR signals consisting of a ( -CsMes) resonance at 1.94 5 (30H), a singlet at 5.73 5 (1H), and singlet at 6.55 5 (1H), accompanies the disappearance of the spectrum of 19. Independent experiments indicate that no H2 or CO evolution is associated with the conversion of 19 to this new compound (20), so both must have the same empirical formula. While our initial interpretation of these NMR data was that 20 was a formyl hydride species, further experiments revealed that it is a dimer with an unusual enne-dioxy bridge of the structure shown in 20. This structure is supported by its ir spectrum (v (Zr-H) 1580 cm-1,... [Pg.150]

When a new chemical compound is prepared, we do not know its formula. To establish the formula, we find by experiment the weights of the various atoms in the compound, and from these weights we compute the relative number of each kind of atom in the molecule. The formula so computed is the simplest formula, not necessarily the true one. It is therefore called the empirical formula. For example, we would find the empirical formula for benzene to be CH, whereas... [Pg.148]

F.5 In an experiment, 4.14 g of the element phosphorus combined with chlorine to produce 27.8 g of a white solid compound. What is the empirical formula of the compound ... [Pg.88]

In another experiment an unknown organic compound was found to contain 0.12 g of carbon and 0.02 g of hydrogen. Calculate the empirical formula of the compound. (Ar H = 1 C = 12)... [Pg.76]

In Figs. 66 and 68 the calculated absorption and loss spectra are depicted for ordinary water at the temperatures 22.2°C and 27°C and for heavy water at 27°C. The solid curves refer to the composite model, and the dashed curves refer to the experimental spectra [42, 51]. For comparison of our theory with experiment at low frequencies, in the case of H20 we use the empirical formula [17] comprising double Debye-double Lorentz frequency dependences. In the case of D20 we use empirical relationship [54] aided by approximate formulae given in Appendix 3 of Section V. The employed molecular constants were presented in previous sections, and the fitted/estimated parameters are given in Table XXIV. The parameters of the composite model are chosen so that the calculated absorption-peak frequencies ilb and vR come close to the... [Pg.323]

This formula is an excellent illustration of the limitations of an empirical formula. It is accurate within the limits of the experiments on which it was based. But it is seen that, if H is only large enough relative to B, the formula would indicate zero flow, and, for an even larger... [Pg.457]

The empirical formula of a compound can be determined in a laboratory experiment by finding the ratio between the number of moles of the elements in the compound. The number of moles of each element can be calculated from the experimental values of the weights in which the elements combine by dividing by their corresponding atomic weights. If the molecular weight and the empirical formula of the compound are known, then the molecular formula of the compound can be determined. [Pg.57]

In this experiment we will verify that the empirical formula of copper(II) chloride is CuCl2, and in so doing, demonstrate the Law of Constant Composition. We will do this by reducing a known weight of copper(II) chloride with aluminum to elemental copper. The reaction is shown by the following equation ... [Pg.58]


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See also in sourсe #XX -- [ Pg.219 , Pg.228 ]




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