Throughput scaling factor

Depart from geometric similarity so that V and A xt both increase in direct proportion to the throughput scaling factor S. Scaling a tubular reactor by adding length is a possibility for an incompressible fluid. 

The throughput scaling factor, Sr, is the ratio of production rates for the large and small reactors [Eq. (3)]. 

At first glance, these results seem fantastic. Look at the case where S = 100. When the pressure drop across the pilot reactor is large, a mere 47% increase in length gives a 100-fold increase in inventory The pressure and the density increase by a factor of about 69. Multiply the pressure increase by the length increase and the factor of 100 in inventory has been found. The reactor volume increases by a factor of only 1.47. The inventory and the throughput scale as S. The scaling factor for volume is much lower, 1.47 instead of 100 in this example. 

Solution Table 5.1 provides the scaling relationships, throughput and volume scaling factor is A = 128. 

Chapter 1 introduced throughput and inventory scaling factors, 5 thr(... 

Table 3.1 gives the general scaling factor for pressure drop as 5 throughput Inserting 5throughput = 5 and 5fl = 5l = 5 / gives... 

SOLUTION Since the fluid is incompressible, throughput = S, and Table 3.3 gives the driving force scaling factor as. This is set to 1. Setting S Sl = S imposes a con-... 

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