Balanced equations decomposition

Dinitrogen pentoxide gas decomposes to form nitrogen dioxide and oxygen. The reaction is first-order and has a rate constant of 0.247 h1 at 25°C. If a 2.50-L flask originally contains N205 at a pressure of 756 mm Hg at 25°C, then how many moles of 02 are formed after 135 minutes (Hint. First write a balanced equation for the decomposition.)... 

The UASB tractor was modeled by the dispensed plug flow model, considering decomposition reactions for VFA componaits, axial dispersion of liquid and hydrodynamics. The difierential mass balance equations based on the dispersed plug flow model are described for multiple VFA substrate components considaed... 

This situation is one involving both a total and a component mass balance, combined with a kinetic equation for the rate of decomposition of the waste component. Neglecting density effects, the total mass balance equation is... 

Depending on the initiator and monomer system secondary decomposition (equation 2), induced decomposition (equations 3,9), primary radical termination (equation 11) or transfer reactions may or may not be important and will have to be considered accordingly in the balance equations. From the above reaction scheme the following equations have been derived under the SSH, the LCA, negligible secondary decomposition and negligible primary radical termination (9,19,20) ... 

A thermal decomposition reaction is a reaction that is activated by heat or high temperatures and that generates simpler (i.e., containing fewer atoms and thus characterized by lower molecular weights) substances from a single complex substance. The overall balanced equation for the thermal decomposition of sodium bicarbonate reveals the simpler substances produced ... 

B) In examining the balanced equation, note that for each mole of N205 gas that decomposes, Vi mole of 02 gas is formed. Therefore, the rate of formation of oxygen gas should be half the rate of decomposition of the N205. 

This chapter has shown that the analysis of the topological structure of the balance equations allows classification of the measured and unmeasured process variables, finally leading to system decomposition. 

To do this, the product of the mass flowrate and the specific enthalpy was substituted by the corresponding enthalpy flow. Results of the reconciliation procedure using the Q-R factorization are given in Table 7. Table 8 compares the residuum of the balance equations, the value of the objective function, and the computing time of the MATLAB implementation for both approaches (Q-R factorization and use of SQP with the reduced set of balance equations). These results show the improvement and the efficiency achieved using Q-R decomposition when the system can be represented as bilinear. 

What mass of oxygen, O2, can be obtained by the decomposition of 5.0 g of potassium chlorate, KCIO3 The balanced equation is given below. 2KCIO3 2KC1 + 3O2... 

Figure 5.4 Calculated (a) electron balance (Equation 5.5), (b) production of acetate (Equation 5.6) and (c) production of H2 (Eqnation 5.7) as fnnctions of the ratio of CH4 to CO2 prodnced ( ) during anaerobic decomposition of soil organic matter. Numbers on curves are ratios of CH4 produced from H2 + CO2 to CH4 produced from acetate (V )...

Nitromannitol is a strong explosive with a positive oxygen balance. Its decomposition proceeds according to the equation ... 

Next, find how many moles of N2 are produced in the decomposition reaction. According to the balanced equation, 2 mol of NaN3 yields 3 mol of N2, so 2.23 mol of NaN3 yields 3.35 mol of N2 ... 

When quoting a reaction rate, it s important to specify the reactant or product on which the rate is based because the rates of product formation and reactant consumption may differ, depending on the coefficients in the balanced equation. For the decomposition of N205,4 mol of N02 form and 2 mol of N205 disappear for each mole of 02 that forms. Therefore, the rate of formation of 02 is one-fourth the rate of formation of N02 and one-half the rate of decomposition of N205 ... 

Matter is conserved in chemical reactions The total mass of the products equals the total mass of the reactants. Chemical equations reflect this conservation. It is why chemical equations must be balanced. Atoms have mass, and the numbers of each kind of atom on each side of the equation must be the same. Coefficients, the numbers to the left of the formulas, are used to balance equations. Many equations can be balanced directly by simply adjusting the coefficients, as illustrated in the equations given above. Other equations are more difficult to balance, such as that for the decomposition of nitroglycerine (an explosive)... 

While it is not possible to determine the rate law of a reaction by inspecting its balanced equation, it is possible to deduce the rate law if you know the elementary steps for the reaction or, in other words, the reaction mechanism. Knowing the molecularity of the elementary step will help you determine the rate law for that step. For example, consider the elementary step that involves the decomposition of substance A into one or more product ... 

What are the products of the following decomposition reactions Predict the products. Then write a balanced equation for each reaction. 

PROBLEMS Classify the five balanced equations above as single replacement, double replacement, synthesis, or decomposition. 

We have already balanced a number of simple oxidation-reduction equations, starting in Chapter 8. Most combination and decomposition reactions and all single substitution and combustion reactions are oxidation-reduction reactions. However, many oxidation-reduction reactions are much more complicated than the ones we have already considered, and we must use a systematic method for balancing equations for them. Unfortunately, many different systematic methods are used, and each chemistry instructor seems to have his or her own favorite method. Most instructors will accept any valid method that a student understands, however. The method outlined here is a standard method that should be acceptable. 

Next, we calculate the moles of KCIO3 needed to produce this quantity of O , using the mole ratio from the balanced equation for the decomposition of KClO ... 

Salmi (25) set up equations needed to simulate the transient response of both the PFR and the CSTR. The balance equations and the generahzed equations for the rates of the elementary steps are compactly expressed in vector and matrix notation. Details of the computational algorithms are discussed, and they are applied to the N2O decomposition (Eqs. 5 and 6). In another paper (26) these equations are used to simulate (for both PFRs and CSTRs) the responses of sysfems following many mechanisms Eley-Rideal, Langmuir-Hinshelwood. a combination of the two. with and without dissociative adsorption, etc. These curves can be added to those of Kobayashi (22), to expand the general view of how various systems respond. 

For such a second-order reaction, a plot of Ijc against t is linear (Fig. 18.7). The factor 2 multiplying kt in this expression arises from the stoichiometric coefficient 2 for NO2 in the balanced equation for the specific example reaction. For other second-order reactions with different stoichiometric coefficients for the reactant (see the thermal decomposition of ethane described on page 755), we must modify the integrated rate law accordingly. 

Again, you have to come up with the balanced chemical reaction. Based on what you should know about decomposition reactions (see Lesson 6-2) and balancing equations (see Lesson 6-1), this shouldn t be too much trouble. Complete Step 1, starting with a balanced equation, and Step 2, labeling the equation. 

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