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Steady-State CSTR with Higher-Order, Reversible Kinetics

2 Steady-State CSTR with Higher-Order, Reversible Kinetics [Pg.387]

Chapter 9 Continuous Stirred Tank and the Plug Flow Reactors [Pg.388]

0 = Cafqf — Caq — kabCaCbV + kdCd V 0 = Cbfqf - Cbq - kabCaCbV + kdCd V 0 = -Cdq + kabCaCbV - kdCd V [Pg.388]

The result is that we get two sets of symbolic solutions forthe concentrations. The first set [Pg.389]

This last equation shows why the CSTR at steady state is such a valuable tool to the experimentalist seeking kinetic parameters. The rate of reaction, independent of the form of the kinetics, is simply the change in concentration of A between the feed and exit streams divided by the holding time. We will see this repeatedly. [Pg.387]

There is something to learn from rearranging the second equation also  [Pg.387]

Given the rate of a chemical reaction, and the target production rate Cd q we can compute the volume necessary for a well-mixed reactor to achieve this output. Thus in a very real sense this becomes a useful design equation to be employed in the earliest stages of a study of economic feasibility. [Pg.387]




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