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Bonding joining

Figure B2.4.1 illustrates this type of behaviour. If there is no rotation about the bond joining the N, N -dimethyl group to the ring, the proton NMR signals of the two methyl groups will have different chemical shifts. If the rotation were very fast, then the two methyl enviromnents would be exchanged very quickly and only a single, average, methyl peak would appear in the proton NMR spectrum. Between these two extremes, spectra like those in figure B2.4.1 are observed. At low temperature, when the rate is slow, two... Figure B2.4.1 illustrates this type of behaviour. If there is no rotation about the bond joining the N, N -dimethyl group to the ring, the proton NMR signals of the two methyl groups will have different chemical shifts. If the rotation were very fast, then the two methyl enviromnents would be exchanged very quickly and only a single, average, methyl peak would appear in the proton NMR spectrum. Between these two extremes, spectra like those in figure B2.4.1 are observed. At low temperature, when the rate is slow, two...
Figure B2.4.5. Simulated lineshapes for an intennolecular exchange reaction in which the bond joining two strongly coupled nuclei breaks and re-fomis at a series of rates, given beside tlie lineshape. In slow exchange, the typical spectrum of an AB spin system is shown. In the limit of fast exchange, the spectrum consists of two lines at tlie two chemical shifts and all the coupling has disappeared. Figure B2.4.5. Simulated lineshapes for an intennolecular exchange reaction in which the bond joining two strongly coupled nuclei breaks and re-fomis at a series of rates, given beside tlie lineshape. In slow exchange, the typical spectrum of an AB spin system is shown. In the limit of fast exchange, the spectrum consists of two lines at tlie two chemical shifts and all the coupling has disappeared.
The unequal distribution of charge produced when elements of different electronegativities combine causes a polarity of the covalent bond joining them and, unless this polarity is balanced by an equal and opposite polarity, the molecule will be a dipole and have a dipole moment (for example, a hydrogen halide). Carbon tetrachloride is one of a relatively few examples in which a strong polarity does not result in a molecular dipole. It has a tetrahedral configuration... [Pg.51]

A con jugated sp - -sp --" single bond (for example, the bond joining the tw o phenyl rings of biphenyl, the central bond of butadiene, with delocali/ed aromatic bonds, or phenyl amine, where N-G bond is labeled aromatic and nitrogen is sp2 b h ybridi/ed) IS described by a two-fold barrier, V2=l() kcal/mol. [Pg.212]

Tests for Unsaturation. The above reactions are used as the general tests for the presence of double or triple bonds joining carbon atoms in an organic compound. [Pg.85]

Now disconnect any bond joining two common atoms and see if there is a good starting material. [Pg.108]

Using our strategic device of marking atoms common to more than one ring (see frames 329-333), we find there is only one disconnection of a bond joining two common atoms as the molecule is symmetrical ... [Pg.119]

A bond joining two six member rings a 6-6 bond A bond joining a five member ring to a six member ring a 5-6 bond... [Pg.54]

For bonded atoms, the off-diagonal terms (where i j) are taken to depend on tjje type and length of the bond joining the atoms on which the basis functions y- and Xj 0 centred. The entire integral is written as a constant, 0ij, which is not the same as the fixY in Hiickel 7r-electron theory. The are taken to be parameters, fixed by calibration against experiment. It is usual to set Pij to zero when the pair of atoms are not formally bonded. [Pg.139]

In these compounds, as in water, the principal intermolecular forces are hydrogen bonds. When a substance like methyl alcohol dissolves in water, it forms hydrogen bonds with H20 molecules. These hydrogen bonds, joining a CH3OH molecule to an H20 molecule, are about as strong as those in the pure substances. [Pg.264]

In the catalyzed decomposition, N20 is chemically adsorbed on the surface of the solid. A chemical bond is formed between the oxygen atom of an N20 molecule and a gold atom on the surface. This weakens the bond joining nitrogen to oxygen, making it easier for the N20 molecule to break apart. Symbolically, this process can be shown as... [Pg.305]

The elasticity of nylon fibers is due in part to hydrogen bonds between adjacent polymer chains. These hydrogen bonds join carbonyl oxygen atoms on one chain to NH groups on adjacent chains (Figure 23.4). [Pg.616]

Disconnection of (2) at the bonds joining the aromatic rings to the aliphatic part of the molecule will need a reagent for the doubly charged synthon (3). [Pg.12]

Choosing all the bonds joining a carbonyl group to a heteroatom (a) or joining a heteroatom (not N, see Chapter T 8) to an alkyl group (b). [Pg.35]

