Solutions to exercises

All quantities on the right are given to us except n, which can be computed from the given mass of Ar. 

The relation between pressure and temperature at constant volume can be derived from the perfect 

According to the perfect gas law, one can compute the amount of gas from pressure, temperature, and volume. Once this is done, the mass of the gas can be computed from the amount and the molar mass using 

7(b) All gases are perfect in the limit of zero pressure. Therefore the extrapolated value of pVm/T will give the best value of R. 

The best value of M is obtained from an extrapolation of p/p versus p top = 0 the intercept is M/RT. 

4(b) According to the perfect gas law, one can compute the amount of gas from pressure, temperature, 

We assumed that the coverage is low. Otherwise we had to solve a differential equation and obtain an exponential dependence on At. 

Sitting or pendent drop. Both methods involve the determination of the shape of the drop in mechanical equilibrium. The shape is determined by the balance between gravitation and surface tensional forces. If gravitation is negligible the shape is always spherical irrespective of the surface tension. 

Water running out of a plastic box. Since the plastic is not wetted by water, the maximum radius of a water drop coming out of the box is 100 /im. To push a water drop of 100 pm radius out of a hole, a pressure of 

Drop-weight method. With a mass m = 2.2 x 10 3kg/100 volume of one drop is 

Since hexadecane wets the capillary we choose the outer diameter of the capillary and 

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The difference between Exercises and Problems is that complete solutions to Exercises are provided at the back of the book, whereas only numerical answers to Problems are provided. Complete solutions to Problems are in the Solutions Manual. Exercises usually cover most of the major ideas in each chapter in the minimum number of questions. 

The complete set of SALCs (which constitute the solution to Exercise 6.1) is as follows ... 

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