When porphyrins dissolved in strong mineral acids or in organic solvents are illuminated by ultraviolet hght, they emit a strong red fluorescence. This fluorescence is so characteristic that it is often used to detect small amounts of free porphyrins. The double bonds joining the pyrrole rings in the porphyrins are responsible for the characteristic absorption and fluorescence of these compounds these double bonds are absent in the porphyrinogens. [Pg.273]

The /3-lactam bond is broken (instead of the equivalent peptide bond joining the alanine residues) but the remaining ring system in the /3-lactam (a thiazolidine in penicillins) is not released (Fig. 8.3). Instead, the transpeptidase remains linked to the hydrolysed antibiotic with a half hfe of 10-15 minutes. Whilst bound to the / -lactam, the transpeptidase cannot participate in further rounds of peptidoglycan... [Pg.166]

Figure 3.4 Transmembrane topology of a 7-TM domain G-protein receptor such as the P-adrenoceptor. Agonist binding is predicted to be within the transmembrane domains. The extracellular structure is stabilised by the disulphide bond joining the first and second extracellular loop. The third intracellular loop is the main site of G-protein interaction while the third intracellular loop and carboxy tail are targets for phosphorylation by kinases responsible for initiating receptor desensitisation... Figure 3.4 Transmembrane topology of a 7-TM domain G-protein receptor such as the P-adrenoceptor. Agonist binding is predicted to be within the transmembrane domains. The extracellular structure is stabilised by the disulphide bond joining the first and second extracellular loop. The third intracellular loop is the main site of G-protein interaction while the third intracellular loop and carboxy tail are targets for phosphorylation by kinases responsible for initiating receptor desensitisation...
We have not, however, defined a unique structure for ethane the a bond joining the two carbon atoms is symmetrical about a line joining the two nuclei, and, theoretically, an infinite variety of different structures is still possible, defined by the position of the hydrogens on one carbon atom relative to the position of those on the other. The two extremes, of all the possible species, are known as the eclipsed and staggered forms ... [Pg.7]

The effect of the chlorine atom s partial appropriation of the electrons of the carbon-chlorine bond is to leave C, slightly electron-deficient this it seeks to rectify by, in turn, appropriating slightly more than its share of the electrons of the a bond joining it to C2, and so on down the chain. The effect of Ct on C2 is less than the effect of Cl on Cl5 however, and the transmission quickly dies away in a saturated chain, usually being too small to be noticeable beyond C2. These influences on the electron distribution in [Pg.22]

As well as the C->-0 inductive effect in the carbonyl group is best represented by a hybrid... [Pg.203]

The shape of Ph3C- (49) is a matter of some interest as it has a bearing on the extent to which delocalisation of the unpaired electron, with consequent stabilisation, can occur. The radical carbon atom is certainly sp2 hybridised in (49), i.e. the bonds joining it to the three benzene nuclei all lie in the same plane but maximum stabilisation will only occur if all three benzene nuclei can be simultaneously coplanar (49a),... [Pg.311]

In certain highly energetic collisions with any molecule M in the system, a bromine molecule may be dissociated in a homolytic split of the bond joining two bromine atoms. [Pg.91]

The Prins cyclization can also be coupled with a ring-contraction pinacol rearrangement, as illustrated in Scheme 1.6. This allows a smooth conversion of alkyl-idene-cyclohexane acetal 1-16 to single bond-joined cyclohexane cyclopentane aldehyde 1-17 [le]. [Pg.14]

An A-B diblock copolymer is a polymer consisting of a sequence of A-type monomers chemically joined to a sequence of B-type monomers. Even a small amount of incompatibility (difference in interactions) between monomers A and monomers B can induce phase transitions. However, A-homopolymer and B-homopolymer are chemically joined in a diblock therefore a system of diblocks cannot undergo a macroscopic phase separation. Instead a number of order-disorder phase transitions take place in the system between the isotropic phase and spatially ordered phases in which A-rich and B-rich domains, of the size of a diblock copolymer, are periodically arranged in lamellar, hexagonal, body-centered cubic (bcc), and the double gyroid structures. The covalent bond joining the blocks rests at the interface between A-rich and B-rich domains. [Pg.147]


See other pages where Bonding joining is mentioned: [Pg.372]    [Pg.16]    [Pg.67]    [Pg.21]    [Pg.146]    [Pg.927]    [Pg.65]    [Pg.67]    [Pg.464]    [Pg.174]    [Pg.590]    [Pg.182]    [Pg.510]    [Pg.519]    [Pg.531]    [Pg.155]    [Pg.15]    [Pg.138]    [Pg.679]    [Pg.246]    [Pg.421]    [Pg.221]    [Pg.308]    [Pg.247]    [Pg.9]    [Pg.88]   


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